CHEMISTRY HIGH SCHOOL

Which of the following would most likely be the characteristics of a desert?O Freezing temperatures and location in higher latitudes
O High temperatures and location in high latitudes
O Moderate temperatures and location in mid to high latitudes
O Warmer temperatures and location around the equator

Answers

Answer 1

Answer:

Answer: D

Explanation:

Answer 2

Answer:

Answer: High temperatures and location in high latitudes

Explanation:

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A physical change is a change
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Which compound is insoluble in water?(1) KOH (3) Na3PO4(2) NH4Cl (4) PbSO4

Which of the following molecules has correctly labeled bond dipoles?

Answers

Answer: The molecule identified with the letter C. HFO.

Explanation:

1) In covalent bonds, the dipolesare identified with an arrow pointing from the least electronegative element toward the most electronegative element.

2) The molecule HFO is formed by one covalent bond between H and O, and other covalent bond between F and O.

3) O is more electronegative than H, so in the H-O bond the dipole is identified with the arrow from the H atom toward the O atom. That is correctly indicated in the drawing C, in this way:

-|----→

H - O

4) F is more electronegative than O, so in the O-F bond the dipole is identified with an arrow from the O atom toward the F atom. That is correctly indicated in this way:

-|---→

O - F.

Which of the following is represented in the highest percentage by volume in dry air?a. Carbon dioxide
b. Oxygen
c. Hydrogen
d. Nitrogen

Answers

Answer: The correct answer is Option d.

Explanation:

Dry air is composed of a mixture of gases like argon, oxygen, nitrogen, carbon dioxide and many other gases present in trace amount.

The percentage of these gases by volume in dry air is:

Carbon dioxide = 0.03%

Argon = 0.93%

Oxygen = 20.95%

Nitrogen = 78.09%

Hydrogen = Trace amounts

From the above percentage values, we can easily say that nitrogen has the highest percentage by volume in dry air. Hence, the correct option is d.

nitrogen is the highest percent of 93%

Given that ka for hclo is 4.0 x 10-8 at 25 °c, what is the value of kb for clo- at 25 c

Answers

The Ka of HClO is 4.0 x 10^-8 at 25 C. The dissociation of HClO is:

HClO + H2O ---> H+ + ClO - T = 25 C

Ka = 4.0 x 10^-8 = [H+][ClO-]/[HClO]

pH = -log[4.0 x 10^-8]
pH = 7.40
pOH = 14 - 7.40
= 6.60
Kb = 10^-6.6

How many grams of CaCl₂ should be dissolved in 500.0 mL of water to make a 0.20M solution of CaCl₂?

Answers

0.2M means 0.2mol CaCl2/1L solution.

This question didn't give us a density of the solution so needs an assumption that the solution has equal volume to water.

xmol/0.5L=0.2M
x = 0.1

0.1mol of CaCl2 is needed. Ca=40g/mol, Cl=35.5g/mol.
CaCl2 0.1mol = (40+35.5*2)*0.1=11.1g

How many moles in 28 grams of CO2

Answers

In the given question, in 28 grams of $\rm CO_2$ molecule 0.636 moles are present.

A mole is the amount of a substance which comprises exactly $6.022* 10^(23)$ 'elementary entities' of that substance.

To find the number of moles in 28 grams of $\rm CO_2$ , we first need to determine the molar mass of $\rm CO_2$ .

Molar mass of $\rm CO_2$ = 12.01 g/mol (carbon) + 2(16.00 g/mol) (oxygen)

= 44.01 g/mol

Now that we know the molar mass of $\rm CO_2$ , we can use the following formula to calculate the number of moles:

$\rm Number \ of\ moles = \frac {mass \ of \ sample\ (in \ grams) }{ molar\ mass}$

$\rm Number\ of\ moles = \frac {28 \ g }{44.01\ g/mol }$

= 0.636 mol

Therefore, there are 0.636 moles in 28 grams of $\rm CO_2$ .

Learn more about Mole here:

brainly.com/question/30892840

#SPJ6

That is approximately .63620 grams.

Molar mass CO2 is 44.01 g/mol. How many moles of LiOH are needed to react completely with 25.5 g of CO2?

Answers

Given:

Molar mass CO2 is 44.01 g/mol

25.5 g of CO2

Required:

Moles of LiOH

Solution:

Balanced equation is:

2LiOH +CO2 → Li2CO3 + H2O

25.5g CO2 (1 mole CO2/44.01 g/mol CO2)(2 moles LiOH/1 mol CO2) = 1.16 moles LiOH

Molarmass carbon dioxide is 44.01 g/mol, 1.16 moles of LiOH are needed to react completely with 25.5 g of CO₂.

Stoichiometry and the molar ratios of CO₂ and LiOH must be used to calculate the number of moles of LiOH required to totally react with 25.5 g of CO₂.

The reaction between CO₂ and LiOH has the following chemical formula:

CO₂ + 2LiOH -> Li₂CO₃ + H₂O

Now,

Molar mass of CO₂ = 44.01 g/mol

Mass of CO₂ = 25.5 g

Number of moles of CO₂ = Mass of CO2 / Molar mass of CO2

= 25.5 g / 44.01 g/mol

≈ 0.58 moles of CO2

As per this,

Number of moles of LiOH = 2 * Number of moles of CO2

= 2 * 0.58 moles

= 1.16 moles of LiOH