Which of the following structural features is possessed by aldehydes but not ketones? A.) at least one hydrogen atom is bonded to the carbonyl carbon atom B.) At Least one hydroxyl group is bonded to the carbonyl carbon atom C.) the carbonyl carbon atom is part of a ring structure D.) the carbonyl carbon atom is bonded to two other carbon atoms

Answers

Answer 1

Answer: A and B I don’t know why they added that

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How is geometrical symmetry related to the polarity of a molecule?

Answers

A symmetric shape means the bonds' polarities are exactly equal then it means the polarities cancel each other, resulting to a nonpolar molecule. This is because there will be no available polarity for other substance to attach.

Explanation :

As we know that the geometrical symmetry of the molecule and the polarity of the bonds both are equally important for determining the polarity of the molecule.

The molecule that has zero dipole moment that means it is a geometrical symmetric molecule and the molecule that has some dipole moment that means it is a geometrical asymmetric molecule.

As the molecule is symmetric, the dipole moment will be zero and the molecule will be non-polar.

As the molecule is asymmetric, the dipole moment will not be zero and the molecule will be polar.

Thus, we can say that the a symmetry molecule is non-polar in nature and an asymmetry molecule is a polar molecule.

Which of the following would you expect to form an ionic bond when combined?. . .A. Ca and O. .B. N and O. C. Ca and Mg. . D. N and He

Answers

Ionic bonding is defined as the total transfer of valence electrons between atoms. What happens in ionic bonding is that a metal loses electrons to become a positive charged cation. On the other hand, the nonmetal receives those electrons to become a negatively charged anion. From the given choices above, the option that you would expect to form an ionic bond when combined is option A. Ca and O.

Use Hess's law and the following equations to calculate the ΔHreaction for the reaction CO(g) + 3H2(g) CH4(g) + H2O(g). (Show your work.) (4 points) • C(s) + O2(g) CO(g) ΔH = –110.5 kJ • C(s) + 2H2(g) CH4(g) ΔH = –74.85 kJ • H2(g) + O2(g) H2O(g) ΔH = –241.83 kJ

Answers

Answer: The enthalpy of reaction is, -206.18 kJ

Explanation:-

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The final reaction is

$CO(g)+3H_2(g)\rightarrow CH_4(g)+H_2O(g)$ $\Delta H_(rxn)=?$

The intermediate balanced chemical reaction will be,

(1) $C(s)+(1)/(2)O_2(g)\rightarrow CO(g)$ $\Delta H_1=-110.5kJ$

(2) $C(s)+2H_2(g)\rightarrow CH_4(g)$ $\Delta H_2=-74.85kJ$

(3) $H_2(g)+(1)/(2)O_2(g)\rightarrow H_2O(g)$ $\Delta H_3=-241.83kJ$

Now adding (2) and (3) and subtracting (1) , we get :

$\Delta H_(rxn)=(\Delta H_2+\Delta H_3)-\Delta H_1$

$\Delta H_(rxn)=((-74.85)+(-241.83))-(-110.5)$

$\Delta H_(rxn)=-206.18kJ$

Therefore, the enthalpy of reaction is, -206.18 kJ

Final answer:

To calculate the ΔHreaction for the given reaction using Hess's Law, we need to manipulate the given equations and sum up the ΔH values. After manipulating the equations and summing up the ΔH values, the ΔHreaction is -280.03 kJ.

Explanation:

To calculate the ΔHreaction for the given reaction, we can use Hess's Law. We need to manipulate the given equations to match the overall reaction. Since the overall reaction involves CO, H2, CH4, and H2O, we can use the given equations as follows:

Reverse the equation for CO(g) + O2(g) → CO(g) to get CO(g) → C(s) + O2(g).
Double the equation for C(s) + 2H2(g) → CH4(g) to get 2C(s) + 4H2(g) → 2CH4(g).
Leave the equation for H2(g) + O2(g) → H2O(g) as is.

Add up the manipulated equations and their respective ΔH values:

CO(g) → C(s) + O2(g) (ΔH = 110.5 kJ)
2C(s) + 4H2(g) → 2CH4(g) (ΔH = -2 * 74.85 kJ = -149.7 kJ)
H2(g) + O2(g) → H2O(g) (ΔH = -241.83 kJ)

Now, sum up the ΔH values:

110.5 kJ + (-149.7 kJ) + (-241.83 kJ) = -280.03 kJ

Therefore, the ΔHreaction for the reaction CO(g) + 3H2(g) → CH4(g) + H2O(g) is -280.03 kJ.

Learn more about Hess's Law here:

brainly.com/question/33958417

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210.0 °C a gas has a volume of 8.00 L. What is the volume of this gas at -23.0°C?

Answers

V₁ = 8.00 L

T₁ = 210.0ºC + 273 = 483 K

V₂ = ?

T₂ = - 23.0ºC + 273 = 250 K

V₁/ T₁ = V₂ / T₂

8.00 / 483 = V₂ / 250

483 x V₂ = 8.00 x 250

483 V₂ = 2000

V₂ = 2000 / 483

V₂ = 4.14 L

hope this helps!

A sample contains 6.25 percent parent isotope and 93.75 percent daughter isotopes. If the half-life of the parent isotope is 58 years, how old is the sample?

Answers

The parent isotope percent will change from 100% to 50% to 25% to 12.5% and to 6.25%. So the sample go through four times of half-life. So the sample is 58*4=232 years old.

Answer is: the sample is 232 years old.

Take 100 atoms:

After first half-life: 50% · 100 ÷ 100% = 50.

After second half-life: 0.5 · 50 = 25.

After third half-life: 0.5 · 25 = 12.5.

After fourth half-life: 0.5 · 12.5 = 6.25.

6.25 ÷ 100 · 100% = 6.25%.

4 half-lives will it take before only about 6.25% of the original sample remains.

t = 4 · 58 y.

t = 232 y.

If it takes 54 mL of 0.1 M NaOH to neutralize 125 mL of an HCl solution,what is the concentration of the HCl ?

Answers

volume of NaOH = 54 mL / 1000 = 0.054 L

Molarity NaOH = 0.1 M

Number of moles NaOH :

n = M * v

n = 0.1 * 0.054

n = 0.0054 moles of NaOH

Finally we calculate the number of moles of HCl in the solution from the stoichiometry of the reaction :

HCl + NaOH = NaCl + H₂O

1 mole HCl -------- 1 mole NaOH
? moles HCl ------- 0.0054 moles NaOH

moles HCl = 0.0054 * 1 /1

= 0.0054 moles of HCl

Volume of HCl = 125 mL / 1000 = 0.125 L

M ( HCl ) = n / V

M = 0.0054 / 0.125

= 0.0432 M

hope this helps!

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