The graph of it's a vertical translation of the graph of the parent linear function a right triangle with an area of 50 square units is formed by the x-axis the y-axis and the graph.f(x)=​

Answer:

Step-by-step explanation:

I see that you want to find the equation of a linear function that forms a right triangle with the x-axis, y-axis, and has an area of 50 square units. To clarify, let's work through this step by step.

A right triangle can be formed with the x-axis and y-axis as two sides, and the third side represented by the graph of a linear function. The area of this right triangle can be found using the formula for the area of a triangle:

Area = (1/2) * base * height

In this case, one of the legs (base) of the right triangle is along the x-axis, and its length is determined by the x-coordinate at which the linear function crosses the x-axis. The other leg (height) is along the y-axis, and its length is determined by the y-coordinate at which the linear function crosses the y-axis.

Let's assume that the linear function is of the form:

f(x) = mx + b

where "m" is the slope and "b" is the y-intercept.

The x-coordinate where the linear function crosses the x-axis is given by:

x-coordinate = -b/m

The y-coordinate where the linear function crosses the y-axis is "b."

Now, let's calculate the area of the right triangle:

Area = (1/2) * (length of base) * (length of height)

Area = (1/2) * (-b/m) * b

Given that the area is 50 square units, we can set up the equation:

(1/2) * (-b/m) * b = 50

Now, you can solve this equation for "m" and "b" to find the equation of the linear function that satisfies the given conditions.