Can someone pleaseeee help its urgent

Answers

Answer 1

Answer:

Based on the given information, we can determine the characteristics of the polygon MNOP.

1. MN || OP and NO || PM:

- This means that the opposite sides MN and OP are parallel, and the opposite sides NO and PM are also parallel.

2. m/M = 93°, m/N = 87°, m/O = 93°, m/P = 87°:

- These angle measurements indicate that the opposite angles M and O are congruent, as well as the opposite angles N and P.

Based on these characteristics, we can conclude that the polygon MNOP is a parallelogram. A parallelogram is a quadrilateral with opposite sides that are parallel. In addition, opposite angles of a parallelogram are congruent.

However, we cannot determine from the given information whether the polygon MNOP is specifically a rectangle, rhombus, square, or trapezoid. These classifications require additional information, such as side lengths or angle measures, to be determined.

Therefore, the correct answers are:

- Parallelogram

- Quadrilateral

Please note that rectangle, rhombus, square, and trapezoid cannot be confirmed based on the given information.

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Y=1/2x-5Write it in a standard form
Find the Pythagorean triplet in which one number is 32
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Choose correct way to rewrite 56% as a decimal number.A. 0.056B. 0.56C. 5.6

Let X1, X2, and X3 represent the times necessary to perform three successive repair tasks at a service facility. Suppose they are normal random variables with means of 50 minutes, 60 minutes, and 40 minutes, respectively. The standard deviations are 15 minutes, 20 minutes, and 10 minutes, respectively. a Suppose X1, X2, and X3 are independent. All three repairs must be completed on a given object. What is the mean and variance of the total repair time for this object.

Answers

Answer:

The mean of the total repair time is 150 minutes.

The variance of the total repair time is 725 minutes^2.

Step-by-step explanation:

To solve this problem, we have to use the properties of the mean and the variance. Our random variable is the sum of 3 normal variables.

In the case, for the mean, we have that the mean of the sum of 3 normal variables is equal to the sum of the mean of the 3 variables:

$y=x_1+x_2+x_3 \n\nE(y)=E(x_1+x_2+x_3)=E(x_1)+E(x_2)+E(x_3)\n\nE(y)=50+60+40=150$

For the variance, we apply the property for the sum of independent variables (the correlation between the variables is 0):

$V(y)=V(x_1)+V(x_2)+V(x_3)\n\nV(y)=s_1^2+s_2^2+s_3^2\n\nV(y)=15^2+20^2+10^2\n\nV(y)=225+400+100\n\nV(y)=725$

What is the equation of this line in slope intercept from?

Answers

The correct answer should be B: y = -3x + 2.

Since the line crosses the y axis at 2, your y-intercept should be 2. Using rise over run you can compare the equations to the graph. If you convert 3x to a fraction, it would be 3/1x. Since the line is going down 3 and the rise of the y = -3x + 2 is -3, that part is correct. The line also moves over 1 unit, so the run is 1, therefore the correct slope would be -3 or -3/1. Now if you combine what you have it should be y = -3x - 2, which is the same equation as B.

A drawer contains 3 tan sweaters and two black sweaters. You randomly choose two sweaters. What is the probability that both sweaters are black?

Answers

A = event that you select a black sweater
P(A) = 2/5 since there are 2 black out of 2+3 = 5 total

After you make a selection, we have the event
B = event that you select another black sweater assuming event A has happened already

P(B) = 1/4 because there's 1 black sweater left out of 5-1 = 4 left over

Multiply the probabilities
P(A and B) = P(A)*P(B)
P(A and B) = (2/5)*(1/4)
P(A and B) = 2/20
P(A and B) = 1/10

The answer as a fraction is 1/10
In decimal form, it is 0.1
As a percent, the answer is 10%

A distance was observed four times as 248.13, 248.06, 248.18, 248.15. The observations were given a weight of 3 1, 2, and 3, respectively, but the observer. a.Calculate the weighted mean for line BC. b.Calculate the weighted mean of BC if weights are revised as 1, 1, 3, & 3 respectively.

Answers

Answer:

a. 248.14

b. 220.576

Step-by-step explanation:

The weighted mean can be calculated as

Xbarw= sumwx/sumw

where x are the observations and w are the weights of the observations.

x w wx

248.13 3 744.39

248.06 1 248.06

248.18 2 496.36

248.15 3 744.45

sumwx=744.39+248.06+496.36+744.45=2233.26

sumw=3+1+2+3=9

Xbarw= sumwx/sumw

Xbarw= 2233.26/9

Xbarw= 248.14

The weighted mean for line BC is 248.14.

x w wx

248.13 1 248.13

248.06 1 248.06

248.18 3 744.54

248.15 3 744.45

sumwx=248.13+248.06+744.54+744.45=1985.18

sumw=3+1+2+3=9

Xbarw= sumwx/sumw

Xbarw= 1985.18/9

Xbarw= 220.576

The weighted mean for line BC is 220.576.

Final answer:

The weighted mean of line BC for the first given weights is 248.13. The weighted mean for the revised weights is 248.14.

Explanation:

The weighted mean of a set of values is calculated by multiplying each value by its weight, summing those products, and then dividing the sum by the total of the weights. So we will first multiply each distance by its corresponding weight then add them all up and divide it by the sum of weights. Let's calculate.

For the first case, the weights given are 3, 1, 2, and 3. The weighted mean of BC can be computed as ((248.13*3)+(248.06*1)+(248.18*2)+(248.15*3)) / (3+1+2+3), which equals 248.13.
For the second case, the weights are revised as 1, 1, 3, and 3. The weighted mean of BC in this case is ((248.13*1)+(248.06*1)+(248.18*3)+(248.15*3)) / (1+1+3+3), which gives 248.14.

Learn more about Weighted Mean here:

brainly.com/question/35447441

#SPJ3

Round 34.037 to 3 significant figures.
a. 34.04
b. 34
c. 34.037
d. 34.0

Answers

Answer:

My answer to the question is 34.0

Is 4:3 and 3:4 equivalent

Answers

Answer: No

Step-by-step explanation:

sorry but nope...........

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