PHYSICS HIGH SCHOOL

Assuming that all carts are moving, compare and contrast the differences in the motion of the 3 carts.

Answers

Answer 1
Answer: To compare and contrast the differences in the motion of three carts, it's essential to consider various aspects of their motion, including speed, direction, and acceleration. Without specific details about the motion of each cart, I can provide a general framework:

Comparison:
1. Speed: You can compare the speeds of the carts to determine which one is moving the fastest and which one is the slowest.
2. Direction: Compare the directions in which the carts are moving. Are they all moving in the same direction, or are some moving in opposite directions?
3. Acceleration: Consider if any of the carts are accelerating (changing their speed) and in which direction.

Contrast:
1. Speed: Highlight the differences in speed between the carts. For example, Cart A may be moving slowly, while Cart B is moving quickly.
2. Direction: Discuss any differences in direction. Are some carts moving forward while others are moving backward or in different angles?
3. Acceleration: Note if any of the carts are accelerating differently. For instance, Cart C might be accelerating rapidly while Cart A maintains a constant speed.

To provide a more detailed comparison and contrast, it would be helpful to have specific information about the motion of each cart, such as their speeds, directions, and accelerations.

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A pickup truck and a hatchback car start at the same position. If the truck is moving at a constant 33.2m/s and the hatchback car starts from rest and accelerates at 5m/s/s, how far away do the cars meet up again?
A student kicks a football vertically upwards, causing the football to reach a maximum height of 40.0m before falling back to the ground. Determine all unknowns and answer the following questions. Neglect drag and the initial height and horizontal motion of the football.A) With what speed was the football kicked?B) What was the football's total flight time?

How did Marie Curie’s research in radioactivity benefit others while harming her

Answers

 The discoveries Mme Curie made were of great benefit to physics, chemistry and medicine. During the time she was doing her research, the health effects of ionizing radiation were not known. The amount of radiation that she was exposed to led to her death. Even today her notebooks and other personal effects are highly contaminated with radioactive material. 

WILL GIVE BRAINLIEST!!!! Nonpolarized light of intensity Io is incident on a polarizing filter, and the emerging light strikes a second polarizing filter. What is the light intensity emerging from the second polarizing filter?

Answers

Answer:

50% of unpolarised light passes through the first filter because, on average, 50% of the waves are aligned with the fiter's axis.  Intensity is reduced by a factor 0.5.

The second filter then reduces the intensity by a factor cos²(θ)

Explanation:

A scientific model is based on assumptions that limit where and how the model can be applied. True False​

Answers

Answer:

i think it is true

Explanation:

An 81 kg stuntman jumps from the top of a building 29 m above a catching net. Assuming that air resistance exerts a 100 N force on the stuntman as he falls, determine his velocity just before he hits the net

Answers

In order to solve this, we can get all tangled up in acceleration,
or we can just add up the energy budget.

-- Gravitational potential energy = (mass) (grav accel) (height above something)

-- 29 m above the net, his potential energy is (81 x 9.8 x 29) = 23,020 joules

-- All the way down, air resistance exerts 100 N of force against him.
The energy burned up by air resistance is the work done = 100 x 29 = 2,900 joules.

-- The energy he has left when he hits the net is (23,020 - 2,900) = 20,120 joules.

-- When he hits the net, all of his energy is kinetic energy . . . (1/2) (m) (v²)

(1/2) (m) (v²) = 20,120

(40.5) (v²) = 20,120

v² = 20,120 / 40.5

v = square root of (20,120 / 40.5) = 22.3 meters per second (about 50 mph)

As you hold book at rest in your hand two forces are being exerted on the book identify the force

Answers

gravity dwn, your hand up and equal to grav

Final answer:

When you hold a book at rest, two forces act upon it: the downward gravitational force exerted by the Earth represented as -14ĵ N and the upward force exerted by your hand that equals 14 N, balancing out the weight of the book. These forces cancel each other out, keeping the book at rest as per Newton's Second Law.

Explanation:

When you hold a book at rest in your hand, two primary forces are acting upon it. These are the gravitational force, which is the book's weight pulling it downwards, and the force exerted by your hand, pushing upwards against the book. The downward gravitational force is caused by the earth's mass attracting the book's mass. This force is represented as -14ĵ N in physics. The force exerted by your hand counters this gravitational pull, allowing the book to remain at rest in your hand.

By Newton's second law, since the book is at rest, the net force acting on the book is zero. Meaning, the gravitational force and the force exerted by your hand cancel each other out. This is represented as: FPH + FEH = 0, where FPH is the force exerted by your hand and FEH is the force exerted by the Earth. With proper calculation, the force exerted by your hand on the book equals 14 N in the upward direction, counteracting the book's weight.

Learn more about Forces on a Resting Book here:

brainly.com/question/19672318

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A graduated cylinder should be read at the top of the meniscus. True

False

Answers

Answer:

Explained

Explanation:

A graduated cylinder should be read at the top of the meniscus or the down of the meniscus purely depends upon the kind of liquid used. Water gives a concave meniscus whereas mercury gives a convex meniscus. The measurement should account for the meniscus. Measurement should be taken such that line we are reading must be even with center of the meniscus. From the above explanation we can

If it's Mercury in the graduated cylinder, then the statement is true.

If it's water in the graduated cylinder, then the statement is false.
-- If it's Mercury in the graduated cylinder, then the statement is true.

-- If it's water in the graduated cylinder, then the statement is false.
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