Carbon-14 has a half-life of 5715 years. If a 2.00g sample of Carbon-14 has decayed for 17145 years, how much of the sample remains?

Answers

Answer 1

Answer: The sample should have .25 g left. I did it and got the answer
N=0.25g

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A 115.0-g sample of oxygen was produced by heating 400.0 g of potassium chlorate. 2KClO3 mc019-1.jpg 2KCI + 3O2 What is the percent yield of oxygen in this chemical reaction?

Answers

The balanced equation that describes the reaction of heatinf potassium chlorate to produce potassium chloride and oxygen is expressed 2KClO3 = 2KCI + 3O2. For a 400 g potassium chloride, using stoichiometry, the mass oxygen produced is 156.67 grams oxygen. The actual product weighed 115.0 grams. Yield is equal to 115/156.67 or 73.74%

Answer:

The percent yield of oxygen in this chemical reaction is 73.71 %.

Explanation:

Experimental yield of oxygen gas = 115.0 g

Theoretical yield:

$2KClO_3rightarrow 2KCI + 3O_2$

Mass of potassium chlorate = 400.0 g

Moles of potassium chlorate = $(400 g)/(122.5 g/mol)=3.2653 mol$

According to reaction, 2 moles of potassium chlorate gives 3 moles of oxygen gas.

Then 3.2653 mol of potassium chlorate will give:

$(3)/(2)* 3.2653 mol=4.89795 mol$

Mass of oxygen gas :

$32 g/mol* 4.89795 mol=156.73 g$

Percentage yield:

$\%=\frac{\text{Experimental yield}}{\text{Theoretical yield}}* 100$

$\%=(115.0 g)/(156.73 g)* 100=73.71\%$

The percent yield of oxygen in this chemical reaction is 73.71 %.

What must be true for a substance to be able to dissolve in water?The solute particles must have a strong attraction for the water particles.
The solute must be able to react with water at the given temperature.
There must be enough energy to break the chemical bonds in the water molecules.
The temperature must be high enough to cause the solute to melt.

Answers

In order for a solute to dissolve in a solvent, the attractive forces between solute particles and the solvent particles must be stronger than the attractive forces between solute-solute and solvent-solvent particles. This is important so that the solute will remain in solution.

A metal, M, forms an oxide compound with the general formula M2O. In which group on the Periodic Table could metal M be found?(1) Group 1 (3) Group 16
(2) Group 2 (4) Group 17

Answers

The oxidation state of an element is calculated by subtracting and the total sum of oxidation states of all the individual atom (excluding the one that has to be calculated) from total charge on the molecule. Option (1) is correct option.

What is oxidation state?

Oxidation state of an element is a number that is assigned to an element in a molecule that represents the number of electron gained or lost during the formation of that molecule or compound. Oxidation state is a unitless quantity.

Oxidation state of M in M₂O is:

Let oxidation state of M be X

Oxidation state of Oxygen is -2

Overall charge on the molecule is 0

so 2X+(-2)=0

X=+1

So from here we can see that oxidation state of M is +1 which is possessed only by group 1 element

Hence option (1) is correct option.

To learn more about Oxidation state, here:

brainly.com/question/11313964

#SPJ2

Because the compound has a formula of M2O, the number of valence electrons of M should be 1.

Therefore, (1) Group 1 is the correct answer because elements in group 1 have 1 valence electron.

Hope this helps~

A material you are testing conducts electricity but cannot be pulled into wires. It is most likely a _____. metal nonmetal metalloid

Answers

The correct answer for the question that is being presented above is this one: "metal." A material you are testing conducts electricity but cannot be pulled into wires. It is most likely a metal. This metal is a good testing for conductivity of an electricity but cannot be pulled into wires.

Answer:

The correct answer is metal.

Explanation:

9Ammonia is manufactured from nitrogen and hydrogen by the Haber process.
N2(g) + 3H2(g)2NH3(g)
What is the percentage yield when 60 kg of ammonia is produced from 60 kg of hydrogen?
A
5.9%
B
17.6%
с
35.3%
D
50.0%

Answers

Answer:

17.6%

Explanation:

1. Percentage yield = (Actual yield/theoretical yield) x 100

2. You know actual yield of ammonia (60kg) so you need to work out theoretical yield.

3. mols of hydrogen = m/mr = 60,000/2 = 30,000 mols.

4. 3:2 ratio so (30,000/3) x 2 = 20,000 mols of Ammonia.

5. Therefore mass of ammonia = mr x mols = 20,000 x 17 = 340,000 grams

6. So percentage yield is (60,000/340,000) x 100 = 17.6

What form of energy provides power for a gas stove?A.nuclear energy
B.electrical energy
C.chemical energy
D.sound energy

Can you explain the answer for me ?

Answers

C . chemical energy will be the answer. In a gas stove, LPG is stored and it is brought out and it reacts with oxygen to give out heat energy. all the other options are not convincing and hence chemical energy is the best answer.

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