Many chemical and toxic substances used in modern industry are flammable or combustible. true/false

Answers

Answer 1
Answer:

Answer:

True

Explanation:

Many chemical and toxic substances used in modern industry are indeed flammable or combustible. These substances can pose significant safety hazards, especially in industrial settings, and require proper handling, storage, and safety measures to prevent fires and explosions. It is crucial to follow strict safety protocols and regulations when working with such materials to ensure the safety of workers and the environment.


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1, This element has a complete outermost energy level and is found in the 5th period. 2. This element has 2 electrons it its outermost energy level and belongs to the 2nd period.
3. This element has 3 electrons in its Lewis dot structure and is in the 3p orbital section.
4. This element has 74 protons.
5.This element in the 4th period wants to gain one electron to make an ionic bond.
6. This element is the halogen in the 5th period.
7. This metalloid has 3 electrons in its 5p orbitals.
8. This element in the 5th period wants to lose two electrons to make an ionic bond.
9. This malleable metal has an atomic number of 47.
10.This element in the 2nd period will form an ionic compound with a 1:1 atom ratio with Magnesium.
11.This element has an electron configuration of 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p4.
12. This element was named for the scientist who discovered the nucleus of the atom using gold foil.
13. This noble gas belongs to the 6th period.
14. This element has 1 electron in its 4d orbital section.
15. This 3rd period element will not form compounds because it fits the Octet Rule.

Answers

1) Xenon
2) Berylium
3) Aluminium (Assuming 3p = 3rd Period)
4) Tungsten
5) Bromine
6) Xenon again
7) Indium I think
8) Strontium
9) Titanium
10) Oxygen
11) I don't understand that at all XD
12) Rutherfordium
13) Radon
14) Potassium?
15) Argon

So somebody needs to confirm 3, 7, 11, and 14, but I think the rest are correct if you load up a Periodic table

In the double replacement reaction between Na2SO4 (aq) and BaCl2 (aq), will a precipitate form?No. This reaction produces no insoluble products.

Yes. The NaCl will precipitate.

Yes. The BaSO4 will precipitate.

Yes. Both the NaCl and the BaSO4 will precipitate.

Answers

Yes. The BaSO₄ will precipitate in this type of double replacement reaction.

What is Double replacement reaction?

This is a type of reaction in which two reactants exchange ions to form two new compounds.

Na₂SO₄ (aq) + BaCl₂ (aq) ⇒ NaCl(aq)+ BaSO₄(s)

The precipitate which will be seen at the bottom of the reaction flask is solid BaSO₄.

Read more about Double replacement reaction here brainly.com/question/5082638

Answer: The correct answer is Yes, BaSO_4 will precipitate.

Explanation:

Double displacement reaction is defined as the reaction in which exchange of ions takes place.

AB+CD\rightarrow AD+CB

Precipitate is defined as the insoluble salt which emerges when two different solutions are mixed together. It settles down at the bottom of the flask after some time.

The chemical equation for the reaction of sodium sulfate and barium chloride follows:

Na_2SO_4(aq.)+BaCl_2(aq.)\rightarrow NaCl(aq.)+BaSO_4(s)

Barium sulfate settles down in the reaction flask and is considered as a precipitate.

Hence, the correct answer is Yes, BaSO_4 will precipitate.

Is a force created by the water that is displaced by an object.

Answers

Answer:

Buoyancy.

Explanation:

Buoyancy is a force created by the water that is displaced by an object. It is directly proportional to the amount of water that is being displaced by an object.

Hence, the greater the amount of water an object displaces; the greater is the force of buoyancy pushing the object up.

The buoyancy of an object is given by the formula;

Fb = pgV\n\nBut, V = Ah\n\nHence, Fb = pgAh

Where;

Fb = buoyant force of a liquid acting on an object.

g = acceleration due to gravity.

p = density of the liquid.

v = volume of the liquid displaced.

h = height of liquid (water) displaced by an object.

A = surface area of the floating object.

The unit of measurement for the buoyancy of an object is Newton (N).

Which rigid cylinder contains the same number of gas molecules at STP as a 2.0-liter rigid cylinder containing H2(g) at STP?(1) 1.0-L cylinder of O2(g)
(2) 2.0-L cylinder of CH4(g)
(3) 1.5-L cylinder of NH3(g)
(4) 4.0-L cylinder of He(g)

Answers

When we say STP that means the system is at its standard temperature and pressure. Both systems is having the same condition hence temperature and pressure is constant. We then set the amount of gas in both cases to be equal. Hence from the ideal gas law, 
PV=nRT we can say that with everything constant, volume must also be constant. 

The answer is (2) 2 L of methane gas. 

2.0-L cylinder of CH₄ (g) contains the same number of gas molecules at STP as a 2.0-liter rigid cylinder containing H₂(g) at STP.

What is ideal gas equation?

It is a hypothetical approximation of the behavior of many gases under many condition, and expressed as PV = nRT.

As in the question it is given that rigid cylinder have the same temperature and pressure i.e. have a standard temperature and pressure. According to the Avogadro's Law, under the same temperature and pressure if equal amount of gas is taken then no. of moles of gases are same.

Ideal gas equation PV = nRT justifies the above statement.

So, from the given 2.0-L cylinder of CH₄ (g) contains the same number of gas molecules at STP.

Hence, option (2) is correct i.e. 2.0-L cylinder of CH₄ (g) contains the same number of gas molecules.

To learn more about ideal gas, visit below link:

brainly.com/question/25290815

A liquid mixture in which particles can be seen and easily separated by settling or filtration is aa. solution.
b. suspension.
c. solvent.
d. solute.

Answers

The answer for this statement is letter B. suspension. The liquid mixture in which particles can be seen and easily separated by settling or filtration is a  suspension. 

Answer:

suspension

Explanation:

A solution is prepared by adding .8 g of iron sulfate to 450mL of watercalculate the effective molality of the solution'

Answers

Molar mass FeSO₄ =151.908 g/mol

Volume = 450 mL / 1000 = 0.45 L

1 mol ----------- 151.908 g
n mol ----------- 0.8 g

n = 0.8 * 1 / 151.908

n = 0.00526 moles 

M = n / V

M = 0.00526 / 0.45

M = 0.01168 mol/L⁻¹

hope this helps!