A mixed dentition usually consists of

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Answer 1

Answer: During childhood a mixed dentition refers to the period when a person has both baby) teeth and permanent (adult) teeth in their mouth. This stage occurs as children start losing their baby teeth and new permanent teeth gradually take their place. It's a part of development that lasts for several years until all the primary teeth are replaced by permanent ones.

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Two objects with different masses collide and bounce back after an elastic collision. Before the collision, thetwo objects were moving at velocities equal in magnitude but opposite in direction. After the collision,
A. the less massive object had gained momentum.
B. the more massive object had gained momentum.
C. both objects had the same momentum.
D. both objects lost momentum.

Answers

The more massive object will lose momentum after collision while the less massive object will gain momentum after collision.

Let the mass of the first object = m₁
Let the mass of the second object = m₂
let the initial velocities of the two objects = u
let the final velocity of the first object after collision = v₁
Let the final velocity of the second object after collision = v₂

Apply theprinciple of conservation of linear momentum for elastic collision;

let the heavier object = m₁

m₁u + m₂(-u) = m₁(-v₁) + m₂v₂

m₁u - m₂u = -m₁v₁ + m₂v₂

where;

m₁u and m₂u are initial momentum of both objects before collision

m₁v₁ and m₂v₂ are final momentum of both objects after collision

Thus, from the equation above we can conclude the following, the more massive object will lose momentum after collision while the less massive object will gain momentum after collision.

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Answer:A

Explanation:

Given

mass of two objects are $m_1$ and $m_2$

taking $m_1>m_2$

Suppose $u_1$ and $u_2$ are the velocities of $m_1$ and

$u_1=u$ and $u_2=-u$

therefore after elastic collision velocity of $m_1$ and $m_2/[tex] are [tex]v_1$ and $v_2$

$v_1=(m_1-m_2)/(m_1+m_2)\cdot u_1+(2m_2)/(m_1+m_2)\cdot u_2$

$v_2=(2m_1)/(m_1+m_2)\cdot u_1-(m_1-m_2)/(m_1+m_2)\cdot u_2$

for $u_1$ and $u_2$

$v_1=(m-m)/(m+m)\cdot u+(2m)/(m+m)\cdot (-u)$

$v_1=(m_1+m_2)/(m_1+m_2)\cdot u=u$

$v_2=(2m)/(m+m)\cdot u-(m-m)/(m+m)\cdot (-u)$

$v_2=(3m_1-m_2)/(m_1+m_2)\cdot u$

$v_2=u+2\cdot (m_1-m_2)/(m_1+m_2)\cdot u$

so velocity of mass $m_2$ is more as compared to $m_1$

so less massive object gained some momentum

a ball is dropped from rest at a height of 80 m above the ground. what is the speed just as it hits the ground?

Answers

Δx=Vi(t)+.5at²
Δx=80
a=9.8
Vi=0 since its from rest, the initial velocity is 0.
80=0+.5(9.8)t²
t=16.33
You can use one of the big five equations: Vf=Vi+at
Vf=0+9.8(16.33)
Vf=160.034 m/s

two truckers are traveling directly away from each other at the same speed. If one trucker sounds her horn at a frequency of 206 Hz, and the other trucker hears a frequency of 189 Hz, determine the speed of the trucks. Use the speed of sound as 343 m/s. m/s

Answers

Answer:

v' = 14.76 m/s

Explanation:

given,

frequency of the one truck = 206 Hz

apparent frequency ,f' = 189 Hz

speed of sound, v = 343 m/s

speed of observer (v_o)and source (v_s) = v'

now, using Doppler's effect

$f' = (v-v_o)/(v+v_s)\ f$

$f' = (v- v')/(v+v')\ f$

$189 = (343- v')/(343+v')\ 206$

$0.9174= (343- v')/(343+v')$

314.69 + 0.9174 v' = 343 - v'

1.9174 v' = 28.30

v' = 14.76 m/s

hence, the speed of the truck is equal to 14.76 m/s

A stone is thrown horizontally at 8.0 m/s from a cliff 78.4 m high. How far from the base of the cliff does the stone strike the ground?

Answers

A stone is thrown horizontally at 8.0 m/s from a cliff 78.4 m high. The distance from the base of the cliff does the stone strike the ground is 64 m.

What is distance?

Distance is defined as the entire path traveled by an object in motion, regardless of journey direction. Three sight distances are primarily taken into account in the geometric design of road construction. Things that can be measured in terms of length include the dimensions of a section or a room. Distance is the separation between two things, like two cities or two points. There will never be a negative value for either length or distance.

A projectile is an object that is launched vertically into the air and moves while being pulled by gravity. A horizontally launched object that defies gravity is referred to as a projectile.

Thus, a stone is thrown horizontally at 8.0 m/s from a cliff 78.4 m high. The distance from the base of the cliff does the stone strike the ground is 64 m.

To learn more about distance, refer to the link below:

brainly.com/question/15172156

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64 meters

Magma appears to be rising underneath the mid-oceanic ridges.
a. True
b. False