The function C (1)31+ 2 is the cost to order a lip gloss L,including the flat rate shipping charge. Which of the for
represents the cost of purchasing 5 lip glosses? (1 point)

C (5)=5
1=5
C (5)
C (1) = 5

Answers

Answer 1
Answer:

Answer:

Therefore, the cost of purchasing 5 lip glosses, as represented by the function C(5), is 41.

Step-by-step explanation:

To find the cost of purchasing 5 lip glosses, we need to use the given function C(1) = 31 + 2, which represents the cost of ordering one lip gloss including the flat rate shipping charge. To find the cost of purchasing 5 lip glosses, we can substitute 5 for the variable in the function: C(5) = 31 + 2 * 5 C(5) = 31 + 10 C(5) = 41

Answer 2
Answer:

Final answer:

The cost of purchasing 5 lip glosses represented in the function C(1)=31+2 is evaluated as C(5)=31+2*5, which equals 41 units.

Explanation:

This question involves the mathematical concept of functions, specifically, simple linear functions. In this example, we have the function C(1)=31+2, which informs us that the cost to order one lip gloss, denoted as 'L', is '31 plus twice the number of lip glosses ordered'

To answer the question 'What represents the cost of purchasing 5 lip glosses?', we substitute the number of lip glosses we want to buy (5) into our function. So instead of evaluating C(1), we evaluate C(5)=31+2*5, following the same structure of '31 plus twice the number of lip glosses ordered'. The solution to this would be C(5)=41, meaning it would cost 41 units (the currency isn't stated) for 5 lip glosses.

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Find common denominators for three sevens and one and half

Answers

3/7 and 1 1/2

Now look at the two denominators: 7 and 2.

Because 7 and 2 are relatively prime, their least common multiple is:
7*2= 14

Therefore, 14 is a common denominator for 3/7 and 1 1/2.

Hope this helps~
3/7 and 1/2    14 is the common denominator    at the end it is   6/14  and 7/14

7. (1 point) A fighter plane, which can shoot a laser beam straight ahead, travels along the path ~r(t) = 5 − t, 21 − t 2 , 3 − t 3 27 Show that there is precisely one time t at which the pilot can hit a target located at the origin.

Answers

Answer:

At t = 3, pilot can hit the target located at the origin.

Step-by-step explanation:

We have been given displacement vector:

r(t) = 5 - t, 21 - t², 3-t³/27

so, in this case r(t) and r'(t) should be in the parallel but opposite direction.

In order to get r'(t) we need to differentiate r(t).

r(t) = 5 - t, 21 - t², 3-t³/27

r'(t) = -1, -2t, -t²/9

Now perform the cross product among these two r(t) and r'(t).

r'(t) x r(t) = \left[\begin{array}{ccc}i&j&k\n-1&-2t&(-t^(2) )/(9)  \n5-t&21-t^(2) &3-(t^(3) )/(27) \end{array}\right]

            = i ((-6t + (2t^(4) )/(27) )+ ( (21t^(2) )/(9) - (t^(2) )/(9) )) -j ((-3 + (t^(3) )/(27) + (5t^(2) )/(9) - (t^(2) )/(9) )) + k ((-21 + t^(2)  + 10t -2t^(2)))

           = ((-t^(4) )/(27) + (7t^(2) )/(3) - 6t )i + ((2t^(3) )/(27) - (5t^(2) )/(9) +3) j + (-t² + 10t -21)k

In order to find the value of t, we need to put

(-t^(4) )/(27) + (7t^(2) )/(3) - 6t = 0

-t² + 10t -21 = 0

So, after solving for t, we will get

- ( t-3) (t-7) = 0

t = 3 or t = 7

In this case, only t = 3 satisfies the other two equations as well. t=7 is not satisfying. So take t =3 as the time. and for further assurance, we need to check are our vectors r(t) and r'(t) opposite at t = 3 or not. Let's check it out.

r(3) = 5-3, 21 - 3²,  3 - 3³/27

r (3) = 2, 12, 2

r'(3) = -1, -2(3) , -3²/9

r'(3) = -1, -6 -1

Here, we can easily see that, r(3) = -2 r'(3) which is opposite and hence it is proved that, at exactly t = 3, pilot can hit a target located at the origin.

Witch is greater 100in or 3yd 1ft

Answers

First you need to convert then to the same units. So 3yd 1ft would be equal to 10 ft. Then you need to convert the feet to inches. 10ft x 12 is equal to 120 inches.

120 inches is greater that 100 inches.

Suppose C and D represent two different school populations where C > D and C and D must be greater than 0. Which of the following expressions is the largest? Explain why. Show all work necessary.. . . (C + D)2. 2(C + D). C2 + D2. C2 − D2

Answers

Answer:

the largest is:   C^2+D^2

Step-by-step explanation:

We are given the expression C>D>0.

As C and D represent two different school populations. This means that C and D will be natural numbers.

C+D<2×(C+D)

Also C^2+D^2>C^2-D^2.

the largest among these expressions is  C^2+D^2


The question or the problem wants to choose among the following expression is the largest, base on the data presented in the problem, the possible answer among the following choices is C2+D2. I hope you are satisfied with my answer and feel free to ask for more 

if n is a positive integer, for what values of n is the function f(x) =x to the power of n

a) even

b) odd

Answers

f(x)=x^n;\ n\in\mathbb{Z^+}\n\n function\ is\ even\ when\ f(-x)=f(x)\n\nfunction\ is\ odd\ when\ f(-x)=-f(x)\n\na)\ f(x)\ is\ even\ when\ n\ is\ even:f(-x)=(-x)^n=x^n=f(x)\n\nb)\ f(x)\ is\ odd\ when\ n\ is\ odd:f(-x)=(-x)^n=-x^n=-f(x)
a) n is even
b) n is odd

Given the perimeter of a rectangle and either the length or​ width, find the unknown measurement using the appropriate formula.The perimeter is 70ft . and the width is 16ft .

Answers

Answer:

Step-by-step explanation:

Givens

P = 2*L + 2*W

P = 70

w = 16

Solution

70 = 2L + 2*16

70 = 2L + 32

70-32 = 2L

38 = 2L

38/2 = 2L/2

L = 19