Find the mass of AlCl3 that is produced when 10 g of Al2O3 reacts with 10 g of HCl according to the following equation Al2O3(s) + 6HCl(aq) --> 2AlCl3(aq) + 3H2O(aq) Please select the correct option: A. 16.2 g B. 20.0 g C. 10.0 g D. 6.10 g E. 12.2 g

Answers

Answer 1
Answer:

Answer:

Considering the reaction stoichiometry and the definition of limiting reagent, the mass of AlCl₃ that is produced when 10.0 grams of Al₂O₃ react with 10.0 grams of HCl is 12.19 grams.

Explanation:

Al₂O₃ + 6 HCl → 2 AlCl₃ + 3 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:  

Al₂O₃: 1 mole

HCl: 6 moles

AlCl₃: 2 moles

H₂O: 3 moles

The molar mass of the compounds present in the reaction is:

Al₂O₃: 102 g/mole

HCl: 36.45 g/mole

AlCl₃: 133.35 g/mole

H₂O: 18 g/mole

Then, by reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of mass of each compound participate in the reaction:  

Al₂O₃: 1 mole× 102 g/mole= 102 grams

HCl: 6 moles× 36.45 g/mole= 218.7 grams

AlCl₃: 2 moles× 133.35 g/mole= 266.7 grams

H₂O: 3 moles× 18 g/mole= 54 grams

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 102 grams of Al₂O₃ reacts with 218.7 grams of HCl, 10 grams of Al₂O₃ reacts with how much moles of HCl?

mass of HCl= 21.44 grams

But 21.44 grams of HCl are not available, 10 grams are available. Since you have less moles than you need to react with 10 grams of Al₂O₃ , HCl will be the limiting reagent.

Then, it is possible to determine the mass of AlCl₃ produced by another rule of three: if by stoichiometry 218.7 grams of HCl produce 266.7 grams of AlCl₃, if 10 grams of HCl react how much mass of AlCl₃ will be formed?

mass of AlCl₃= 12.19 grams

In summary, the mass of AlCl₃ that is produced when 10.0 grams of Al₂O₃ react with 10.0 grams of HCl is 12.19 grams.


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1. Identify evidence that a chemical reaction has occurred.
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Answers

Answer:

1. The evidence that chemical reaction has occurred can be found in the change of the reagents present after the reaction, that is formation of glucose in the area where the reaction is taking place

2. The most abundant element of the chemical reaction is oxygen which has a total quantity of 18 atoms in the reaction

3. The oxygen atom has an atomic number of 8 and therefore contains 8 protons and 8 neutrons and (therefore) 8 electrons (to be neutral, electronically)

4. The protons and the neutrons of the atom, oxygen, are located in the nucleus, while the electron are found in the different orbitals surrounding the atom

5. The element, oxygen, symbol, O, belongs to the group 16 of period 2 in the periodic table

Explanation:

In a laboratory investigation, magnesium reacts with hydrochloric acid to produce hydrogen gas and magnesium chloride. This reaction is represented by the unbalanced equation below.Mg(s) + HCl(aq) ==>H2(g) + MgCl2(aq)

State, in terms of the relative activity of elements, why this reaction is spontaneous.

Answers

The reaction depicted by the equation would be spontaneous because Mg is higher in reactivity than H.

Reactivity series of cations

The reactivity series of anions is such that: K, Na, Ca, Mg, Al, Zn, Fe, Sn, Pb, and H.

Ions at the higherposition in the reactivity series are able to displace those in lower positions in chemical reactions. Whereas, those in lower positions cannot displace those in higher positions.

Mg is far higher than H in the reactivity series, and thus, will be able to displace Hfrom HCl without any forceful procedure.

More on the reactivity series can be found here:brainly.com/question/14652325

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How can a mixture of nails and sawdust be most efficiently separated into its component parts?

Answers

I am pretty sure that sawdust float in water so you could dump the mixture in water so that all of the sawdust float on the surface while the nails sink to the bottom.  

You might also be able to use a strong magnet since nails are usually magnetic while sawdust is not.

I hope this helps.  Let me know if anything is unclear or if you need a different method.

A 25.5 liter balloon holding 3.5 moles of carbon dioxide leaks. How many grams of carbon dioxide escaped before the container could be sealed if the new volume of the balloon is 15.4L?

Answers

Assumptions made: 
1. Temperature and pressure is constant. 
2. Ideal gas is involved. 

The variables involved in this problem is the moles of the gas and the volume. We find their relationship from the ideal gas law. PV=nRT. With all other concept besides n and V is constant, Volume is directly proportional to the amount of gas inside the balloon. Solving this is as simple as ratio and proportion. 

25.5L/3.5 moles = =15.4L/X moles 
X= 2.11 moles. 

Answer:

61 grams

Explanation:

If the number of moles of CO₂ in the balloon is given to be 3.5 moles, the mass of CO₂ in the balloon will be

number of moles = mass ÷ molar mass

Hence, mass = number of moles × molar mass

Molar mass of CO₂ is 44g. This is 44 because the atomic mass of carbon is 12 while that of oxygen is 16. Thus, 12 + (16 × 2) = 44 g

mass=  3.5 moles × 44g

mass = 154g (which is the initial mass)

When the mass of CO₂ in the 25.5 liter balloon is 154g, the mass of CO₂ in the balloon when the volume of CO₂ in the balloon is 15.4 liter will be X

To get X,

25.5 L ⇒ 154g

15.4 L ⇒ X

cross-multiply, and

X = (15.4 × 154) ÷ 25.5

X = 93.00 grams (which is the final mass)

93.00 grams of CO₂ was left in the balloon, hence the mass of CO₂ that escaped will be: initial mass minus final mass

= 154g - 93g

= 61g

The mass of CO₂ that escaped is 61 grams

This element is often used to block out dangerous radiation.a. lead
b. carbon-12
c. uranium-236
d. uranium-238

Answers

Lead is often used to block out radiation

When compared with the energy of an electron in the first shell of a carbon atom, the energy of an electron in the second shell of a carbon atom is(1) less(2) greater(3) the same

Answers

When compared with the energy of an electron in the first shell of a carbon atom, the energy of an electron in the second shell of a carbon atom is \boxed{\left( {\text{2}} \right){\text{ greater}}}.

Further explanation:

Quantum numbers:

Quantum numbers govern the size, energy, shape, and orientation of an orbital. The four quantum numbers are as follows:

1. Principal Quantum Number (n): It denotes the principle electron shell. The values of n are positive integers (1, 2, 3,…).

2. Angular Momentum Quantum Number (l): It represents the shape of an orbital. The value of l is an integer from 0 to (n-1).

3. Magnetic Quantum Number\left( {{m_l}} \right): This quantum number represents the orientation of the orbital in space. The value of {m_l}lies between –l to +l. The formula to calculate the value of {m_l} is as follows:

{m_l} =  - l,( - l + 1),.....,0,1,2,.....,(l - 1),l

Therefore, the total number of {m_l} values for a given value of l is 2l+1.

4. Electron Spin Quantum Number({m_s}): It represents the direction of the electron spin. Its value can be + (1)/(2)or- (1)/(2).

The formula to calculate the energy of an electron in an atom is as follows:

{{\text{E}}_{\text{n}}} = \frac{{ - 13.6{{\text{Z}}^2}}}{{{{\text{n}}^{\text{2}}}}}{\text{eV}}                           …… (1)

Here,

E is the energy of an electron.

Z is the atomic number of atom.

n is the principal quantum number.

Calculation of energy of an electron in the first shell of carbon atom.

The value of Z is 6.

The value of n is 1.

Substitute these values in equation (1) to calculate the energy of electron in the first shell.

\begin{aligned}{{\text{E}}_2}&=\frac{{ - 13.6{{\left( 6 \right)}^2}}}{{{{\left( 1 \right)}^{\text{2}}}}}{\text{eV}}\n&=\boxed{-489.6\;{\text{eV}}}\n\end{aligned}

Calculation of energy of an electron in the second shell of carbon atom.

The value of Z is 6.

The value of n is 2.

Substitute these values in equation (1) to calculate the energy of an electron in the second shell.

\begin{aligned}{{\text{E}}_1}&=\frac{{-13.6{{\left( 6 \right)}^2}}}{{{{\left( 2 \right)}^{\text{2}}}}}{\text{eV}\n&=\boxed{-122.{\text{4 eV}}}\n\end{aligned}

The negative sign in the energy of the electron in both the shells indicates that the electron is bound to the nucleus of an atom. So the energy of electron in the second shell of carbon atom is greater than its energy in the first shell of carbon atom and therefore option (2) is correct.

Learn more:

1. Which transition is associated with the greatest energy change? brainly.com/question/1594022

2. Describe the spectrum of elemental hydrogen gas: brainly.com/question/6255073

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Atomic structure

Keywords: energy of electron, n^2, Z^2, -13.6, n, Z, -122.4 eV, -489.6 eV, 6, 1, 2, first shell, second shell.

The answer is (2) greater. The energy of an electron will increase when the number of valence shell increases. So the energy of an electron in the second shell of a carbon atom is greater than in the first shell.