Answer:
True
Explanation:
2 to 5 nm
5 × 10−21 m to 2 × 10−20 m
2 to 5 cm
The atomic radii is approximately between 5 × 10−11 m to 2 × 10−10 m
Gold atoms are similar to alpha particles.
Alpha particles and gold nuclei have opposite charges.
Alpha particles are less dense than gold atoms.
According to ErnestRutherford's gold foil tests, the true statement is that space makes up the majority of gold atoms. The correct option is A.
According to Rutherford's studies, the majority of the alphaparticles encountered free space inside the atom since they mostly went through the gold foil with little to no deflection.
This finding helped scientists comprehend that atoms have a small, compact nucleus at their center and are primarily made up of empty space elsewhere in the atom.
The nuclearmodel of the atom was created as a result of the deflection of several alpha particles, which showed that they came into contact with the positively charged atom's nucleus.
Thus, the correct option is A.
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Your question seems incomplete, the probable complete question is:
In Ernest Rutherford's gold foil experiments, some alpha particles were deflected from their original paths, but most passed through the foil with no deflection. Which statement about gold atoms is supported by these experimental observations?
A. Gold atoms consist mostly of empty space.
B. Gold atoms are similar to alpha particles.
C. Alpha particles and gold nuclei have opposite charges.
D. Alpha particles are less dense than gold atoms
Answer:
A
Explanation:
Answer:
Conductivity, Malleability, High Melting Point, Luster
Explanation:
Transition metals have the following properties:
Conductivity (Electrical and Thermal)
Malleability (You can hit it with a hammer to mold it)
High melting point
Luster (Shininess)
B) 1-chloro-5-ethyl-4-methyl-3-heptene x
C) 1-chloro-3-pentenyl-2-pentene x
D) cis-7-chloro-3-ethyl-4-methyl-3-heptene
E) trans-7-chloro-3-ethyl-4-methyl-3-heptene
The question is incomplete. The complete question is attached below.
Answer : The correct option is, (A) 7-chloro-3-ethyl-4-methyl-3-heptene
Explanation :
The rules for naming of alkene are :
First select the longest possible carbon chain.
The longest possible carbon chain should include the carbons of double bonds.
The naming of alkene by adding the suffix -ene.
The numbering is done in such a way that first carbon of double bond gets the lowest number.
The carbon atoms of the double bond get the preference over the other substituents present in the parent chain.
If two or more similar alkyl groups are present in a compound, the words di-, tri-, tetra- and so on are used to specify the number of times of the alkyl groups in the chain.
The given compound name will be, 7-chloro-3-ethyl-4-methyl-3-heptene.
The structure of given compound is shown below.
The structure given can be named as trans-7-chloro-3-ethyl-4-methyl-3-heptene.
The structure given can be named as trans-7-chloro-3-ethyl-4-methyl-3-heptene. The name is determined by identifying the longest carbon chain, the substituents attached to it, and their positions. In this case, the longest carbon chain has 7 carbons, with a chlorine atom attached at position 7. There is an ethyl group at position 3 and a methyl group at position 4. The presence of double bonds is indicated by the -ene ending.
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