Ammonia, NH3, can be classified as a base because in a chemical reaction with an acid, ammonia will (1 point)produce hydroxide ions in solution. produce hydronium ions in solution. donate a proton and become NH2–. accept a proton and become NH4+.

Answers

Answer 1

Answer:

Answer: Option (d) is the correct answer.

Explanation:

Bases are the electron rich species which readily accept a proton. Therefore, when ammonia is classified as a base in a chemical reaction with an acid, it readily accepts a proton to give ammonium cation.

For example, the reaction of ammonia with hydrochloric acid will be as follows.

$NH_(3) + HCl \rightarrow NH^(+)_(4) + Cl^(-)$

Thus, we can conclude that ammonia, $NH_(3)$ , will accept a proton and become $NH^(+)_(4)$ .

Answer 2

Answer: NH will accept a proton and become NH4+

Bases follow $B^-+H^+=BH$ , with $B^-=NH_3$ in our case.

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What is determined by the motion of and distance between particles of a sample of matter?

Answers

heat is the speed of the particles and defines the higher speed at the higher heat temperature. the temperature of a substance also determines the state of matter a substance is when it has a higher heat temperature at lower densities.

Hi can someone help me with this question!
First one to answer it I will make u brainliest

Answers

Answer:

Test 2

Explanation:

............................................

Answer:

(B) Test 2

Explanation:

The entire substance changed, and turned into a liquid.

How many cases of measles would you predict were reported last year

Answers

In the laws of mathematics, especially in rounding off digits, you should take note of the digit following that number no matter how long or short a number is. If the numberis preceded by numbers between 0-4, the number does not change. However if its is preceded by numbers between 5-9, add one to the number. For example, 145698. If it is rounded off to the nearest hundreds, since 9 is the number after 6, add 1 to 6 and it becomes 145700. If it is rounded off to the nearest hundred thousands, since 4 is the number after 1, you do not add, the number stays the same and it becomes 100000

The true color of water isa. clear.
b. greenish blue.
c. sky blue.
d. green. E. white.

Answers

a. clear.
Water is transparent.

Scientific experiments are specially designed to evaluate explanations for an observed phenomenon. A student decides to conduct an experiment to determine the effect that the amount of time spent in sunlight has on the overall growth of a plant. The student will carry out the experiment using two identical plants that will only spend different amounts of time in sunlight. All other aspects necessary for growth will remain identical for each. In the experiment described, what would be the amount of water given to each plant?

Answers

Answer:

This question lacks options, the options are:

a. an observation

b. a dependent variable

c. an independent variable

d. a control

The answer is D. Control

Explanation:

According to the question, a student decides to conduct an experiment to determine the effect that the amount of time spent in sunlight has on the overall growth of a plant. The student keeps all other variables needed for the plants' growth in this experiment the same/identical. These variables kept identical by the student is called CONTROL OR CONSTANT.

One of the CONTROL is the amount of water given to each plant. The amount of water given to the two plants being tested must be the same. Hence, WATER in this experiment is a CONTROL VARIABLE.

Note that, the independent/manipulable variable is the amount of time spent in sunlight while the dependent/measurable variable is the growth of the plants.

Answer:

The answer is D control

Explanation:

In the following reaction 2C6H6 + 15O2 12CO2 + 6H2O how many grams of oxygen will react with 10.47 grams of benzene (C6H6)?

Answers

$2 C_(6)H_(6) + 15O_(2) ----->\ \textgreater \ 12CO_(2) + 6H_(2)O$

$mol of benzene = (mass)/(Mr)$
= $<span>(10.47g)/((6 * 12) (6 * 1) g/mol)$
= 0.134 mol

mol of oxygen:
ratio of $C_(6) H_(6) : O_(2)$
= 2 : 15
= 1 : 7.5

: . mol of $O_(2)$ = 0.134mol * 7.5
= 1.01 mol

Mass of Oxygen = mol * Mr
= 1.01 mol * (16*2) g/mol
= 32.22g

Note: Mr is molar mass

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