What is the vaule 8x-|-6|

Answers

Answer 1
Answer:

Answer:  8x - 6

Explanation

The |-6| part simplifies to 6. The absolute value removes the negative inside. This is because absolute value represents distance on a number line. The number -6 is 6 units away from 0.

That's how we go from 8x - |-6| to 8x - 6

Since we do not know what x is, we can't simplify further.


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A parking lot is 100 yards long. What is the length of 3/4 of the parking lot, in feet? (Not in words)

Answers

1 yard = 3 feet.

100 yards x 3 = 300 feet.

300 feet x 3/4 = 225 feet.

The answer is 225 feet.

Answer:

225 ft hope it helps

WHAT IS THE SLOPE OF THE LINE6X + 3Y = 18?
Can anyone actually help me work it out please

Answers

Answer:

6x + 3y = 18 \n \n y = - 2x + 6 \n \n x = 3

3y=6x=18 the equation must look like this y=mx+b where m is the slope in this case it is 2 and b is the y-intercept 18 hope it helps

just divide every term by 3 to isolate y

GraceRosalia

On his last 5 math tests, Gilbert earned: 94, 72, 83, 94, 90. What was his average score? ( Report your answer to the tenths place).

Answers

Answer:

Average of Gilbert in last 5 test = 86.6

Step-by-step explanation:

Given:

Score earned by Gilbert in last 5 test = 94, 72, 83, 94, 90

Find:

Average of Gilbert in last 5 test

Computation:

Average value = Sum of all events / Total number of events

Average of Gilbert in last 5 test = Sum of all last results / Number of results

Average of Gilbert in last 5 test = [94 + 72 + 83 + 94 + 90] / 5

Average of Gilbert in last 5 test = [433] / 5

Average of Gilbert in last 5 test = 86.6

2x+3y=-11, and x=2y+12 solve in substition equations

Answers

The answer would be (2,-5)
Because you know the equation for what x is, you can substitute (2y+12) for x. Your new equation would look like this;

2(2y+12)+3y=-11

Distribute the 2 into 2y+12

4y+24+3y=-11

Add 4y and 3y

7y+24=-11

Subtract 24 from both sides

7y=-35

y=-5


Now, substitute -5 in for y in the 2nd equation.

x= 2(-5)+12
x=-10+12
x=2


x=-5
y=2

Hope this helped! You can reach out to me if you have any more questions!

In determining automobile-mileage ratings, it was found that the mpg (X) for a certain model is normally distributed, with a mean of 33 mpg and a standard deviation of 1.7 mpg. Find the following:__________. a. P(X<30)
b. P(28c. P(X>35)
d. P(X>31)
e. the mileage rating that the upper 5% of cars achieve.

Answers

The upper 5% of cars have a mileage rating of 35.805 mpg

What is z score?

Z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

z = (raw score - mean) / standard deviation

Given;  mean of 33 mpg and a standard deviation of 1.7

a) For < 30:

z = (30 - 33)/1.7 = -1.76

P(x < 30) = P(z < -1.76) = 1 - 0.8413 = 0.0392

b) For < 28:

z = (28 - 33)/1.7 = -2.94

P(x < 28) = P(z < -2.94) = 0.0016

c) For > 35:

z = (35 - 33)/1.7 = 1.18

P(x > 35) = P(z > 1.18) = 1 - P(z < 1.18) = 1 - 0.8810 = 0.119

d) For > 31:

z = (31 - 33)/1.7 = -1.18

P(x > 31) = P(z > -1.18) = 1 - P(z < -1.18) = 0.8810

e) The  upper 5% of cars achieve have a z score of 1.65, hence:

1.65 = (x - 33)/1.7

x = 35.805 mpg

The upper 5% of cars have a mileage rating of 35.805 mpg

Find out more on z score at: brainly.com/question/25638875

Answer:

a) P(X < 30) = 0.0392.

b) P(28 < X < 32) = 0.2760

c) P(X > 35) = 0.1190

d) P(X > 31) = 0.8810

e) At least 35.7965 mpg

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = (X - \mu)/(\sigma)

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 33, \sigma = 1.7

a. P(X<30)

This is the pvalue of Z when X = 30. So

Z = (X - \mu)/(\sigma)

Z = (30 - 33)/(1.7)

Z = -1.76

Z = -1.76 has a pvalue of 0.0392.

Then

P(X < 30) = 0.0392.

b) P(28 < X < 32)

This is the pvalue of Z when X = 32 subtracted by the pvalue of Z when X = 28. So

X = 32

Z = (X - \mu)/(\sigma)

Z = (32 - 33)/(1.7)

Z = -0.59

Z = -0.59 has a pvalue of 0.2776.

X = 28

Z = (X - \mu)/(\sigma)

Z = (28 - 33)/(1.7)

Z = -2.94

Z = -2.94 has a pvalue of 0.0016.

0.2776 - 0.0016 = 0.2760.

So

P(28 < X < 32) = 0.2760

c) P(X>35)

This is 1 subtracted by the pvalue of Z when X = 35. So

Z = (X - \mu)/(\sigma)

Z = (35 - 33)/(1.7)

Z = 1.18

Z = 1.18 has a pvalue of 0.8810.

1 - 0.8810 = 0.1190

So

P(X > 35) = 0.1190

d. P(X>31)

This is 1 subtracted by the pvalue of Z when X = 31. So

Z = (X - \mu)/(\sigma)

Z = (31 - 33)/(1.7)

Z = -1.18

Z = -1.18 has a pvalue of 0.1190.

1 - 0.1190 = 0.8810

So

P(X > 31) = 0.8810

e. the mileage rating that the upper 5% of cars achieve.

At least the 95th percentile.

The 95th percentile is X when Z has a pvalue of 0.95. So it is X when Z = 1.645. Then

Z = (X - \mu)/(\sigma)

1.645 = (X - 33)/(1.7)

X - 33 = 1.645*1.7

X = 35.7965

At least 35.7965 mpg

Need help with 5. Part C

Answers

Answer:

  BA = 12

Step-by-step explanation:

All the right triangles are similar, so the ratio of hypotenuse to long side is a constant. In particular ΔABC ~ ΔDBA, so ...

  hypotenuse/long-side = BC/BA = BA/BD

Cross multiplying gives ...

  BA² = BC·BD

  BA = √(BC·BD) = √(16·9)

  BA = 12