The increase of this pigment molecule in the blood induces the yellowish color of the skin described as Jaundice. (a) Stercobilin (b) Bilirubin (c) Urobilin (d) Hemoglobin
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(b) Bilirubin
The pigment molecule that increases in the blood and induces the yellowish color of the skin described as Jaundice is (b) Bilirubin. Jaundice occurs when there is an accumulation of bilirubin in the bloodstream, which can be due to various medical conditions affecting the liver or the breakdown of red blood cells. This excess bilirubin can lead to the yellowing of the skin and the whites of the eyes.
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How many constitutional isomers of C4H9Br are possible? a) Five b) One c) Four d) Three e) Two
Which equation shows conservation of atoms?A) H2 + O 2 --> H2O B) H2 + O 2 --> 2H2O C) 2H2 + O2 --> 2H2O D) 2H2 + 2O2 --> 2H2O
Define equivalent weight of an element​
(2) Cu(s) + 2AgNO3(aq) ==>2Ag(s) + Cu(NO3)2(aq)
(3) 2H2(g) + O2(g) ==>2H2O(l)
(4) KOH(aq) + HCl(aq) ==>KCl(aq) + H2O(l)
Answers
Answer : The correct option is, (1)
Explanation :
The option (1) reaction is an example of decomposition reaction because in this reaction the larger compound, calcium carbonate decomposes into smaller molecule, calcium oxide and carbon dioxide.
Decomposition reaction : It is a type of reaction in which a larger compound decomposes into a smaller molecule or elements.
The option (2) reaction is an example of single displacement reaction because in this reaction the most reactive metal, copper displace the less reaction metal, silver.
The option (3) reaction is an example of combination reaction because in this reaction two reactants, hydrogen and oxygen react to give a single product as water.
The option (4) reaction is an example of double displacement reaction because in this reaction a positive cation and a negative anion of two reactants exchange their places to give two new products.
Hence, the correct option is, (1)
CaCO3(s) ==>CaO(s) + CO2(g)
hope this helps!.
Answers
Answer:
Less than
Explanation:
The process of dissolution occurs as a kind of "tug of war". On one side are the solute-solute and solvent-solvent interaction forces, while on the other side are the solute-solvent forces.
Only when the solute-solvent forces are strong enough to overcome the pre-mixing forces do they overcome the "tug of war", and thus dissolution occurs.
Thus, it is concluded that the interaction forces between solute particles and solvent particles before they are combined are less than the interaction forces after dissolution.
For the dissolution of the soluteparticles in the solvent particles, the force of attraction between the particles of solute and between the particle of solvent must be less than the interaction between the solute particles and solvent particles after dissolution.
In a solution the forces act between the solute molecules, solvent molecules, and solute-solvent molecules. For the dissociation to take place the bond between the solute and solvent has to be formed. The resultant will result in the dissolution of the solute in the solvent mixture. The strong solute-solute and solvent-solvent bond will result in difficulty in the formation of the solute-solvent bond, and the dissolution will not take place.
Thus for the dissolution of the solute particles in the solvent particles, the force of attraction between the particles of solute and between the particle of solvent must be less than the interaction between the solute particles and solvent particles after dissolution.
For more information about dissolution, refer to the link:
A.) 6.8 mol
B.) 13.7 mol
C.) 54.8 mol
D.) 109.6 mol
Answers
2 mol H2 ----------- 1 mol O2
27.4 mol H2- ------ x mol O2
2x = 27.4
x = 27.4 / 2
x = 13.7 moles O2
answer b
hope this helps!.
Answer:
B.) 13.7 mol
Explanation:
Edge 2020
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Final answer:
Uranium (U) is found in the f-block of the periodic table, specifically in the actinide series.
Explanation:
Uranium (U) is found in the actinide series, which is located in the f-block of the periodic table. The actinide series consists of elements with atomic numbers from 89 to 103. Uranium is the 92nd element, making it part of this series. The f-block is located below the main body of the periodic table, between groups 3 and 4.
Learn more about Uranium location in periodic table here:
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A. F = ma
B. F = md
C. F = m/a
D. F = m/d
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