Which atom in the ground state requires the least amount of energy to remove its valence electron?(1) lithium atom (2) potassium atom (3) rubidium atom (4) sodium atom

Answers

Answer 1
Answer:

Answer:

                   Rubidium (Rb)

Explanation:

                           Ionization Energy is defined as, "the minimum energy required to knock out or remove the valence electron from valence shell of an atom".

Trends in Periodic table:

               Along Periods:

                                        Ionization Energy increases from left to right along the periods because moving from left to right in the same period the number of protons (atomic number) increases but the number of shells remain constant hence, resulting in strong nuclear interactions and electrons are more attracted to nucleus hence, requires more energy to knock them out.

              Along Groups:

                                        Ionization energy decreases from top to bottom along the groups because the number of shells increases and the distance between nucleus and valence electrons also increases along with increase in shielding effect provided by core electrons. Therefore, the valence electrons experience less nuclear attraction and are easily removed.

Conclusion:

                   Given elements belong to same group hence, Rubidium present at the bottom of remaining elements will have least ionization energy due to facts explained in trends of groups above.


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Find the density of evaporated milk if 411 grams occupy 384 cm^3

Answers

Answer:

The answer is 1.07 g/cm³

Explanation:

The density of a substance can be found by using the formula

density =  (mass)/(volume) \n

From the question

mass = 411 g

volume = 384 cm³

We have

density =  (411)/(384)  \n  = 1.0703125

We have the final answer as

1.07 g/cm³

Hope this helps you

What is the final concentration of a solution prepared by diluting 35.0 ml of 12.0 m hcl to a final volume of 1.20 l? what is the final concentration of a solution prepared by diluting 35.0 ml of 12.0 m hcl to a final volume of 1.20 l?

Answers

We know that, M1V1     =     M2V2
                        (Initial)          (Final)
where, M1 and M2 are initial and final concentration of soution respectively. 
V1 and V2 = initial and final volume of solution respectively

Given: M1 = 12 m, V1 = 35 ml and V2 = 1.2 l = 1200 ml

∴ M2 = M1V1/V2 = (12 × 35)/ 1200 = 0.35 m
Final concentration of solution is 0.35 m

Final answer:

The final concentration of the solution prepared by diluting 35.0 ml of 12.0 M HCl to a final volume of 1.20 L is 0.35 M.

Explanation:

The final concentration of a solution prepared by diluting 35.0 ml of 12.0 M HCl to a final volume of 1.20 L can be calculated using the formula for dilution: M1V1 = M2V2. In this formula, M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume.

Firstly, we convert the initial volume from ml to litres because the final volume is given in litres. So, 35.0 ml = 0.035 L. Therefore, the equation becomes: 12.0 M * 0.035 L = M2 * 1.20 L.

On rearranging the equation to solve for M2, the result is 0.35 M.

Learn more about Final Concentration here:

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Every action produces an equal and opposite -- ---------- when one object exterts a force on another object,the second object pushes back with the same amount of--------- someone knows the answer​

Answers

The answer will be Reaction, second will be force

When molten material hardens and cools, what type of rock is formed?

Answers

Should be an igneous rock.

Sodium chloride, NaCl forms in this reaction between sodium and chlorine. 2Na(s) + Cl2(g) → 2NaCl(s) How many moles of NaCl result from the complete reaction of 3.9 mol of Cl2? Assume that there is more than enough Na.

Answers

Answer: 7.8 moles of NaCl result from the complete reaction of 3.9 mol of Cl_2

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}*{\text{Molar Mass}}    

\text{Moles of} Cl_2=3.9mol

2Na(s)+Cl_2(g)\rightarrow 2NaCl(s)

As Na is the excess reagent, Cl_2 is the limiting reagent as it limits the formation of product.

According to stoichiometry :

1 mole of Cl_2 gives = 2 moles of NaCl

Thus 3.9 moles of Cl_2 will give=\frac{2}1}* 3.9=7.8moles  of NaCl

7.8 moles of NaCl result from the complete reaction of 3.9 mol of Cl_2

To form a solution, ________. A. substance must dissolve in another
B. a solid must dissolve in a liquid
C. the solvent must be water
D. a gas must dissolve in a liquid

Answers

To form a solution, a substance must dissolve in another. The correct answer will be A. 

Answer:

1.A

2.A

3.A

4.A

100% RIGHT

Explanation: