The fraction models below represent two fractions of the same whole. How many 7 over 10s are there in 1 over 5?Two rectangles of the same size are drawn side by side touching each other. The first rectangle is divided into 10 portions of equal size. Seven of these are shaded. The shaded portion alone is labeled as 7 over 10. The second rectangle is divided into 5 portions of equal size. One portion is shaded. The shaded portion alone is labeled 1 over 5.

fraction 7 over 50
fraction 8 over 50
fraction 1 over 7
fraction 2 over 7

Answers

Answer 1

Answer:

Answer:

To determine how many 7 over 10s are there in 1 over 5, we need to compare the two fractions and find their relationship.

Given:

7 over 10 represents the shaded portion in a rectangle divided into 10 equal portions, with 7 portions shaded.

1 over 5 represents the shaded portion in a rectangle divided into 5 equal portions, with 1 portion shaded.

To find the relationship between these two fractions, we can compare the number of shaded portions in each rectangle.

Since there are 7 shaded portions out of 10 in the first rectangle and 1 shaded portion out of 5 in the second rectangle, we need to determine how many times the shaded portion in the first rectangle fits into the shaded portion in the second rectangle.

To find this, we can set up a proportion:

7/10 = x/1

Cross-multiplying, we get:

10x = 7

Solving for x, we divide both sides by 10:

x = 7/10

Therefore, there are 7 over 10s in 1 over 5.

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Complete the solution of the equation. find the value of y when x equals -8 8x+8y=-48

The work of a student to solve a set of equations is shown below:Equation 1: m = 8 + 2n
Equation 2: 4m = 4 + 4n

Step 1: −4(m) = −4(8 + 2n)
4m = 4 + 4n

Step 2: −4m = −32 − 8n
4m = 4 + 4n

Step 3: −4m + 4m = −32 − 8n + 4n

Step 4: 0 = −32 − 4n

Step 5: n = − 8

In which step did the student first make an error?
Step 1 Step 2 Step 3 Step 4

Answers

The error is found in step 3.

Here is what he did:

-4m + 4m = -32 - 8n + 4n <<<<<<<<<<<< What happened to +4???

0 = -32 - 4n

n = -8.

He made erron in step 3. He forgot add 4. it should be
-4m + 4m = -32 - 8n + 4n +4

Greeting

What is the value of 5c + 2, if c = 6

Answers

Answer:

Step-by-step explanation:

5c + 2, if c = 6

5(6) + 2

30 + 2

= 32

What is 5 x 2 + 3 to the power of 2

Answers

5*2 = 10

3^2 = 3*3 = 9

10 + 9 = 19

Answer: 19

Cone A has a height of 3 meters and a radius of 2 meters. Cone B has the same radius, but the height is 6 meters. Calculate the volume of each cone. Which conclusion is correct?A) The volume of cone A is twice the volume of cone B.
Eliminate
B) The volume of cone B is twice the volume of cone A.
C) The volume of cone B is 4 times the volume of cone A.
D) The volume of cone B is three times the volume of cone A.

Answers

V=(1/3)hpir^2

Avol is (1/3)3pi2^2=4pi m^3

Bvol is (1/3)6pi2^2=2pi4=8pi m^3

B is twice vol A

answer is B

Answer:

Step-by-step explanation:

Which does NOT represent a function
a
b
c
d

Answers

the answer is d
hope this helps

In a relay race, the probability of the Galaxy team winning is 22%. In another unrelated relay race, the probability of the Komets team winning is 47%. If the possibility of a tie is not an option, the probability of the Komets losing their race and the Galaxy winning theirs is ?%

Answers

Answer: There is 12% chance that Komets losing their race and the Galaxy winning theirs.

Step-by-step explanation:

Since we have given that

Probability that Galaxy team winning = 22%

Probability that Komets team winning = 47%

Probability that Komets team losing = 100-47=53%

We need to find the probability of the Komets losing and Galaxy winning their game.

So, Probability that Komets losing and Galaxy winning their game is given by

$(22)/(100)* (53)/(100)\n\n=(1166)/(10000)\n\n=0.1166\n\n=0.12=12\%$

Hence, there is 12% chance that Komets losing their race and the Galaxy winning theirs.

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