A golf ball is dropped from rest from a height of 9.5m.  It hits the pavement then bounces back up rising  just 5.7 m before falling back down again.  A boy then catches the ball on the way down when it is 1.20 m above the pavement.  Ignoring air resistance, calculate the total amount of time the ball is in the air, from drop to catch.

Answers

Answer 1
Answer:

Answer: 3.4s

Explanation:

There are three stages in the motion of the ball, so you have to calculate the times for every stage.

1) Ball dropping from 9.5m: free fall

d = Vo + gt² / 2

Vo = 0 ⇒ d = gt² / 2 ⇒ t² = 2d / g = 2 × 9.5 m / 9.81 m/s² = 1.94 s²

t = √ (1.94 s²) = 1.39s

2) Ball rising 5.7m (vertical rise)

i) Determine the initial speed:

Vf² = Vo² - 2gd

Vf² = 0 ⇒ Vo² = 2gd = 2 × 9.81 m/s² × 5.7m = 111.8 m²/s²

⇒ Vo = 10.6 m/s

ii) time rising

Vf = Vo - gt

Vf = 0 ⇒ Vo = gt ⇒

t = Vo / g = 10.6 m/s / 9.81 m/s² = 1.08 s

3) Ball dropping from 5.7 m to 1.20m above the pavement (free fall)

i) d = 5.7m - 1.20m = 4.5m

ii) d = gt² / 2 ⇒ t² = 2d / g = 2 × 4.5 m / 9.81 m/s² = 0.92 s²

t = √ (0.92 s²) = 0.96s

4) Total time

t = 1.39s + 1.08s + 0.96s = 3.43s ≈ 3.4s

Answer 2
Answer: The time the ball takes to fall 9.5 meters is the square root of (19/g), where g is gravitational acceleration.
The time it takes to rise to 5.7 meters is the square root of (11.4/g), for the same value of g. 
The time it takes to fall from 5.7 meters to 1.2 is the square root of (9/g). 
So the answer is [sqrt(19)+sqrt(11.4)+sqrt(9)]/sqrt(g). If g=10, the answer is 3.39 seconds; if g=9.8, the answer is 3.43 seconds.

Related Questions

1. How does an area’s weather differ from the area’s climate? (1 point). A.Weather involves temperature and precipitation and climate involves only temperature.. B. An area’s weather depends on where it is located on Earth and the area’s climate does not.. C.An area’s weather does not change very much and an area’s climate changes many times.. D.Weather is the area’s day-to-day conditions and climate is the area’s average conditions.. 2. All of the following factors contribute to Earth’s climate EXCEPT (1 point) . latitude.. longitude.. transport of heat by winds.. shape and elevation of landmasse
How will you describe the magnetic field around a current-carrying coil?a.the magnetic field is weakest near and around the coilb)the magnetic field vary directly with the distance from the coilc)the magnetic field is strongest inside the current-carrying coild)the magnetic field lines are closed loops along the loops in the coil
a friend tells you that his family always complains about the noise when he practices his electric guitar in his room. write at least three recommendations for how our friend might reduce the sound that escapes from his room. why do these changes to the room help reduce noise?
Is a marble rolling across the table kinetic energy
Which of the following condition would decrease the ability of a person to hear a sound?

a ball is dropped from rest at a height of 80 m above the ground. what is the speed just as it hits the ground?

Answers

Δx=Vi(t)+.5at²
Δx=80
a=9.8
Vi=0 since its from rest, the initial velocity is 0.
80=0+.5(9.8)t²
t=16.33
You can use one of the big five equations: Vf=Vi+at
Vf=0+9.8(16.33)
Vf=160.034 m/s

Energy is measured in watts and work is measured in joules. true or false?

Answers

it's true
work measure by joule.
Energy = work/time
= joule/s .
and joule/s represents watt

What nondestructive testing method requires little or no part preparation, is used to detect surface or near surface defects in most metals, and may also be used to separate metals or alloys and their heat-treat conditions?

Answers

Answer:Eddy current inspection.

Explanation:EDDY CURRENTS are currents which are produced as a result of changes observed within the magnetic field of an electric circuits. Eddy currents are also called Foucault's Currents. Eddy currents can heat up objects without actually coming in contact with that object.

Eddy current testing or inspection ( ECT) is an electromagnetic testing/inspection methods applied in nondestructive testing (NDT).

Nondestructive testing utilises

Electromagnetic induction to detect and describe surface and sub-surface issuess in conductive materials according to the features of the issues or problems in the conductive material.

Answer:Eddy current testing method.

Explanation:

Non destructive testing methods are techniques which makes use of electromagnetic radiation to examine and detect anomalies in a wide variety of articles( metallic or non - metallic) without causing any changes to it. Non destructive testing is used in science and technology fields such as:

- petroleum engineering,

-mechanical engineering,

- forensic engineering,

- aeronautical engineering and

- medicine.

Types of non destructive testing includes

Eddy current testing, magnetic- particle testing, liquid penetrant testing, radiographic testing, ultrasonic testing, and visual testing.

Eddy current testing method is used to detect surface or near surface defects in most metals, and may also be used to separate metals or alloys and their heat-treat conditions.

A 5.0-kg object is pulled along a horizontal surface at a constant speed by a 15-n force acting 20° above the horizontal. How much work is done by this force as the object moves 6.0 m?

Answers

A 5.0 kg object is pulled by a 15-N force acting 20 °C above the horizontal. After moving for 6.0 m, the work done is 85 J.

What is work?

In physics, work is the energy transferred to or from an object via the application of force along a displacement.

A 5.0 kg object is pulled by a 15-N force acting 20 ° above the horizontal. We can calculate the work done after the object moved 6.0 m using the following expression.

W = F × s × cosθ

W = 15 N × 6.0 m × cos 20° = 85 J

where,

  • W is the work.
  • F is the force.
  • s is the displacement.
  • θ is the angle between F and s.

A 5.0 kg object is pulled by a 15-N force acting 20 °C above the horizontal. After moving for 6.0 m, the work done is 85 J.

Learn more about work here: brainly.com/question/62183

Answer:

84.6 J

Explanation:

The work done by the force is given by

W=Fd cos \theta

where

W is the work done

F = 15 N is the force applied

d = 6.0 m is the displacement

\theta=20^(\circ) is the angle between the force's direction and the displacement

Substituting the numbers into the equation, we find

W=(15 N)(6.0 m)cos 20^(\circ) =84.6 J

A man’s mass is 100 pounds on Earth. His weight is 445N. What would change if this man were on the moon? A) His mass
B) His weight
C) His weight and mass
D) Neither the mass or the weight

Answers

Answer: B) weight

Explanation: Your mass does not change on the moon

A current is always developed in the secondary of a transformer. true or false

Answers

false. only when supply 'alternate' current in the primary.