Simplify the expression:
√125 - √25 + √5

Answers

Answer 1
Answer:

Answer: (6\sqrt{5})

Step-by-step explanation:

To simplify the expression (\sqrt{125} - \sqrt{25} + \sqrt{5}), we’ll start by simplifying each square root separately:

1. (\sqrt{125} = \sqrt{25 \times 5} = \sqrt{25} \times \sqrt{5} = 5\sqrt{5}).

2. (\sqrt{25} = 5).

Now, substitute the simplified square roots back into the original expression:

[5\sqrt{5} - 5 + \sqrt{5}]

Now, combine the terms with (\sqrt{5}):

[5\sqrt{5} + \sqrt{5} = 6\sqrt{5}]

So, the simplified expression is (6\sqrt{5}).


Related Questions

How many times greater is 700,000 than 70,000
HELP! 10 POINTS!! :((
cell phone company Y charges a $10 start-up fee plus $0.10 per minute, x. cell phone company Z charges $0.20 per minute, x, with no start-up fee. which function repesents the difference in cost between company Y and company Z?
What is the slope between 3,6 and 11,6
Find two consecutive whole numbers that 51 lies between.

Max travels to see his brother's family by car. He drives 216 miles in 4 hours. What is his rate in miles per hour? B) Suppose he makes two stops of 10 minutes each during his journey. Will he be able to reach the town in 4 hours if he keeps the speed the same?

Answers

Answer:

54 miles/hour

If he made two stops of 10 minutes each and maintains the same speed, it would take him more than 4 hours to reach the town as the time speed would have been extended by 20 minutes.

Step-by-step explanation:

The rate of change of distance with time is called speed and it is measured in miles per hour. Mathematically,

Speed = Distance/time

His rate in miles per hour is his speed

= 216/4

= 54 miles per hour

Answer:

Rate in miles per hour: 54 miles per hour

Step-by-step explanation:

The equation D=13/v shows that the density of a particular substance equals a mass of 13 grams divided by the volume of the substance. What happens to the density as the volume approaches 0?The density approaches infinity.
The density approaches 0.
The density approaches 1.
The density approaches 13.

Answers

D = 13/v

What happens to the density as the volume approaches 0?

The density approaches 13.

Assume : V = 3 ; V = 2 ; V = 1

D = 13/3 = 4.33
D = 13/2 = 6.50
D = 13/1 = 13

Answer:

Option A is correct

The density approaches infinity.

Step-by-step explanation:

Given the equation:

D = (13)/(v)               ....[1]

where,

D is density of a particular substance .

v is the volume of the substance.

We have to find What happens to the density as the volume approaches 0.

As the volume approaches to 0

v \rightarrow 0

[1] ⇒

D \rightarrow \infty

⇒The density approaches infinity.

Therefore, the density as the volume approaches 0 is,  infinity.

F (x)=2x-1 Find f (-2)

Answers

Answer:

-5

Step-by-step explanation:

f(x) =2x-1

f(-2)=2(-2)-1

2×(-2) = -4 -1= -5

f(-2)= -5

Marie spends 14 dollars on lottery tickets every week and spends $128 per month on food. On an annual basis, the money spent on lottery tickets is what % of the money spent to buy foid

Answers

The money spend on lottery tickets is 40%

A caterer knows that 18 heads of lettuce are needed to make dinner salads fro 70 people. How many heads of lettuce are needed for a party of 175 people?

Answers

45 because 70 multiplied by 2 equals 140. There are 35 left over which is half of 70 meaning you have to multiply 18 by 2.5 to get your answer.

Joe, Keitaro, and Luis play tennis. To decide who will play against each other in the first match, they put their names in a hat and choose two names without looking.What subset, A, represents the complement of the event in which Joe plays in the first match?


A = {KL}

A = {KJ, KL}

A = {KL, LK}

A = {KJ, KL, LJ}

Answers

Answer:  First Option is correct.

Step-by-step explanation:

Since we have given that

There are three person : Joe, Keitaro, Luis.

And two names will be selected for he game .

Possible events will be

\{JK,JL,KL\}

But we want to find the complement of the event in which Joe plays in hte first match,

As we know that complement of any events means eliminate that event from the universal set.

Event of getting Joe plays in the first match is given by

\{JK,JL\}

So, complement of this event that Joe plays in the first match is given by

\{KL\}

so, First Option is correct.

The possible events are:

{JK, JL, KL}

The events where J does not play (the first game) are: {KL}

Answer: A = {KL}