rabbit
mushroom
tulip
Answer:
mushroom
Explanation:
Answer: Kilograms (kg)
Explanation:
Answer:
(g)
Explanation:
(g) is the symbol of a gram which is the metric unit that measures mass.
Hope that helps!
The number of moles in 82 grams of water is calculated by dividing the given mass (in grams) by the molar mass (in g/mol). Thus, the number of moles in 82 grams of water is 4.56 moles.
The number of moles in 82 g of water can be calculated using the molar mass of water. The molar mass of water is the sum of the molar masses of its constituent elements. Hydrogen has a molar mass of approximately 1 g/mol and oxygen has a molar mass of approximately 16 g/mol. Therefore, the molar mass of water is 18 g/mol. To calculate the number of moles in 82 g of water, we divide the mass by the molar mass:
Number of moles = Mass (g) / Molar mass (g/mol)
Number of moles = 82 g / 18 g/mol
Number of moles = 4.56 mol
#SPJ2
(2) CO2 and CH4 (4) H2O and CH4
Answer is: 3) H2O and HCl.
Polar molecules are water (H₂O) and hydrochloric acid (HCl).
Nonpolar molecules are carbon(IV) oxide (CO₂) and methane (CH₄).
Carbon(IV) oxide is nonpolar because CO₂ is linear molecule and the oxygen atoms are symmetrical (bond angles 180°).
Water is polar because of the bent shape of the molecule.
Hydrochloric acid has polar covalent chemical bond where hydrogen has oxidation umber +1 and chlorine oxidation number -1.
In molecule of methane (CH₄) all the atoms around the central element (carbon) are equivalent (four hydrogens) and it has a net dipole moment of 0 (vectors of dipole moments cancel each other, dipole moment is zero).
In this reaction, ammonia molecules (NH3) act as a base because they
(1) accept hydrogen ions (H+)
(2) accept hydroxide ions (OH-)
(3) donate hydrogen ions (H+)
(4) donate hydroxide ions (OH-)
Answer:
1. accept hydrogen ions (H+)
Explanation:
In the given reaction, NH3 acts as a base because it accepts hydrogen ions (H+) from the acid HCl to form the conjugate acid NH4+. Therefore, the correct answer is 1. accept hydrogen ions (H+).