The Smith'd CD’s sell for $10 and Arctic Monkeys CD’s sell for $15. If a music store sold 18 CD’s and worth $240, how many of each CD did they sell?​

Answers

Answer 1
Answer:

Answer:

6 Smith'd CDs

12 Arctic Monkeys CDs

Step-by-step explanation:

To solve this problem, we can use a system of equations. Let x be the number of Smith'd CDs sold and y be the number of Arctic Monkeys CDs sold. We know that the total number of CDs sold is 18 and the total sales is $240. We can represent this information in the following system of equations:

x + y = 18

10x + 15y = 240

We can solve this system of equations using elimination. Multiplying the top equation by -10, we get:

-10x - 10y = -180

10x + 15y = 240

Adding the top and bottom equations, we get:

5y = 60

Dividing both sides by 5, we get:

y = 12

Now that we know the value of y, we can substitute it into the top equation to find the value of x:

x + 12 = 18

x = 18 - 12

x = 6

Therefore, the music store sold 6 Smith'd CDs and 12 Arctic Monkeys CDs.


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ON A TEST PLZ ANSWER This equation represents what type of function?y=1/2x^3+ 5x
A linear
B quadratic
C exponential
D cubic

Answers

Linear equation is the answer

Susan averages 8 birdies in an 18 hole round of golf. how many birdies should she expect after playing 45?

Answers

Hey there, 8 birdies in an 18 hole is 8/18, 8/18 simplified is 4/9, 4/9*45=20. Therefore, the answer is 20 birdies.

5) What is the value of n in the picture?3n
n 14
A) 19
B) 33
C) 57
D) 41.5

Answers

ok. because those two angles are sumplimentary, (they equal 180 degrees) we can set up an equations.
3n+n+14=180

then isolate the variable
4n+14=180 
     -14   -14
4n=166

then divide to undo the multiplication

4n=166
---   ----
4      4
 
n=41.5

that's super wrong .the answer cannot be 41.5 because if n=41.5 then 41.5 ×4 =166 +90 +14 =270 and that's wrong because in the diameter need have 180 not 270 so is 19×4+90+14=180 answer = 19

The length of a rectangle is 5cm longer than twice the length of the width. If the perimeter is 88 centimeters, what is the width?

Answers

L = length
W = width
P = perimeter

Equations:
L = 2W + 5
2L + 2W = P
P = 88

Solve using the equations above:

2(2W + 5) + 2W = 88
4W+ 10 + 2W = 88
6W + 10 = 88
6W = 78
w=16

the width is 16 centimeters

Write the quadratic equation whose roots are-1 and 6, and whose leading coefficient is 4

(Use the letter to represent the variable.)
?=0

Answers

The quadraticequation is 4x² - 20x - 24 = 0 whose roots are-1 and 6.

What is a quadratic equation?

The quadratic equation is defined as a function containing the highest power of a variable is two.

The roots are given in the question, as follows:

-1 and 6

As we know that the standard quadratic equation ax² + b x + c = 0.

Since the leading coefficient of the quadratic equation is 4

So, a = 4

The sum of roots = -b/a

-1 + 6 = -b/4

5 = -b/4

b = -20

The multiplication of roots = c/a

-1 × 6 = c/4

c = -24

So, the quadratic equation is 4x² - 20x - 24 = 0.

Learn more about quadratic function here:

brainly.com/question/14083225

#SPJ2


You've got a=4

-b/a=sum=-1+6=5 so b=-20

c/a=product=-1*6=-6 so c=-6

Final equation: 4x^2-20x-6=0

NEED answer soon. just the 4 letters thankss

Answers

Answer:

a = 25m^2

b = 5m

d = 35.73 m^2

c = 7.94m

Step-by-step explanation:

First, remember that the area of a square of side length L is:

A = L^2

And for a triangle rectangle with catheti a and b, and hypotenuse H, we have the relation:

H^2 = a^2 + b^2  (Phytagorean's theorem)

Ok, let's look at the left image, we have a green triangle rectangle.

The bottom cathetus has a length equal to the side length of a square with area of 16m^2

Then the side length of that square (and the cathetus) is:

L^2 = 16m^2

L = √(16m^2) = 4m

The left cathetus has a length equal to the side length of a square of area = 9m^2

Then the side length of that cathetus is:

K^2 = 9m^2

K = √(9m^) = 3m

Then the catheti of the green triangle rectangle are:

4m and 3m

Then the hypotenuse of this triangle (b) is:

b^2 = (4m)^2 + (3m)^2

b^2 = 16m^2 + 9m^2 = 25m^2

b = √(25m^2) = 5m

And b is the side length of the red square, then the area of that square is:

a = b^2 = 25m^2

Now let's go to the other image.

Here we have an hypotenuse of side length H, such that:

H^2 = 144m^2

And we have a cathetus (the one adjacent to the green triangle) of side length L such that:

L^2 = 81m^2

The other cathetus will have a sidelength c, such that:

c^2 = area of the purple square

By the Pythagorean's theorem we have:

144m^2 = 81m^2 + c^2

144m^2 = 81m^2 + c^2

144m^2 - 81m^2 = c^2

63m^2 = c^2

(√63m^2) = c = 7.94m

And the area of a triangle rectangle is equal to the product between the catheti divided by two.

We know that one cathetus is equal to c = 7.94m

And the other on is equal to the square root of 81m^2

√(81m^2) = 9m

then the area of the triangle is:

d = (7.94m)*(9m)/2 = 35.73 m^2