Answer:
6 Smith'd CDs
12 Arctic Monkeys CDs
Step-by-step explanation:
To solve this problem, we can use a system of equations. Let x be the number of Smith'd CDs sold and y be the number of Arctic Monkeys CDs sold. We know that the total number of CDs sold is 18 and the total sales is $240. We can represent this information in the following system of equations:
x + y = 18
10x + 15y = 240
We can solve this system of equations using elimination. Multiplying the top equation by -10, we get:
-10x - 10y = -180
10x + 15y = 240
Adding the top and bottom equations, we get:
5y = 60
Dividing both sides by 5, we get:
y = 12
Now that we know the value of y, we can substitute it into the top equation to find the value of x:
x + 12 = 18
x = 18 - 12
x = 6
Therefore, the music store sold 6 Smith'd CDs and 12 Arctic Monkeys CDs.
A linear
B quadratic
C exponential
D cubic
n 14
A) 19
B) 33
C) 57
D) 41.5
(Use the letter to represent the variable.)
?=0
The quadraticequation is 4x² - 20x - 24 = 0 whose roots are-1 and 6.
The quadratic equation is defined as a function containing the highest power of a variable is two.
The roots are given in the question, as follows:
-1 and 6
As we know that the standard quadratic equation ax² + b x + c = 0.
Since the leading coefficient of the quadratic equation is 4
So, a = 4
The sum of roots = -b/a
-1 + 6 = -b/4
5 = -b/4
b = -20
The multiplication of roots = c/a
-1 × 6 = c/4
c = -24
So, the quadratic equation is 4x² - 20x - 24 = 0.
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You've got a=4
-b/a=sum=-1+6=5 so b=-20
c/a=product=-1*6=-6 so c=-6
Final equation:
Answer:
a = 25m^2
b = 5m
d = 35.73 m^2
c = 7.94m
Step-by-step explanation:
First, remember that the area of a square of side length L is:
A = L^2
And for a triangle rectangle with catheti a and b, and hypotenuse H, we have the relation:
H^2 = a^2 + b^2 (Phytagorean's theorem)
Ok, let's look at the left image, we have a green triangle rectangle.
The bottom cathetus has a length equal to the side length of a square with area of 16m^2
Then the side length of that square (and the cathetus) is:
L^2 = 16m^2
L = √(16m^2) = 4m
The left cathetus has a length equal to the side length of a square of area = 9m^2
Then the side length of that cathetus is:
K^2 = 9m^2
K = √(9m^) = 3m
Then the catheti of the green triangle rectangle are:
4m and 3m
Then the hypotenuse of this triangle (b) is:
b^2 = (4m)^2 + (3m)^2
b^2 = 16m^2 + 9m^2 = 25m^2
b = √(25m^2) = 5m
And b is the side length of the red square, then the area of that square is:
a = b^2 = 25m^2
Now let's go to the other image.
Here we have an hypotenuse of side length H, such that:
H^2 = 144m^2
And we have a cathetus (the one adjacent to the green triangle) of side length L such that:
L^2 = 81m^2
The other cathetus will have a sidelength c, such that:
c^2 = area of the purple square
By the Pythagorean's theorem we have:
144m^2 = 81m^2 + c^2
144m^2 = 81m^2 + c^2
144m^2 - 81m^2 = c^2
63m^2 = c^2
(√63m^2) = c = 7.94m
And the area of a triangle rectangle is equal to the product between the catheti divided by two.
We know that one cathetus is equal to c = 7.94m
And the other on is equal to the square root of 81m^2
√(81m^2) = 9m
then the area of the triangle is:
d = (7.94m)*(9m)/2 = 35.73 m^2