The option 'mix household products together' is not a safety tip when using household chemicals. On the contrary, it can be dangerous due to potential harmful reactions. Other tips suggested are all important for safety (option c).
The option that is not a safety tip for using household chemicals is 'c. mix household products together'. Mixing different household chemicals or cleaners can be very dangerous and can lead to harmful reactions.
Such a reaction can produce harmful gases which can be fatal. Other options listed, a. read the label before use, b. open a fan or window when using chemicals and d. wear protective clothing, are all important measures to ensure safety when handling household chemicals.
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a) in this we are diluting a stock solution, so we can use the dilution formula
c1v1 = c2v2
where c1 is concentration and v1 is volume of the stock solution
c2 is concentration and v2 is volume of the diluted solution to be prepared
substituting the values
6.0 M x V = 0.500 M x 110 mL
V = 9.17 mL
9.17 mL of the stock solution should be taken and diluted upto 110 mL to prepare the 0.500 M solution
b)
In this question we are given the volume taken from the stock solution , we have to find the concentration of the diluted solution
again we use the dilution formula, c1v1 = c2v2
substituting the values
6.0 M x 10.0 mL = C x 250 mL
C = 0.24 M
the concentration of diluted solution is 0.24 M
To prepare 110 ml of 0.500 M HNO3 from a 6.0 M HNO3 solution, 9.17 ml of the stock solution would have to be used. If 10.0 ml of the stock solution is diluted to a final volume of 0.250 L, the concentration of the diluted solution will be 0.24 M.
(a) In order to prepare 110 ml of 0.500 M HNO3 from a 6.0 M HNO3 solution, we have to use the formula M1V1 = M2V2 where M and V are the molarity and volume respectively. Here, the M1 and V1 are the molarity and volume of the stock solution and M2 and V2 are the molarity and volume of the diluted solution. Filling in known values, 6.0M * V1 = 0.500M * 110ml. Solving for V1, we get V1 = (0.500 M * 110 ml) / 6.0 M = 9.17 ml. So, you would have to use 9.17 ml of the stock solution.
(b) The diluted solution's molarity is calculated using the same formula as before. Substituting the known values 6.0M * 10.0 ml = M2 * 0.250 L, rearrange the formula to get M2= (6.0M * 10.0 ml) / 0.250 L = 0.24 M or 240 mM. Therefore, the concentration of the diluted solution is 0.24 M.
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The CCl₄ molecule has a tetrahedral geometry. It is a symmetrical molecule. The polarised bond thus cancels out each other due to the geometry of the molecule and that is why CCl₄is nonpolar.
Chlorine has a higher electronegativity than phosphorous. As a result, the chlorine atom has a partial negative charge relative to phosphorous. Since all three chlorine atoms pull electrons from the phosphate atom, the molecule is a polar molecule.
The reason why CCl₄is not soluble in water is because it is not soluble in polar solvents. Both PCl₃ and water are polar molecules. This is due to their shape and the electronegativity difference between the H and O molecules in water and the P and Cl molecules in PCl₃. Therefore, PCl₃in water is soluble.
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b. least abundant isotope
c. radioactive isotopes
d. most abundant isotope
Answer:
I say its A.
But im not EXTREMELY sure
Explanation:
Answer:
A. Naturally ocuring isotopes
Explanation:
Molarity is defined as the number of moles per liter of solution.
Mathematically, Molarity =
Since it is given that the molarity of a solution of 14.0 g and volume is 150 mL or 0.15 L.
Whereas number of moles =
So, molar mass of is 97.94 g/mol.
Thus, number of moles =
= 0.142 mol
Therefore, calculate the molarity as follows.
Molarity =
=
= 0.946 mol/L
Hence, we can conclude that molarity of the solution is 0.946 mol/L.
The molarity of the solution is approximately 0.952 M.
To calculate the molarity of the solution, we need to convert the given mass of NH4Br to moles. The molar mass of NH4Br is 97.94 g/mol. So, 14.0 g of NH4Br is equal to 0.143 mol. Next, we convert the given volume of the solution to liters, which is 0.150 L. Finally, we divide the number of moles by the volume in liters to find the molarity.
Molarity (M) = moles/volume (L)
Therefore, the molarity of the solution is approximately 0.952 M.
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