What is the solution of the system of equations c+3d=8 and c=4d-6?
Show work plz.

Answers

Answer 1

Answer: $\left\{\begin{array}{ccc}c+3d=8\nc=4d-6\end{array}\right\n\nsubstitute:\n\n(4d-6)+3d=8\n4d+3d-6=8\ \ \ \ /+6\n7d=14\ \ \ \ /:7\nd=2\n\nc=4\cdot2-6=8-6=2\n\n\left\{\begin{array}{ccc}c=2\nd=2\end{array}\right$

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fifteen percent of the workers at nationwide industries earn minimum wage. if 24 workers earn minimum wage, how many total workers are there at nationwide industries.?

Answers

24/.15 (for the decimal value of 15%) to obtain a value of 160 nationwide industry workers

I don’t understand the answer can you explain it please?

If DE = 7x + 3 and EF = 9x - 19,
then EF = ?

Answers

The measure of line segment EF from the given line segment DF is 80 units.

From the given line segment $DE=7x+3$ and $EF=9x-19$ .

A midpoint of a line segment is the point on a segment that bisects the segment into two congruent segments.

In the given line segment $DE=EF$

$7x+3=9x-19$

$3+19=9x-7x$

$2x=22$

$x=(22)/(2)$

$x=11$

Substitute $x=11$ in $EF=9x-19$ , we get

$EF=9(11)-19$

$EF=80$

Therefore, the measure of line segment EF is 80 units.

To learn more about the midpoint of line segment visit:

brainly.com/question/29163672.

#SPJ3

Answer:

Step-by-step explanation:

7x + 3 = 9x - 19

-2x + 3 = -19

-2x = -22

x = 11

DE= 7(11) + 3 = 77 + 3 = 80

EF = 9(11) - 19 = 99 - 19 = 80

80 + 80 = 160 for DF

Can anyone help me please?
What is
21 times x = 7

Answers

Answer:

x = 1/3

Step-by-step explanation:

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other:

21x = 7

Divide 21 from both sides:

(21x)/21 = (7)/21

x = 7/21

x = 1/3

x = 1/3 is your answer.

Answer: is 3 unless you mean that the x=7 if you mean that then it would be 147

How do i solve and graph $5x- y \geq 5$

Answers

one way is to make it into slope intercept form which is
y=mx+b
m=slope
b=y intercept or where the line will go though the y axis
treat the equal to or greater than sign as equals for now

5x-y=5
subtract y from both sides
5x=5+y
subtract 5
5x-5=y
put the sign back in
5x-5 ≥ y
reverse
y ≤ 5x-5

one way is to subsitute values and get values out so
if x=1 then
y≤5(1)-5
y≤0
(x,y)
(1,0)
(2,5)
(3,10)
(4,15)
(0,-5)

plot the points
then the ≤ sign
since ther is an underline, that means that the points are included so draw a solid line through the points

then figure out which side to shade on
the easy way is, is the point (0,0) a solution?
subsitute
0 ≤ 5(0)-5
0 ≤ -5
false so we shade the section that does not include the point (0,0) in it
the graph would look like this attachment

(you have to put y alone {Ex: y = 12x + 3 (yis alone on one side)}

5x - y ≥ 5 (subract 5x from each side)
-y ≥ -5x + 5 (divide - or -1 from each side) Note: when you are dividing or multiplying anything negative the sign changes
y ≤ 5x - 5 <--- answer

As for graphing you take the equation and graph it normally, but with a slight change. since y is less than or equal to 5x - 5, you have to color on the spACE BELOW the graphed line.

see picture:

The roots of the function f(x) = x2 – 2x – 3 are shown. what is the missing number? x = –1 and x =

Answers

we have

$f(x)=x^(2)-2x-3$

Find the roots

Equate the function to zero

$x^(2)-2x-3=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^(2)-2x=3$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^(2)-2x+1=3+1$

$x^(2)-2x+1=4$

Rewrite as perfect squares

$(x-1)^(2)=4$

Square root both sides

$(x-1)=(+/-)2$

$x=1(+/-)2$

$x=1+2=3$

$x=1-2=-1$

therefore

the answer is

$x=3$

x^2 -2x -3 = 0

(x-3)(x+1)=0

x+1=0
x=-1

x-3=0
x = 3

so the missing number is 3

Which of the following could not be true for a function?Domain is {2}, Range is {2}
Domain is {2, 3}, Range is {2}
Domain is {2}, Range is {2, 3}
Domain is {2, 3}, Range is {2, 3}