MATHEMATICS HIGH SCHOOL

Is .05 greater than 1/20

Answers

Answer 1
Answer: No, they are both the same.

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PLSSS? i dont really get itThanks
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Order from least to greatest 0.4,5/8,38%

Answers

38%, 0.4, 5/8

I don't know hot to explain it :D

If you need more help message me so you don't use your points!

For each value of kk specified in parts (a)–(e), plot the set of points in the plane that satisfy the equationx2 / k − y2 = 1.
a. k = −1
b. k = 1
c. k = 2
d. k = 4
e. k = 10
f. k = 25
g. Describe what happens to the graph of
x2 / k − y2 = 1 as k → [infinity].

Answers

Answer:

Seee answer below.

Step-by-step explanation:

a. k = −1

If K=-1 the equation gets this form:

(x^2/-1) -y^2=1

There aren't natural numbers that being negative, adding them, we get 1 as result. So there is no graph for this equation.

b. k = 1

(x^2/1) -y^2=1

This is the natural form of the equation of an hyperbola. Attached you can find the graph.

c. k = 2

(x^2/2) -y^2=1

This is the natural form of the equation of an hyperbola. Attached you can find the graph.

d. k = 4

(x^2/4) -y^2=1

This is the natural form of the equation of an hyperbola. Attached you can find the graph.

e. k = 10

(x^2/10) -y^2=1

This is the natural form of the equation of an hyperbola. Attached you can find the graph.

f. k = 25

(x^2/25) -y^2=1

This is the natural form of the equation of an hyperbola. Attached you can find the graph.

g. Describe what happens to the graph of

x2 / k − y2 = 1 as k → [infinity].

As K is increasing the value of X will be tending to 0. So the equation for this will be:

− y^2 = 1.The solution for this is in the domain of the imaginary numbers.

Make a formula to find the of the diameter 'a' if the area is 'A'. ​

Answers

Answer:

2\sqrt{(A)/(\pi)} = a

Step-by-step explanation:

I am assuming that you are referring to the diameter and area of a circle. If this is false, then please note that my answer is wrong.

Ok, we know that the area formula for a circle is A = \pi r^(2), where r is the radius.

We also know that the diameter, a, is two times the radius. Thus, a = 2r, which also means that  (1)/(2) a = r. This means that we can substitute the radius (r) with half the diameter ((1)/(2)a) in the area formula equation:

A = \pi *((1)/(2) a)^(2)

Your question asks us to find the diameter, which means we must solve for, or isolate, the diameter (a):

A = \pi *((1)/(2) a)^(2)\n(A)/(\pi) =((1)/(2) a)^(2)\n(A)/(\pi) =(1)/(4) a^(2)\n(4A)/(\pi) = a^(2)\n\sqrt{(4A)/(\pi)} = a\n2\sqrt{(A)/(\pi)} = a

What are the answers to the picture?

Answers

Answer: Brailiest plz?

prt 1 (42°) 48° is complementary

prt2 (42°) 138° is supplementary

prt1 (81°) 9° is complementary

prt2 (81°) 99° is supplementary

Step-by-step explanation:

Whats the correct option?

Answers

-2 looks to be it as I can see I just would have to work it out

Which is greater, 4 or 126?

Answers

Answer:

126

Step-by-step explanation:

4 is less than 126 so 126 > 4
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