The correct IUPAC chemical names for Copper chloride, Copper bromide, Copper iodide, and Copper hydride are Copper(II) chloride, Copper(II) bromide, Copper(II) iodide, and Copper hydride respectively.
In accordance with International Union of Pure and Applied Chemistry (IUPAC) naming conventions, the chemical names for the given formulas are as follows:
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(2) equal to the total number of protons gained
(3) less than the total number of electrons gained
(4) less than the total number of protons gained
Answer is: (1) equal to the total number of electrons gained.
In oxido-reduction reaction, at least one element lose and one element gain electrons.
Oxidation reaction is increasing of oxidation number of atom, because element lost electrons in chemical reaction.
Reduction is lowering oxidation number because atom gain electrons.
For example, in oxidation-reduction reaction: 2H₂ + O₂ → 2H₂O; hydrogen is oxidized (change oxidation number from 0 to +1) and oxygen i s reduced (change oxidation number from 0 to -2).
Hydrogen lost .four electrons anf oxygen gain four electrons
(2) 0.10 M K2SO4(aq)
(3) 0.10 M K3PO4(aq)
(4) 0.10 M KNO3(aq)
Electron sea model: Electrons all have approximately the same energy.
Band theory: Electrons move among orbitals of different energies.
Both models: Electrons move freely among atoms (delocalized).
is the answer on edgeunuity
The volume of one mole of gas at STP is 22.4 liters.
In the combustion reaction of acetylene (C2H2), 60 liters of CO2 will be produced if 60 liters of O2 is used.
To determine the volume of CO2 produced in the combustion reaction of acetylene (C2H2), we need to use stoichiometry. From the balanced equation, we can see that 2 moles of C2H2 produce 4 moles of CO2. The ratio is 2:4 or 1:2. Given that 60 liters of O2 is used, we can assume the same volume of CO2 will be produced since both gases are at STP.
Therefore, the volume of CO2 produced would be 60 liters as well.
Keywords: combustion, volume, acetylene, O2, CO2, STP
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Answer: Na has a ground-state electronic configuration of 1s2 2s2 2p6 3s1. Removing the 3s electron leaves us with the noble gas configuration 1s2 so a sodium ion is Na+.
Explanation: I HOPE THAT HELPED!
The ground state electron configuration for sodium (Na) is 1s²2s²2p63s¹. The electron in the outermost shell (3s orbital) is the valence electron, with the rest being core electrons. It can be abbreviated as [Ne]3s¹.
The ground state electron configuration for sodium (Na), an alkali metal with atomic number 11, is 1s²2s²2p63s¹. This configuration includes one electron in the outermost shell, or 3s orbital, and the rest in the core electron shells. To abbreviate this, we look at the noble gas that matches the core configuration, in this case neon (Ne), and the configuration becomes [Ne]3s¹. The outermost electron, in the 3s orbital, is known as a valence electron, while the others are core electrons.
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