89.64 decreased by 8%

Answers

Answer 1

Answer:

if a number is decreased by 8%, it becomes 92%, or .92, of the original number.

we can then find the answer by multiplying 89.64 by .92 to get 82.4688

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One half of the sum of a number and 10

Answers

The expression (1/2)[x+10] represents the one half of the sum of a number and 10.

What is an expression?

It is defined as the combination of constants and variables with mathematical operators.

We have:

One half of the sum of a number and 10

Let's suppose the number is x:

So from the problem, the one half of the sum of a number and 10 is:

$\rm =(1)/(2)(x+10)$

The above expression represents the one half of the sum of a number and 10.

Thus, the expression (1/2)[x+10] represents the one half of the sum of a number and 10.

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One half of the sum of a number and 10

n - a number

$(1)/(2)(n+10)$

A surveyor has poles A, B, and C set to form a right triangle with the right angle at B. If the distance from A to B is 35 meters and the distance from B to C is 25 meters, what is the distance from A to C? He can t measure it because there is a deep pond between points A and C.

Answers

It's about Pythagorean theorem.

AB*AB + BC*BC = AC*AC, so:

35*35 + 25*25 = AC*AC
1225 + 625 = AC*AC
1850 = AC*AC

So AC is a root of 1850, which is ~43 (exactly: 43,01162633521313)

It means that distance between A and C is 43 meters and some milimeters.

What is the reference angle for 7pi/2

Answers

The reference angle is -90 deg or -pi/2

I think its 90 degrees

The difference of two numbers is 20 and their product is 125 what is the answer

Answers

The value of the two numbers will be -25 and -5.

What is an expression?

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that the difference between the two numbers is 20 and their product is 125. Let the two numbers are x and y.

x - y =20 or x = y + 20

xy = 125

Solve the equations,

y(y+20) = 125

y² + 20y -125 =0

y² +25y - 5y -125=0

y(y + 25) --5(y + 25) = 0

( y + 25 )( y - 5 ) = 0

y = -25 and y = 5

x = y + 20

x = -25 + 20

x = -5

Therefore, the value of the two numbers will be -25 and -5.

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Solve this..➕+ ➕ + ➕+ ➕=30
Fill the boxes using (1, 3, 5, 7, 9, 11, 13, 15)
U can also repeat the numbers..

Answers

These are all possible combinations:
1 , 1 , 13 , 15
1 , 3 , 11 , 15
1 , 3 , 13 , 13
1 , 5 , 9 , 15
1 , 5 , 11 , 13
1 , 7 , 7 , 15
1 , 7 , 9 , 13
1 , 7 , 11 , 11
1 , 9 , 9 , 11
3 , 3 , 9 , 15
3 , 3 , 11 , 13
3 , 5 , 7 , 15
3 , 5 , 9 , 13
3 , 5 , 11 , 11
3 , 7 , 7 , 13
3 , 7 , 9 , 11
3 , 9 , 9 , 9
5 , 5 , 5 , 15
5 , 5 , 7 , 13
5 , 5 , 9 , 11
5 , 7 , 7 , 11
5 , 7 , 9 , 9
7 , 7 , 7 , 9

There can be a lot many solutions for the above question
some of them are
9+11+5+5=30
it can also be solved as
15+5+5+5=30
also
13+7+5+5=30

Sales at a fast-food restaurant average $6,000 per day. The restaurant decided to introduce an advertising campaign to increase daily sales. To determine the effectiveness of the advertising campaign, a sample of 49 days of sales were taken. They found that the average daily sales were $6,300 per day. From past history, the restaurant knew that its population standard deviation is about $1,000. If the level of significance is 0.01, have sales increased as a result of the advertising campaign? Multiple Choice A. Reject the null hypothesis and conclude that the mean is equal to $6,000 per day.
B. Fail to reject the null hypothesis.
C. Reject the null hypothesis and conclude the mean is lower than $6,000 per day.
D. Reject the null hypothesis and conclude the mean is higher than $6,000 per day.

Answers

Answer:

Option B) Fail to reject the null hypothesis.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = $6,000

Sample mean, $\bar{x}$ = $6,300

Sample size, n = 49

Alpha, α = 0.01

Population standard deviation, σ = $1,000

First, we design the null and the alternate hypothesis

$H_(0): \mu = 6000\text{ dollars per week}\nH_A: \mu > 6000\text{ dollars per week}$

We use one-tailed(right) z test to perform this hypothesis.

Formula:

$z_(stat) = \displaystyle\frac{\bar{x} - \mu}{(\sigma)/(√(n)) }$

Putting all the values, we have

$z_(stat) = \displaystyle(6300 - 6000)/((1000)/(√(49)) ) = 2.1$

Now, $z_(critical) \text{ at 0.01 level of significance } = 2.33$

Since,

$z_(stat) < z_(critical)$

We fail to reject the null hypothesis and accept the null hypothesis. Thus, we conclude that sales have not increased as a result of the advertising campaign

Option B) Fail to reject the null hypothesis.

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