(3x - 40)° (2x + 23)°​

Answers

Answer 1
Answer:

Answer:

Step-by-step explanation:

The expression (3x - 40)° (2x + 23)° represents the product of two angles, (3x - 40)° and (2x + 23)

(3x - 40)° (2x + 23)° = (3x - 40)(2x + 23)°

3x - 40)(2x + 23)° = 3x(2x + 23) - 40(2x + 23)°

3x(2x + 23) - 40(2x + 23)° = 6x² + 69x - 80x - 920

6x² + 69x - 80x - 920 = 6x² - 11x - 920

simplified expression of (3x - 40)° (2x + 23)° is 6x² - 11x - 920.


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The function t(x) = x + 6 determines how many cans of soup a food truck needs to stock, where x is the number of shifts the crew is going to work in the truck. The crew uses c(t(x)) to find the amount of money to spend on soup. The function c(x) = 2x + 4. Solve for how much money must be spent when the crew is going to work 4 shifts.(A. 24; B. 28; C. 30; D. 34)

Answers

Answer:

Option A is correct.

The amount of money must be spent when the crew is going to work 4 shifts is, 24

Step-by-step explanation:

Given the function:t(x) = x+6 .....[1] ; where x represents the number of shifts the crew is going to work in the truck.

Also, the crew uses c(t(x)) which  represents the amount of money to spend on soup.

The function is given as:

c(x) = 2x + 4               .....[2]

To find c(t(x)) i.e, the money must be spent when the crew is going to work 4 shifts.

⇒ x = 4

First substitute the value of x in [1] to find t(x);

t(4) = 4+6 = 10

Then;

For x=4 ,

c(t(4)) = 2(t(4)) +4                   [Using equation [2]]        

Substitute the value of t(4) = 10 we have;

c(t(4)) = 2(10) +4 = 20 + 4 = 24

Therefore, the amount must be spent when the crew is going to work 4 shifts is, 24




First, you have to solve t(x) when x=4, because the crew is working 4 scripts.    Which is t(x)=4+6                                 
t(x)=10
Then, you plug in t(x) to c(x).
c(x)=2(10)+4
c(x)=24

What are the solutions of the equation below
(x-2)(x+9)=0

Answers

Answer: {2, -9}

Step-by-step explanation: Think of these two binomials, x -2 and x + 9,

as two numbers that are multiplying together to equal zero.

In order for two numbers to multiply together to equal zero,

either one number or the other number must equal zero.

So for two binomials to multiply together to equal zero,

either one binomial or the other binomial must equal zero.

So we can split this problem up into two parts.

If (x - 2)(x + 9) = 0, then either x - 2 = 0 or x + 9 = 0.

On the left, add 2 to both sides and we have x = 2.

On the right, subtract 9 from both sides and we have x = -9.

For our final answer we use set notation.

So our answer is {2, -9}.

Answer:

2 and -9

Step-by-step explanation:

x-2=0

x=2

x+9=0

x=-9

Write and solve an inequality for x.

Answers

x + 2 > 5

x > 3

Answer is the 2nd option

x + 2 > 5; x > 3

it is c im 100% sure

a rectangle has a length that is nine feet less than four times its width. Its area is 90 ft. Algebraically determine the length of its width and length. Show work

Answers

Ok... after much confusion, I've come to the conclusion that you must have written the question wrong and it's actually the perimeter that is 90 feet so that's how I'm going to work it...

Width = w
Length = 4w - 9

P = 2w x 2L
90 = 2w + 2(4w - 9)
90 = 2w + 8w - 18
90 = 10w - 18
108 = 10w
108/10 = w
10 4/5 = w

Width is 10 4/5 ft

Length = 4w - 9
L = 4(10 4/5) - 9
L = 43 1/5 - 9
L = 34 1/5 ft

Length 34 1/5 ft  Width 10 4/5 ft or
Length 34.2 ft and width 10.8 ft

What are the lengths of the legs of a right triangle in which one acute angle measures 19° and the hypotenuse is 15 units long?a) 9 units, 12 units
b) 11 units, 10.2 units
c)4.9 units, 15.8 units
d)4.9 units, 14.2 units
e)5.2 units, 14.1 units

Answers

The length of the legs of a right triangle  in which one acute angle measures 19° and the hypotenuse is 15 units are 4.9 units and 14.2 units.

What is a right angle triangle?

A right angle triangle has one of its angles as 90 degrees. The sides can be found using pythagoras theorem or trigonometric ratios.

Therefore,

sin 19 = opposite / hypotenuse

sin 19  = h / 15

cross multiply

h = 15 sin 19

h = 4.88352231686 = 4.9 units

Hence,

cos 19 = adjacent / hypotenuse

cos 19 = x / 15

cross multiply

x = 15 cos 19

x = 14.182778634 = 14.2 units

Therefore, the other  legs are 4.9 units and 14.2 units.

learn more on right triangle here: brainly.com/question/1478228

#SPJ5

Can someone show me how to solve this? A boat took 5 hours to travel 60km up a river, against the current. The return trip took 3 hours. Find the speed of the boat in still water and the speed of the current.

Answers

Yes, I can.

And even though you haven't asked to be shown how to do it,
I'll go ahead and do that too:

Call the speed of the boat (through the water) 'B'.
Call the speed of the current (the water) 'C'.

When the boat is going 'up' the river, against the current,
his speed past the riverbank is (B - C).

When the boat is going 'down' the river, the same way as the current,
his speed past the riverbank is (B + C).

The problem says it took him 5 hours to travel 60 km against the current.
Distance = (speed) x (time)
60 km = (B - C) x (5 hours)

The problem also says it took him 3 hours to return.
The distance to return is the same 60 km.
The other direction is the same direction as the current,
so his speed on the return is (B + C).
Distance = (speed) x (time)
60 = (B + C) x (3)

Now we have two equations, so we can find 'B' and 'C'.

5B - 5C = 60
3B + 3C = 60

Multiply each side of the first equation by 3, and
multiply each side of the second equation by 5:

15B - 15C = 180
15B + 15C = 300

Add the second equation to the first one:

30B = 480
B = 480/30 = 16 km per hour.

Subtract the second equation from the first one:

-30C = -120
C = -120/-30 = 4 km per hour.

The speed of the boat through the water (B) is 16 km per hour.
The speed of the water past the riverbank is 4 km per hour.

Check:

-- When the boat is going along with the current, his speed past the riverbank
is (16 + 4) = 20 km per hour. In 3 hours, he covers (3 x 20) = 60.

-- When the boat is going against the current, his speed past the riverbank
is (16 - 4) = 12 km per hour.  In 5 hours, he covers (5 x 12) = 60 km.

yay !