Question 1: Hypothesis and Data CollectionFill the balloon with water until it is the size of a golf ball, and tie a knot in the end. Make sure there are no air bubbles in the balloon. In the plastic container, mix the plaster of Paris powder with water until it is as thick as yogurt, and then press the balloon into the center. One-third of the balloon should be below the surface of the plaster. Set the container aside until the plaster sets.

Part A
In this experiment, you will place the container in the freezer. What do you think will happen?

Answers

Answer 1

Answer:

Hypothesis: When the container with the balloon and plaster of Paris is placed in the freezer, the water inside the balloon will freeze and expand as it turns into ice. As the water freezes, it will exert pressure on the plaster, causing the plaster to crack or deform. The extent of cracking or deformation may depend on the strength and thickness of the plaster.

Part B of the experiment would typically involve conducting the experiment and observing the actual outcome to confirm or reject the hypothesis.

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A stone is dropped from a tower 100 meters above the ground. The stone falls past ground level and into a well. It hits the water at the bottom of the well 5.00 seconds after being dropped from the tower. Calculate the depth of the well. Given: g = -9.81 meters/second2.

Which contributes to acid rain? A. solar power

B. burning fossil fuels

C. nuclear power

D. hydroelectric power

Answers

The answer is D. hydroelectric power

A car of mass 1330 kg is traveling at 28 m/s. The driver applies the brakes to bring the car to rest over a distance of 79 m. Calculate the force acting on the car.

Answers

you could use SUVAT to work out the deceleration and then use F=ma

S= 79m U=28m/s V=0m/s A=? T=n/a

V^2 = U^2 + 2AS so 0 = 28^2 + 158A so -158A = 784

A= 4.962 (3dp)

so F = ma = 4.962 *1330 = 6599.494N (3dp)

Describes how a simple machine can make work easier?

Answers

simple machines such as ramps lessen the moment required to do work. if a triangle has a base of 5 and the height is 7, a ramp would make the hypotenuse of this triangle lessoning the total distance. using a²+b²=c² 25+49=c² 74≈8.6 and it is obvious that 8.6 is less than 12 in every unit. other simple machines such as pulleys make it lighter making it simply easier for an object to be lifted.

Which of the following conditions creates the largest waves? A.
slow-moving wind over smooth water

B.
slow-moving wind over choppy water

C.
fast-moving wind over smooth water

D.
fast-moving wind over choppy water

Answers

D because choppy water is already a little bit of wave action and then the wind adds a lot of speed to the waves and height to the waves to meek the best waves. Hope this helped.

I believe that the correct answer is D.) Fast moving wind over choppy water.

_______________________________________________________

My reason being is because the water is already moving and crashing against it's self plus the rock , so now that the wind is blowing against it , it's going to get worse.

i really hope that this helps you out a lot.

A 400 kg object is sitting at rest at the top of a hill that is 30.0m high and 80.0m long measured along the hill . If there is no friction ,how fast will the object be going at the bottom of the hill?

Answers

The object be going at the bottom of the hill with velocity 7.75 m/s.

What is velocity?

When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.

Given in the question a 400 kg object is sitting at rest at the top of a hill that is 30.0 m high and 80.0 m long measured along the hill . If there is no friction, velocity with which object be going at the bottom of the hill,

θ =sin^-1(30/80)

θ =22

F = 400 g sin(22) = 150 N

F = ma

150 = 400 a

a = 0.375 m/s²

v² - u²= 2 a s

v² - 0 = 2 x 0.375 x 80

v = 7.75 m/s

The object be going at the bottom of the hill with velocity 7.75 m/s.

To learn more about velocity refer the link:

brainly.com/question/18084516

#SPJ2

theater=sin^-1(30/80)
theater=22
F=400gsin22=150N
F=ma
150=400a
a=0.375ms^-2
v^2-u^2=2as
v^2-0=2x0.375x80
v=7.75ms^-1

If 20 beats are produced within one second, which of the following frequencies could possibly be held by two sound waves traveling through a medium along a common path at the same time? A. 38 Hz and 63 Hz
B. 22 Hz and 42 Hz
C. 47 Hz and 55 Hz
D. 18 Hz and 26 Hz

Answers

Answer:

B. 22 Hz and 42 Hz

Explanation:

The beat is an interference pattern which occurs when two waves of slightly different frequencies meet each other. The beat is heard as a periodic variation, whose frequency (called beat frequency) is equal to the absolute value of the difference between the frequencies of the individual waves:

$f_B = |f_1-f_2|$

In this problem, we are told that 20 beats per second are produced, so the beat frequency is

$f_B = 20 s^(-1) = 20 Hz$

Therefore, we must find the two waves which have a difference in frequency equal to this value, 20 Hz. Let's see each choice:

A. 38 Hz and 63 Hz --> $f_B = |38 Hz-63 Hz|=25 Hz$ --> NO

B. 22 Hz and 42 Hz --> $f_B = |22 Hz-42 Hz|=20 Hz$ --> YES

C. 47 Hz and 55 Hz --> $f_B = |47 Hz-55 Hz|=8 Hz$ --> NO

D. 18 Hz and 26 Hz --> $f_B = |18 Hz-26 Hz|=8 Hz$ --> NO

So, the correct choice is

B. 22 Hz and 42 Hz

The right answer for the question that is being asked and shown above is that: "B. 22 Hz and 42 Hz." If 20 beats are produced within one second, the frequencies that could possibly be held by two sound waves traveling through a medium along a common path at the same time is B. 22 Hz and 42 Hz

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