Which describes a spontaneous reaction? a. Positive ΔH
b. Negative ΔH
c. Positive ΔG
d. Negative ΔG
e. Positive ΔS

Answers

Answer 1
Answer: C. ) Negative Delta G is the answer that describes a spontaneous reaction
Answer 2
Answer: The answer is D
For Delta G the negative number is always spontaneous because it is less than 0

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What is the percent by mass of magnesium sulfate in MgSO4 · 7H2O?

Answers

ANSWER - 48.83%

Mg - 24.31
S - 32.07
O - 16x4 - 64
ADD ALL TOGETHER = 120.38

H - 1.01x2 - 2.02
O - 16
TOTAL = 18.02x7 = 126.14

ADD 120.38 to 126.14 = 246.52
last part divide MgSO4 by total compound mass 
120.38/246.52 then multiply by 100 = 48.831

Answer:

48.83

Explanation:

Edg

What is the chemical name for Fe(HCO3)2

Answers

The answer is Iron(II) Hydrogen Carbonate. It can also be known or referred as Ferrous Hydrogen Carbonate or even Iron(II) Bicarbonate. The known formula for this chemical is Fe(HCO3)2. The Molar Mass of this chemical is known as 177.8787. Here are some chemical reactions that may be equivalent to this chemical:  FeCO3 + H2CO3 = Fe(HCO3)2; or Fe(HCO3)2 = FeCO3↓ + CO2 + H2O; or Fe(HCO3)2 + 2HNO3 = Fe(NO3)2 + 2H2O + 2CO2

The chemical name for Fe(HCO₃)₂ is iron(II) bicarbonate.

Iron (II) compounds typically form coordination complexes with ligands that have a higher affinity for binding to the iron ion. Bicarbonate is a relatively weak ligand and is more commonly found as a component of soluble salts, such as sodium bicarbonate (NaHCO3) or potassium bicarbonate (KHCO3).

In this compound, the iron ion has a +2 charge, and the bicarbonate ion (HCO3-) has a -1 charge. When these ions combine, the resulting compound is named accordingly with the Romannumeral (II) to indicate the iron ion's charge.

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Given the balanced equation representing a reaction:Fe(s) + 2HCl(aq) → FeCl2(aq) + H2(g)
This reaction occurs more quickly when powdered iron is used instead of a single piece of iron of the same mass because the powdered iron
(1) acts as a better catalyst than the single piece of iron
(2) absorbs less energy than the single piece of iron
(3) has a greater surface area than the single piece of iron
(4) is more metallic than the single piece of iron

Answers

Answer: Option (3) is the correct answer.

Explanation:

One of the important factor on which rate of reaction depends is surface area. That is, when a compound is crushed into powdered form then there will be increase in surface area of the compound.

Hence, now more number of particles can interact, therefore, there will be increase in rate of reaction.

Thus, we can conclude that reaction occurs more quickly when powdered iron is used instead of a single piece of iron of the same mass because the powdered iron has a greater surface area than the single piece of iron.

Reactant X contains 199.3 J of chemical energy. Reactant Y contains 272.3 J of chemical energy. Product W contains 41.9 J of chemical energy. If the reaction loses 111.6 J of chemical energy as it proceeds, how much chemical energy must product Z contain? 318.1 J 429.7 J 541.3 J 625.1 J

Answers

Answer : The correct option is, 318.1 J

Solution :

The given chemical reaction will be,

X+Y\rightarrow W+Z+Energy

In this reaction, X and Y are the reactants and W and Z are the products.

As we know that the energy remains conserved during the chemical reaction.

So,

Sum of energy of product = Sum of energy of reactant

W+Z+Energy=X+Y\n\n41.9J+Z+111.6J=199.3J+272.3J\n\nZ=318.1J

Therefore, the amount of chemical energy of product Z contain will be, 318.1 J

Answer:

318.1 J

Explanation:

The reaction given is:

X + Y → W + Z

The chemical energy of the reaction (ΔU), is the variation of the chemical energy, so is the chemical energy of the products (UW and UZ) less the chemical energy of the reactants (UX and UY).

If the reaction loses the chemical energy, it must be negative, and the chemical energy that a substance contains, is positive.

ΔU = (UW + UZ) - (UX + UY)

-111.6 = (41.9 + UZ) - (199.3 +272.3)

-111.6 = 41.9 + UZ - 471.6

- UZ = - 429.27 + 111.6

-UZ = - 318.1

UZ = 318.1 J

When compared with the energy of an electron in the first shell of a carbon atom, the energy of an electron in the second shell of a carbon atom is(1) less(2) greater(3) the same

Answers

When compared with the energy of an electron in the first shell of a carbon atom, the energy of an electron in the second shell of a carbon atom is \boxed{\left( {\text{2}} \right){\text{ greater}}}.

Further explanation:

Quantum numbers:

Quantum numbers govern the size, energy, shape, and orientation of an orbital. The four quantum numbers are as follows:

1. Principal Quantum Number (n): It denotes the principle electron shell. The values of n are positive integers (1, 2, 3,…).

2. Angular Momentum Quantum Number (l): It represents the shape of an orbital. The value of l is an integer from 0 to (n-1).

3. Magnetic Quantum Number\left( {{m_l}} \right): This quantum number represents the orientation of the orbital in space. The value of {m_l}lies between –l to +l. The formula to calculate the value of {m_l} is as follows:

{m_l} =  - l,( - l + 1),.....,0,1,2,.....,(l - 1),l

Therefore, the total number of {m_l} values for a given value of l is 2l+1.

4. Electron Spin Quantum Number({m_s}): It represents the direction of the electron spin. Its value can be + (1)/(2)or- (1)/(2).

The formula to calculate the energy of an electron in an atom is as follows:

{{\text{E}}_{\text{n}}} = \frac{{ - 13.6{{\text{Z}}^2}}}{{{{\text{n}}^{\text{2}}}}}{\text{eV}}                           …… (1)

Here,

E is the energy of an electron.

Z is the atomic number of atom.

n is the principal quantum number.

Calculation of energy of an electron in the first shell of carbon atom.

The value of Z is 6.

The value of n is 1.

Substitute these values in equation (1) to calculate the energy of electron in the first shell.

\begin{aligned}{{\text{E}}_2}&=\frac{{ - 13.6{{\left( 6 \right)}^2}}}{{{{\left( 1 \right)}^{\text{2}}}}}{\text{eV}}\n&=\boxed{-489.6\;{\text{eV}}}\n\end{aligned}

Calculation of energy of an electron in the second shell of carbon atom.

The value of Z is 6.

The value of n is 2.

Substitute these values in equation (1) to calculate the energy of an electron in the second shell.

\begin{aligned}{{\text{E}}_1}&=\frac{{-13.6{{\left( 6 \right)}^2}}}{{{{\left( 2 \right)}^{\text{2}}}}}{\text{eV}\n&=\boxed{-122.{\text{4 eV}}}\n\end{aligned}

The negative sign in the energy of the electron in both the shells indicates that the electron is bound to the nucleus of an atom. So the energy of electron in the second shell of carbon atom is greater than its energy in the first shell of carbon atom and therefore option (2) is correct.

Learn more:

1. Which transition is associated with the greatest energy change? brainly.com/question/1594022

2. Describe the spectrum of elemental hydrogen gas: brainly.com/question/6255073

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Atomic structure

Keywords: energy of electron, n^2, Z^2, -13.6, n, Z, -122.4 eV, -489.6 eV, 6, 1, 2, first shell, second shell.

The answer is (2) greater. The energy of an electron will increase when the number of valence shell increases. So the energy of an electron in the second shell of a carbon atom is greater than in the first shell.

How do you find the name of the chemical formula Pb3N4 (the 3 and 4 are subscripts)

Answers

This is a salt because there is a cation and an anion.  Because lead can have multiple charges, its charge must correspond to the charge of the anion.  The charge on the N is -3, so the 4 N's equal a total charge of -12. Therefore, the total charge of the 3 Pb's must be 12, so each lead should have a charge of +4.  So the name of the compound is Lead (IV) Nitride. 

Final answer:

The name of the chemical compound Pb3N4 is Lead (IV) Nitride. The number of atoms of each element in the compound is represented by the subscript numbers, and the '-ide' suffix is used for the non-metal (Nitrogen). The Roman numeral indicates the oxidation state of Lead.

Explanation:

The chemical formula Pb3N4 corresponds to a compound made up of Lead (Pb) and Nitrogen (N). The subscript numbers (3 and 4) denote the number of atoms from each element present in the compound. Considering that Lead is a metal and Nitrogen is a non-metal, we use the '-ide' suffix for the non-metal in the name of the compound. Therefore, the name of Pb3N4 is Lead (IV) Nitride. The Roman numeral (IV) indicates the oxidation state of Lead in the compound.

Learn more about Chemical Nomenclature here:

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