Use the REMAINDER THEOREM to explain whether or not (x-2) is a factor of F(x)=x^4-2x^3+3x^2-10x+3

Answers

Answer 1
Answer: (P(x))/(R(x))|(D(x))/(Q(x))

\frac{x^4-2x^3+3x^2-10x+3}{}|\frac{x-2}{}

(x^4-2x^3+3x^2-10x+3)/(-x^4+2x^3)|(x-2)/(x^3)

(3x^2-10x+3)/(-3x^2+6x)|(x-2)/(x^3+3x)

(-4x+3)/(4x-8)|(x-2)/(x^3+3x-4)

\frac{-5}{}|(x-2)/(x^3+3x-4)

\boxed{\boxed{(x^4-2x^3+3x^2-10x+3)/(-5)|(x-2)/(x^3+3x-4)}}

R(x)=-5

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What are the solutions of x^2 - 5x+7 = 0 ?​

Answers

Answer:

C.

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Algebra I

  • Standard Form: ax² + bx + c = 0
  • Quadratic Formula: x=(-b\pm√(b^2-4ac) )/(2a)

Algebra II

  • Imaginary Roots: √-1 = i

Step-by-step explanation:

Step 1: Define

x² - 5x + 7 = 0

Step 2: Identify Variables

a = 1

b = -5

c = 7

Step 3: Find solutions

  1. Substitute [Quad Formula]:                    x=(5\pm√((-5)^2-4(1)(7)) )/(2(1))
  2. Evaluate Exponents:                               x=(5\pm√(25-4(1)(7)) )/(2(1))
  3. Evaluate Multiplication:                          x=(5\pm√(25-28) )/(2)
  4. Evaluate Subtraction:                             x=(5\pm√(-3) )/(2)
  5. Factor:                                                     x=(5\pm√(-1) √(3) )/(2)
  6. Simplify:                                                  x=(5\pm i√(3) )/(2)

The solutions to the equation x² - 5x + 7 = 0  are:

x = (5 + i√3) / 2 or x = (5 - i√3) / 2

Option C is the correct answer.

We have,

To find the solutions of the quadraticequation x² - 5x + 7 = 0, we can use the quadraticformula:

x = (-b ± √(b² - 4ac)) / (2a)

For the given equation, the coefficients are:

a = 1

b = -5

c = 7

Substituting these values into the quadraticformula,

x = (-(-5) ± √((-5)² - 4(1)(7))) / (2(1))

Simplifying further:

x = (5 ± √(25 - 28)) / 2

x = (5 ± √(-3)) / 2

Since the discriminant (the value inside the square root) is negative, √(-3) is imaginary, meaning there are norealsolutions to this quadratic equation.

The solutions exist in the complex number system.

So,

√-1 = i

x = (5 ± i√3) / 2

This can be written as,

x = (5 + i√3) / 2

and

x = (5 - i√3) / 2

Thus,

The solutions to the equation x² - 5x + 7 = 0  are:

x = (5 + i√3) / 2 or x = (5 - i√3) / 2

Learn more about solutionsofequations here:

brainly.com/question/545403

#SPJ6

What is the slope of any line parallel to the line8x + 9y = 3 in the standard (x,y) coordinate plane?

Answers

The slope of any line parallel to that line is -8/9
parallel -8/9 hope that helpd

Show how to apply the order of operation rules as you simplify the following expression.|-5| – 45 ÷ 3

Answers

|-5| - (45)/(3) 

5- (45)/(3)    Simplify \ (45)/(3) \ to \ 15

5-15 

\boxed{\boxed{=-10}}   Solution
There arnt really any steps
|-5|-45/3=-10

How many angles does a dodecagon have

Answers

A\ dodecagon\ has\ 12\ angles.\n\nSum\ of\ the\ angles\ is\ (12-2)\cdot 180^0=10\cdot180^0=1800^0
A dodecagon has 12 angles. 'Do' means two and 'Deca' means ten. That's how i got it.

Identify the series as geometric or arithmetic.
2, 4/3, 8/9, 16/27

Answers

Hello,

((4)/(3))/(2)=(4)/(6)=(2)/(3)

((8)/(9))/((4)/(3))=(8*3)/(9*4)=(2)/(3)

((16)/(27))/((8)/(9))=(16*9)/(27*8)=(2)/(3)

The sequence is geometric .
(a serie is a sum)





Write the polynomial in standard form. Give the degree of the polynomial. Classify the polynomial byits degree.

a. 7x-14x^4 +19x^3 +26x^5-18

Standard form:

degree:

name based on degree:

Answers

Answer:

Sure, I'd be happy to help!

The polynomial you provided is:

7x - 14x^4 + 19x^3 + 26x^5 - 18

To put this polynomial in standard form, we need to factor it. Here's the factored form of the polynomial:

7x(1 - 14x^3 + 19x^2 + 26x^4) - 18

Now, we can see that the degree of the polynomial is 4, so it is a quartic polynomial.

Based on the degree of the polynomial, we can classify it as a quartic polynomial.

Step-by-step explanation: