Joe has been keeping track of his cellular phone bills for the last two months. The bill for the first mont was $38.00 for 100 minutes of usage. The bill for the second month was $45.50 for 150 minutes of usage. Find a linear equation that gives the total monthly bill based on the minutes of usage

Answers

Answer 1
Answer: The problem here is that you need to find what is the monthly fee for the telephone + the fee per minute.

Data we are looking for:

x - subscription plan
y - rate per minute

1. Finding the monthly fee (x) + rate per minute (y)

x + 150y = 45.50
x + 100y = 38.00
you have to deduct those equatations (x - x = 0, 150y - 100y = 50y, 45.5 - 38 = 7.5)

- finding rate per minute:
50y = 7.50
5y = 0.75
y = 0.15

- finding monthly fee
x + 150 *0.15 = 45.50
x = 45.50 - 22.50
x = 23.00

Looking at the data above you can see that no matter for how many minutes you use your phone you have to pay 23$. For every minute you spend talking the fee is 0.15$

That is why (z) the total amount you have to pay consist of 23 (subscription) + 0.15y (15c per minute):

z = 23 + 0.15y

Add a comment if sth is not clear
Answer 2
Answer:

Answer:

Step-by-step explanation:

We can make 2 simultaneous equations and solve for the set fee

and the per minute charge:

 

Let x = fixed monthly rate

Let m = per minute charge

 

x + 100m = 135    {equation 1}

x + 500m = 375    {equation 2}

 

subtract equation 1 from equation 2

 

400m = 240

m = 0.6

 

substitute that back into equation 1 or 2 to solve for x.

Using equation 1

 

x + 100(.6) = 135

x + 60 = 135

x = 75

 

The fixed monthly rate is $75

The per minute charge is $0.6

*****************************

If y is the total cost for a month and x is the

number of minutes used the equation is:

 

y = 0.6x + 75


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Please help me ASAP!!!!

Answers

Answer:

what exactly is your question

for his long distance phone service, Pablo pays an eight dollars monthly fee +6 cents per minute. Last month, Pablo's long-distance bill was $19.46. For how many minutes was Pablo billed?

Answers

He was billed for 191 minutes. $19.46-$8 fee=$11.46/6=191

Write the equation of a parabola, in standard form, that goes through these points: (0, 3) (1, 4) (-1, -6)

Answers

Hello,

P:y=ax²+bx+c is the equation.

(0,3)∈P==>3=a*0+b*0+c==>c=3
(1,4)∈P==>4=a+b+3==>a+b=1 (1)
(-1,-6)∈P==>-6=a-b+3==>a-b=-3 (2)

(1)+(2)==>2a=-2==>a=-1
(1)==>b=1-(-1)==>b=2

y=x²+2x+3 
y=(x+1)²+2
Vertex is (-1,2)


"The graph of F(x), shown below, resembles the graph of G(x) = x2, but it has been changed somewhat. Which of the following could be the equation of F(x)?

Answers

G(x)=x²
The graph  has moved to the right 4 units, therefore the new graph will be:
H(x)=(x-4)²

It has also move 4 units up, therefore the new graph will be:
F(x)=(x-4)²+4

Answer: 
F(x)=(x-4)²+4

y = (x - 4)² + 4

or y = x² - 8x + 20

Further explanation

Transformation of a graph is changing the shape and location of a graph.

There are four types of transformation geometry: translation (or shifting), reflection, rotation, and dilation (or stretching).  

  • In this case, the transformation is shifting horizontally or vertically.
  • Translation (or shifting): moving a graph on an analytic plane without changing its shape.
  • Vertical shift: moving a graph upwards or downwards without changing its shape.
  • Horizontal shift: moving a graph to the left or right downwards without changing its shape.  

In general, given the graph of y = f(x) and v > 0, we obtain the graph of:

  • \boxed{ \ y = f(x) + v \ } by shifting the graph of \boxed{ \ y = f(x) \ } upward v units.
  • \boxed{ \ y = f(x) - v \ } by shifting the graph of \boxed{ \ y = f(x) \ } downward v units.

That's the vertical shift, now the horizontal one. Given the graph of y = f(x) and h > 0, we obtain the graph of:

  • \boxed{ \ y = f(x + h) \ } by shifting the graph of \boxed{ \ y = f(x) \ } to the left h units.
  • \boxed{ \ y = f(x - h) \ } by shifting the graph of \boxed{ \ y = f(x) \ } to the right h units.

Hence, the combination of vertical and horizontal shifts is as follows:

\boxed{\boxed{ \ y = f(x \pm h) \pm v \ }}

The plus or minus sign follows the direction of the shift, i.e., up-down or left-right

Given:\boxed{ \ g(x) = x^2 \ becomes \ f(x) = ? \ }

In the graph, notice the shifting of the vertex from (0, 0) to (4, 4).

From this, we can describe that from g(x) to f(x) there has been a shift to the right 4 units and upward 4 units.

Let us construct f(x) from g(x).

\boxed{ \ g(x) = y = x^2 \ } \rightarrow \boxed{ \ f(x) = y = (x + h)^2 + v \ }

We set h = -4 and v = +4 and we get the equation f(x) as

\boxed{\boxed{ \ f(x) = (x - 4)^2 + 4 \ }}

Let's expand it if we want to represent a standard form of a quadratic function, like this:

\boxed{ \ f(x) = x^2 - 8x + 16 + 4 \ }

\boxed{\boxed{ \ f(x) = x^2 - 8x + 20 \ }}

Conclusion

The graph of f(x) is drawn by the combination of shifting the graph of g(x) to the right 4 units and upward 4 units.  

Learn more  

  1. Transformations that change the graph of (f)x to the graph of g(x) brainly.com/question/2415963
  2. The similar problem brainly.com/question/1369568
  3. Determine the coordinates of the image of a point after the triangle is rotated 270° about the origin brainly.com/question/7437053

Keywords: transformations, the graph of f(x), resembles, g(x) = x², f(x) = (x - 4)² + 4, y = x² - 8x + 20, translation, shifting, right, upward, horizontal, vertical

In quadrilateral ABCD, angle A=(4x+10), Angle B=108, angle C= 3x, and angle D=67. Solve for x.

Answers

as the sum of angels in quadrilateral = 360°
so , A+B+C+D = 360
hence, x = 25

Which statement is true about the equation fraction 3 over 4z − fraction 1 over 4z + 1 = fraction 2 over 4z + 1?It has no solution.
It has one solution.
It has two solutions.
It has infinitely many solutions.

Answers

Answer:

It has no solution.

Step-by-step explanation:

I just did the test and got this right (as a matter of fact, I got 100% ^^)

It has no solution because no matter how much you multiply the two fractions to the left, it will always equal to 1/2, and 2/4, no matter how many times you multiply it, will always equal to 1/2 as well. Therefore, since those two cancel out, and the leftover numbers in the equation aren't the same, there is no possible solution for this equation.  

The solution is Option A.

The equation has no solutions

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is

Substituting the values in the equation , we get

( 3/4z ) - ( 1/(4z+1 ) ) = 2/ (4z + 1 )   be equation (1)

Adding ( 1/(4z+1 ) )  on both sides of the equation , we get

( 3/4z ) = ( 2 + 1 ) / (4z + 1 )

On further simplification , we get

( 3/4z ) = 3/(4z + 1 )

Divide by 3 on both sides of the equation , we get

1/4z = 1/( 4z+1 )

Taking reciprocals on both sides of the equation , we get

4z = 4z + 1

Subtracting 4z on both sides of the equation , we get

1 ≠ 0

Hence , the equation has no solutions

To learn more about equations click :

brainly.com/question/19297665

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