At standard pressure when NaCl is added to water,the solution will have a

Answers

Answer 1
Answer:

Answer: lower freezing point and a higher boiling point than water

Explanation:

Addition of a non volatile solute leads to elevation in boiling point and depression in freezing point.

This increase in boiling point arises because particles of the non-volatile solute occupy the surface of solution due to which solvent particles can not escape out of the solution.  Hence, high amount of heat is required for the solute particles to escape out of the solution. Therefore, an increase in boiling point will occur.

Also as vapor pressure of solution becomes less, the freezing point gets depressed as freezing point is the temperature at which vapor pressure of solid becomes equal to the vapor pressure of solution.

Thus at standard pressure when NaCl is added to water,the solution will have a lower freezing point and a higher boiling point than water

Answer 2
Answer: lower freezing point and a higher boiling point than water 

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At what temperature will the following reaction happen spontaneously, given that ΔH=8.91×103J and ΔS= –219.20 J/K? CaSO4(s) + 2HCl(g) → CaCl2(s) + H2SO4(l)A) at 298 K
B) at 100 K
C) It is spontaneous at any temperature.
D) It is not spontaneous at any temperature.

Answers

Answer:

D) It is not spontaneous at any temperature.

Explanation:

Given reaction:

CaSO4(s) + 2HCl(g) → CaCl2(s) + H2SO4(l)

ΔH = +8.91*10³ J

ΔS = -219.20 J/K

The sign of the Gibbs free energy (ΔG) determines the spontaneity of a given reaction. ΔG is related to ΔH and ΔS as follows:

\Delta G = \Delta H-T\Delta S

A reaction is spontaneous only when ΔG is negative i.e. ΔG < 0

Under the given conditions:

ΔH > 0 ; ΔS <0 and ΔH > ΔS

i.e. ΔG = ('+' value) - T( '- 'value) = + value

Therefore, irrespective of the temperature, ΔG will always be positive

DG = DH - TDS 

For this reaction DH>0 and DS<0. So, d. the reaction is not spontaneous at any temperature.

During nuclear fission, great amounts of energy are produced froma. very small amounts of mass.
b. tremendous amounts of mass.
c. a series of chemical reactions.
d. particle accelerators.

Answers

The answer should be A.  It takes a very small amount of mass to produce a lot of energy which is displayed in Einstein's equation E=mc².  E is the amount of energy given off when some mass is converted into energy.  
E=the energy given off, m=the mass turned to energy (I think this is sometimes referred to as the mass defect), and c=the speed of light.  Nuclear reactions do not fallow the law of conservation of mass since some of the mass is converted into energy.

I hope this helps.  Let me know if anything is unclear.

Final answer:

In nuclear fission, great amounts of energy are produced from very small amounts of mass, as described by Einstein's mass-energy equivalence principle E=mc². The energy is derived from the conversion of a small amount of nuclear mass.

Explanation:

During the process of nuclear fission, large amounts of energy are actually released from very small amounts of mass. This is in accordance with Einstein's mass-energy equivalence principle expressed in his famous equation E=mc², where E represents energy, m is the mass, and c² is the speed of light squared. This equation depicts that even small amounts of mass can produce tremendous energy when speed of light is raised to power of two which is a very large number. Therefore, the correct answer to your question is Option A: very small amounts of mass.

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. Find the mass of 0.159 mol silicon dioxide.​

Answers

One mole of any element contains 6.022×10²³ atoms which is also called Avogadro number. The mass of  0.159 mole silicon dioxide.​ is 9.55g.

What is mole?

The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity of amount of substance. It measure the number of elementary entities of a given substance that are present in a given sample.

Mathematically,

mole =given mass ÷ Molar mass

First of all we find the molar mass of silicon oxide

Molar mass of silicon oxide= atomic mass of silicon+2×molar mass of oxygen

Molar mass of silicon oxide=28.0855+2×16

Molar mass of silicon oxide=60.08 g/mol

Substituting the values in fisrt equation we get

0.159 mol=given mass÷60.08 g/mol

0.159 mole x 60.08 g/mol=mass

9.55g=mass of silicon oxide

Therefore the mass of 0.159 mol silicon dioxide.​ is 9.55g.

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Answer:

9.55 grams of SiO2

Explanation:

If the mass you mean by grams:

0.159 mole x 60.08 g (Periodic table by adding both elements)

Cancel moles with moles (Original moles with the 1 mol at the bottom of the grams) and gives you:

9.55 grams of SiO2

When 0.2mol of calcium reacts with 880g of water 2.24L of hydrogen gas form at STP How would the amount of hydrogen produced change if the volume of water was decreased to 440mL 400g?

Answers

The amount of hydrogen produced does not change if the volume of water was decreased to 440mL 400g.

What is Mole?

The mole is an amount unit similar to familiar units like pair, dozen, gross, etc. It provides a specific measure of the number of atoms or molecules in a bulk sample of matter.

A mole is defined as the amount of substance containing the same number of atoms, molecules, ions, etc. as the number of atoms in a sample of pure 12C weighing exactly 12 g.

The reaction will be;

Ca(s) + 2 H₂O(l) → Ca(OH)₂(aq) + H₂ (g)

Since water is in excess, because 0.1 moles of calcium requires only 0.2 moles of water which is 3.6 g, therefore changing the mass of water used will not affect the amount of hydrogen gas produced since the amount of hydrogen gas produced depends on the amount of calcium used.

Therefore, The amount of hydrogen produced does not change if the volume of water was decreased to 440mL 400g.

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Answer:

The volume of hydrogen produced would be the same.

Balance the following equation. Then determine the mole ratio of Ca(OH)2:Al(OH)3.Al2(SO4)3 + Ca(OH)2 Al(OH)3 + CaSO4?
A) 2:3
B) 3:2
C) 1:2
D) 3:3
E) 1:1

Answers

Balanced equation:

Al2(SO4)3 +3 Ca(OH)2 ---> 2Al(OH)3 + 3CaSO4?

Check:
Left side: Al:2; [SO4]: 3; Ca: 3; [OH] 3*2 = 6

Rigth side: Al: 2; [OH]: 2*3 = 6; Ca:3; [SO4]: 3

Mole ratio of Ca(OH)2 : Al (OH)3

3 moles of Ca(OH)2: 2moles of Al(OH)3 = 3:2

Answer: Option B.

Electric current is _____. the continuous flow of atoms in a conductor the continuous flow of static electricity in a conductor the continuous flow of electric charges in a conductor a staggered flow of charges in a conductor

Answers

Answer: The correct answer is the continuous flow of electric charges in a conductor.

Explanation:

Electric current is defined as the continuous flow of electric charges through a conductor. Direction of the electric current is opposite to the flow of electrons. It is represented by a symbol 'I' and its S.I. unit is Amperes.

Its value depends on the voltage and resistance. The equation representing the relationship between current, voltage and resistance is given by Ohm's Law, which is:

V=IR

where,

V is the voltage

I is the current

R is the resistance

Hence, the correct answer is the continuous flow of electric charges in a conductor.

Electric current is: C) the continuous flow of electric charges in a conductor.

The movement or flow of electric charges across a conducting media, such as a metal wire, is known as electric current. The mobility of electrons within the conductor is what causes the flow of charges. The flow of electric charges in the majority of conventional electrical circuits is from the negative terminal, where extra electrons build up, to the positive terminal, where there are insufficient electrons.

It's crucial to understand that the passage of atoms in a conductor is not what constitutes electric current. While atoms may vibrate or move slightly within a conductor, the passage of electrons is the main movement in charge of electric current.

Static electricity does not continuously flow through a conductor, and neither does electric current. An imbalance of electric charges on a material's surface is referred to as static electricity, which normally doesn't entail a constant flow or movement of charges.

A staggered passage of charges in a conductor is not how electric current behaves either. Charges flow continuously, uniformly, and orderly through the conductor in a steady electric current.

In conclusion, electricity and electrical circuits are based on the continuous flow of electric charges, typically electrons, in a conductor. Electric current is defined as this flow.

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