How many atoms are in 3.50 moles of calcium (Ca)?
Answers
= 3.50 x 6.022*10^23
= 21.077 x 10 ^23
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If you have to prepare the reactants by dissolving 1.00 g of BaCl₂ and 1.00 g of NaOH in water,
(a) What is the limiting reactant?
(b) How many grams of Ba(OH)₂ are produced?
(c) If your experiment produced 0.700 g of Ba(OH)₂, what is the percent yield of Ba(OH)₂?
(d) Based on this percent yield, how much limiting reactant should be used to achieve the target Ba(OH)₂ theoretical yield?
Answers
Answer:
The answer to your question is:
a) BaCl2
b) 0.8208 g
c) yield = 85.3 %
d)
Explanation:
BaCl₂(aq) + NaOH(aq) ----> Ba(OH)₂(s) + 2NaCl(aq)
Data
a) 1 g of BaCl₂
1 g of NaOH
MW BaCl2 = 137 + (35.5x2) = 208 g
MW NaOH = 23 + 16 + 1 = 40 g
208 g of BaCl2 ------------- 1 mol
1 g of BaCl2 ------------- x
x = ( 1 x 1) / 208 = 0.0048 mol of BaCl2
40 g of NaOH ------------ 1 mol
1 g of NaOH ------------ x
x = (1 x 1) / 40
x = 0.025 mol of NaOH
The ratio BaCl2 to NaOH is 1:1 (in the equation)
But experimentally we have 0.0048 : 0.025, so the limiting reactant is BaCl2, because is in lower concentration.
b)
1 mol of BaCl2 -------------- 1 mol of Ba(OH)2
0.0048 mol --------------- x
x = (0.0048 x 1) / 1
x = 0.0048 mol of Ba(OH)2
MW Ba(OH)2 = 137 + 32 + 2 = 171 g
171 g of Ba(OH)2 -------------------- 1 mol
x -------------------- 0.0048 mol
x = (0.0048 x 171) / 1
x = 0.8208 g
c)Data
Ba(OH)2 = 0.700 g
% yield = 0.700 / 0.8208 x 100
% yield = 85.3
d)
Sorry, i don't understand this question
Answers
The chemical reaction is
C3H8O + (9/2) O2 = 3CO2 + 4H2O
Theoretical amount of oxygen needed = 0.1 mol of propanol ( 4.5 mol O2 / 1 mol propanol) = 0.45 mol
The amount of oxygen used in mol can be calculated using the ideal gas equation
PV = nRT
@room conditions
P = 1 atm
T = 25C ~ 298 K
R = 0.08205 mol – L/ atm – K
1 dm3 = 1 L
(1 atm) (12 L) = n (0.08205)*(298K)
n = 0.49 mol O2
Excess O2 = 0.49 – 0.45 = 0.04 mol O2
Amount of CO2 produced = 0.1 mol propanol (3 mol CO2/ 1 mol propanol) = 0.3 mol
Amount of H2) produced = 0.1 mol propanol (4 mol H2O/ 1 mol propanol) = 0.4 mol
TOTAL amount of gases = 0.04 + 0.3 + 0.4 = 0.74 mol
Therefore
V = (0.74*0.08205*298)/1
V = 18.0 dm3, the answer is letter D
Answer:The the correct answer is option (A).
Explanation:
12 L of oxygen gas burns 0.10 mol of propanol.(1 L = 1)
According to reaction, 2 moles of propanol gives 6 moles of then, 0.10 moles of propanol will give:
moles of
that is 0.30 mol.
The final volume of the gas evolved after the reaction can be determined by Ideal gas equation. Since, the reaction is taking place at room temperature the value of pressure and temperature will be:
At room temperature:
Pressure = 1 atm
Temperature , T= 293 K
The closest answer from the given options is option (A) that is 7.20
Answers
= 952 g (NH4)2CO3 / 1750 mL x 100
= 0.544 x 100
(%m/v) = 54.4 g /mL or 54.4% concentration of ammonium carbonate
solution
B. Sand
C. Copper
D. Zinc
Answers
For example if Nitrogen and Hydrogen reacted, and they were both gases, the reaction would be homogeneous.
Sand is a compound, so therefore not a mixture.
Copper and Zinc are both elements, so again, not a mixture.
Bronze is an alloy, a mixture of Copper and Tin. As Copper and Tin are both solid (metals), we can say this mixture is homogeneous.
The answer is (A) Bronze.
The correct answer is:
A. Bronze
Explanation:
Bronze is an alloy consisting principally of copper, generally with about 12% tin and often with the extension of other metals and sometimes non-metals or metalloids such as arsenic, phosphorus or silicon.Both copper and tin are solid.
A homogeneous mixture is a solid, liquid, or gaseous mixture that has the same proportions of its components throughout any given sample. Conversely, a heterogeneous mixture has elements whose dimensions vary completely the sample. Water itself is an example of a homogeneous mixture. It often includes dissolved metals and gases, but these are removed throughout the water.
Answers
Acid Rain is formed when chemicals in the air get into rain and up the acidity levels!!!!!!
Hope this helps guys!
Answer:
yes acid rain
Explanation: