PLEASE HELP. A substance decays according the the equation ae^-0.0025t, where t is in minutes. Find the half life of the substance. Round to the nearest tenth.

Answers

Answer 1
Answer:
First of all, that's not an equation.  An equation needs an 'equals' sign ( = ),
so you need something like 

               Amount present = a e^-0.0025t .

                                   'a' = amount present when t = 0 .

The half-life is the time it takes for the original amount to decay to half of it.

That's just 't' when                      e^-0.0025t  =  1/2

Take the natural log of each side:    -0.0025t  =  ln(0.5)

Divide each side by  -0.0025 :        t = ln(0.5) / (-0.0025) =

                                                     (-0.69315) / (-0.0025) =

                                                   t  =  277.26 minutes

                                                    ( 4hrs 37min 15.5sec)

Rounded to nearest tenth:  t = 277.3 minutes .



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A crane lifts 400 N crate full of baked beans 15m how much work is done by the crane ?

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Lookattheattachedpicture

Hope itwillbehelpfultoyou..

A weight is connected to a spring that is suspended vertically from the ceiling. If the weight is displaced downward from its equilibrium position and released, it will oscillate up and down.If air resistance is neglected, will the total mechanical energy of the system (weight plus Earth plus spring) be conserved?

A. Yes
B. No

Answers

Answer:

Yes

Explanation:

Neglecting air resistance, the total mechanical energy of the system would be conserved because the two forces acting on the weight are the spring force and the gravitational force, and both are conservative in nature.

Prior to determining the experimental design, a scientist typically? A. makes observations. B. forms a hypothesis. C. performs an experiment. D. predicts the result of an experiment.

Answers

Prior to determining the experimental design, a scientist typically forms a hypothesis. The answer is letter B. this is to prepare the scientist, the possible outcome of their research before the experimental design whether they are wrong or not.

If an alloyed guitar B string (147 Hz resonance) has an average diameter of .6 mm over an effective oscillating length of 65 cm, what is the tension in Newtons if the alloy is 10% aluminum and 90% copper? (assume the specific gravities of the metals are 2.6 and 8.9 grams per cubic centimeter, respectively)

Answers

Answer:

73.8 N

Explanation:

The total volume is,

V = (m_Al)/(P_Al) = (m_copper)/(P_copper)

=  (10m)/((100)(2.6)) = (90m)/((100)(8.9))

= 0.1396 m

The average  density is,

p = (m)/(V)

= (m)/(0.1396)

= 7.169 g/cm³

The linear mass density is,

μ = pπr²

= (7.169 x 10⁹) (π (0.3 x 10⁻³)²)

= 2.026 x 10⁻³ Kg/m

The fundamental mode of length is,

L =  λ/2

λ=2L

= 2 x 0.65

= 1.3 m

The speed of the wave is,

v = λf

= 1.3 m x 147 Hz

= 1.91 m/s

The tension is,

v =  √T/ц

T = ц v²

= 2.026 x 10⁻³)(1.91 m/s)²

= 73.769N

73.8N

1. A rifle with a longer barrel can fire bullets with a larger velocity than a rifle with a shorter barrel.

Answers

i dont believe so because thw longer the barrel the longer the bullet is inthe rifle shortening the force from the friction with the barrel so a rifle with a shorter barrel would be betterto use than one with a lomger barrel even though the longer barreled rifle may be more presice

Hi all! I’m struggling with solving this section in a physics test. Especially the last point.

Answers

Answer:

Explanation:

We should know that the gradient(slope) of a distance-time graph is the speed, and the gradient of a velocity-time graph is the acceleration.

a) Since the gradient from t=80 to 160 is 0, the speed is 0, indicating it is at rest.

b)To find the speed, we find the gradient of the graph at t=40. Since it is a straight line from t=40 to 60, we can do this simply by

Gradient = (200-120)/(60-40)=80/20=4 (This is an estimate since the graph is not clear, instead of t=40 and t=60, you can use any two points along that straight line (from about t=20 to 60))

c)The one on the right is the velocity graph, and the one on the left shows acceleration. We can know this by analysing some points. For example, and t=50, the right graph is about constant at 5, while the left one is 0. This would indicate that the left one shows the gradient of the right (gradient of a constant portion is 0). We can choose another place on the right graph, say t=60 to 80. The curve is decreasing. The left graph for this same time period is negative. This reaffirms our guess, since the gradient of a decreasing curve should be negative.

If you want to do it the other way around, you can analyse the left graph. From about t=15 to t=30 the graph is decreasing. Thus its slope should be negative. However, the right graph is positive for this period. This means that the right graph definately does not show the slope of the left.

When you learn about calculus and derivatives, these will become much clearer :)