Why isn't propyne call 1-propyne, but heptene is called 3-heptene

Answers

Answer 1

Answer:

Propyne has one triple bond between the two carbons HC≡C-CH₃ while heptene has one double bond between two carbons in the chain of the seven carbon atoms.

What are the steps for the IUPAC nomenclature?

The 1st step for the IUPAC name is to select the longest, most substituted carbon chain with a functional substituent chosen. Then the use of the primary suffix indicates the degree of saturation in the structure such as 'ane' or 'ene.

The 'ane' suffix is used for a singlebond while 'ene' suffix is used for a doublebond and 'yne' is used for triple bonds.

Then the identification of the secondary suffix indicates the functional substituent in the molecule which depends on the number of times the same functional substituent is repeated such as di, tri, tetra, etc.

In the structure of heptene, the double bond can be present between any two adjacent carbons. If the double bond is present at the third and 4th carbon then it can be named 3-heptene.

Learn more about IUPAC nomenclature, here:

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Answer 2

Answer: the formula for propyne is CH3C-CH and the formula for 1-propyne is CH-CCH3. So it is a matter of redundancy. :)

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Cuantas moléculas de oxigeno se producen por la descomposición de 28.5 g de H2O2 (masa molecular = 34.0g/mol) de acuerdo a la ecuación 2H2O2(l) → 2H2O(l)+O2(g)

Answers

The question is as follows: How many oxygen molecules are produced by the decomposition of 28.5 g of H2O2 (molecular mass = 34.0g / mol) according to the equation

2H2O2 (l) → 2H2O (l) + O2 (g)

Answer: There are $2.52 * 10^(23)$ molecules are produced by the decomposition of 28.5 g of $H_(2)O_(2)$ according to the equation $2H_(2)O(l) \rightarrow 2H_(2)O(l) + O_(2)(g)$ .

Explanation:

Given: Mass of $H_(2)O_(2)$ = 28.5 g

As moles is the mass of a substance divided by its molar mass. Hence, moles of $H_(2)O_(2)$ is calculated as follow.

$Moles = (mass)/(molarmass)\n= (28.5 g)/(34.0 g/mol)\n= 0.838 mol$

According to the given equation, 2 moles of $H_(2)O_(2)$ gives 1 mole of $O_(2)$ . So, moles of $O_(2)$ produced by 0.838 moles of $H_(2)O_(2)$ will be calculated as follows.

$Moles of O_(2) = (0.838 mol)/(2)\n= 0.419 mol$

This means that moles of $O_(2)$ produced is 0.419 mol.

As per the mole concept, 1 mole of every substance has $6.022 * 10^(23)$ molecules.

So, molecules of $O_(2)$ present in 0.419 mole are as follows.

$0.419 * 6.022 * 10^(23)\n= 2.52 * 10^(23)$

Thus, we can conclude that there are $2.52 * 10^(23)$ molecules are produced by the decomposition of 28.5 g of $H_(2)O_(2)$ according to the equation $2H_(2)O(l) \rightarrow 2H_(2)O(l) + O_(2)(g)$ .

Which best describes the effect of J. J. Thomson’s discovery

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Well one effect of J. J. Thomson's discovery is that he actually got a Nobel Prize. I don't really know what your choices are, so it's kinda difficult to know what you need.

All of the following methods would increase the solubility of a solid solute, except for

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may i please have a(n) answer choices please because it would be a lot better if it was like that and then ill answer it

Why does a leak in a car tire (at constant temperature) decrease the pressure of the tire?A) It removes kinetic energy from the system.
B) The number of molecules decreases.
C) The temperature decreases.
D) The volume decreases.

Answers

Answer:

Explanation:

The volume decreases.

At normal atmospheric pressure, water freezes at:a. -20 °C
b. 0 °C
c. 100 °C
d. 120 °C

Answers

Water will freeze at 0°C so the answer is b

Hi there! Your answer would be B. 0°C. Just like water at a lake, that water is a liquid and when it freezess it eventually becomes a solid. Now, you could ice skate on the lake, but make sure that the water is absolutely frozen.

When floral design first emerged as an art form, which technique was emphasized?

Answers

using flowers in their natural state and shape

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