Based on the results of testing colorless solutions with indicators, which solution is most acidic?(1) a solution in which bromthymol blue is blue
(2) a solution in which bromcresol green is blue
(3) a solution in which phenolphthalein is pink
(4) a solution in which methyl orange is red
Answers
Therefore, the solution that is most acidic is methyl orange because it was a darker red then any of the others.
Answer: Methyl Orange (#4)
Hope this helped!! :D
Phenolphthalein is pink in a basic solution (colorless in acid).Methyl orange is red in an acidic solution. Therefore, the most acidic solution is #4.
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How many moles is 1.50 x 1023 molecules of NH3
Answers
Answer:- Law of definite proportions.
Explanations:- The chemical composition of a compound is always constant means it contains the same elements in exactly same proportions by mass. This is called "Law of definite proportions."
Molecular formula of water is . It has two hydrogen atoms and one oxygen atom. Atomic mass of H is 1.008 and that of oxygen atom is 15.999.
Molar mass of water = 2(1.008) + 15.999 = 18.015
mass percentage of H = = 11.2%
mass percentage of O = = 88.8%
These percentages are always fix, no matter from where the sample of water is collected.
The molar mass of Cu is 63.5 g/mol. The molar mass of Ag is 107.9 g/mol. What mass, in grams, of Ag is produced from reaction of 31.75 g of Cu?
26.95
107.9
215.91
431.82
Answers
we are given the reaction Cu + 2AgNO3 ---> Cu(NO3)2 + 2Ag. This means for every mole Cu used, there are 2 moles of Ag produced. In this case, given 31.75 g Cu, converting to moles through molar mass and using stoichiometric ratio and the molar mass of Ag, the mass Ag produced is 107.9 grams.
The mass in grams of Ag produced from reaction of 31.75g of Cu is 107.9 grams
calculation
Cu+2AgNO3 ---> Cu(NO3)2 + 2Ag
find the moles of Cu that reacted
moles= mass/molar mass
=31.75 g/63.5 g/mol= 0.5 moles
from the equation above the mole ratio of CU:Ag is 1:2 therefore the moles of Ag=0.5 moles x2 = 1 mole
mass of Ag= moles of Ag x molar mass
= 1 mole x107.9g/mol = 107.9 grams
Answers
Answer is: B. 2NaCl +H2SO4 ----> Na2SO4 + 2HCl.
According to principle of mass conservation, number of atoms must be equal on both side of balanced chemical reaction.
There are two sodium atoms, two chlorine atoms, two hydrogen atoms, one sulfur atom and four oxygen atoms on both side of balanced chemical reaction.
A) This reaction is not balanced, because number of oxygen atoms are not the same.
C) This reaction is not balanced, because number of oxygen and calcium atoms are not the same.
D) This reaction is not balanced, because number of sulfur atoms are not the same.
The equatin that is balanced is 2NaCl + H2SO4 → Na2SO4 + 2HCl. The answer is letter B. The reactant has two Na, 2 Cl, 2 H, 1 S and 4 O. These number of atoms is also the same for the product side.
Answers
1) Assume 100 g sample
63.15% C * 100 g = 63.15g
5.30% H * 100 g = 5.30g
31.55% O * 100g = 31.55g
2) Convert mass to moles using their atomic weights
63.15 g * 1 mol C / 12.0107 g C = 5.2870 mol C
5.30 g * 1mol H / 1.0079 g H = 5.2585 mol H
31.55 g * 1mol O / 15.9994 O = 1.9719 mol O
3) Divide each quantity by the smallest number of moles
5.2870 mol C / 1.9719 mol = 2.6812 C = 2 C
5.2584 mol H / 1.9719 mol = 2.6667 H = 2 H
1.9719 mol O / 1.9719 mol = 1.000 O = 1 O
Empirical Formula is C₂H₂O
If the problem is silent, the molecular weight is equivalent to the empirical weight.
To get the molecular formula, divide the molecular weight by the empirical weight to get the multiple.
Molecular Weight is not mentioned thus it is equivalent to Empirical Weight which is:
Atom Number in Molecule Atomic Weight Total Mass
C 2 12.0107 24.0214
H 2 1.0079 2.0158
O 1 15.9994 15.9994
Total weight is 42.0366
Molecular weight / Empirical Weight = Multiple to be multiplied to the Empirical Formula
42.0366 / 42.0366 = 1
Molecular Formula isC₂H₂O
(2) 2.0 M (4) 0.75 M
Answers
Q < Keq
Q > Keq
Q = Keq
Answers
Answer:
A. Q = Keq
B. Equilibrium quantities of reactants and products
C. Q > Keq
D. System will shift toward reactants
E. Overabundance of reactants
F. System will shift toward products
Here are all the answers :)
Final answer:
To fill in the table about equilibrium, if Q < Keq the reaction will move right (produce more products), if Q > Keq it will move left (produce more reactants), and if Q = Keq the system is at equilibrium with no net change.
Explanation:
To complete the first row in the table about a system at equilibrium, we need to fill in the missing information based on the reaction quotient (Q) and the equilibrium constant (Keq).
For a system at equilibrium, not only is Q = Keq, but also the change in Gibb's free energy (ΔG) is zero. This relationship can be represented as 0 ΔG° + RT ln K at equilibrium.