At which temperature would atoms of a He(g) sample have the greatest average kinetic energy?(1) 25°C (3) 273 K
(2) 37°C (4) 298 K

Answers

Answer 1
Answer:

Answer;

37 ° C

Explanation;

-The average kinetic energy of gas particles is directly proportional to the the temperature. An increase in temperature increases the speed at which the gas molecules move, and thus increasing their kinetic energy. At any given temperature gases have the same kinetic energy.

-Hence, the temperature at which Helium gas will have the highest kinetic energy is at the highest temperature, which is 37° Celsius.


Answer 2
Answer:

Answer:

2: 37°C

Explanation:

This is because the temperature at which Helium gas will have the highest kinetic energy is at the highest temperature, which is 37° Celsius.


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What is made up of biotic and abiotic features

Answers

biotic - animals anything tht is living abiotic anything tht is non-living

Biotic-living organisms within an ecosystem. 
Abiotic-non-living things.

How many total atoms are in 0.380 g of P2O5

Answers

The gram formula mass of P2O5 is 31*2 + 16*5 =142. The mole number of P2O5 is 0.380/142=0.00268 mol. There is 7 atom in one P2O5 molecule. And there is 6.02 * 10^23 molecule per mol. So the answer is 1.13*10^22 atoms.

The change that is undergone by an atom of an element made radioactive by bombardment with high-energy protons is called(1) natural transmutation(2) artificial transmutation(3) natural decay(4) radioactive decay

Answers

Answer: The correct answer is Option 2.

Explanation:

Natural transmutation is defined as the decay process of the radioactive elements which occur spontaneously by a process that causes transmutation.

Artificial transmutation is defined as the process where artificially induced nuclear reaction is done by the bombardment of nucleus with high energy particles on a radioactive element. It is a spontaneous reaction.

Natural decay or radioactive decay are the processes in which a nucleus disintegrates spontaneously on its own. There are many processes by which this decay takes place.

Hence, the correct answer is Option 2.

Final answer:

Artificial transmutation is the process where an atom of an element is made radioactive by bombardment with high-energy protons. This process was exemplified by Ernest Rutherford when bombarding nitrogen atoms with alpha particles. Thus, changes in atomic structure due to high-energy proton bombardment are results of artificial transmutation.

Explanation:

The change undergone by an atom of an element made radioactive by bombardment with high-energy protons is called artificial transmutation. This is a process of nuclear chemistry, which involves the conversion of one nuclide into another. It can occur through the radioactive decay of a nucleus or via the reaction of a nucleus with another particle.

An example of artificial transmutation was evident in the early work of Ernest Rutherford. In 1919, he bombarded nitrogen atoms with high-speed alpha particles from a natural radioactive isotope of radium and observed protons resulting from the reaction. Thus, artificial transmutation is the process responsible for the alteration in atomic structure when an element becomes radioactive due to bombardment by high-energy protons.

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How many atoms are contained in 1 mole of silver

Answers

3 atoms! Glad I can help! :)
3 atoms are contained in 1 mole of silver

What is the percent by mass of potassium in K3Fe(CN)6?16.96%
21.88%
25.53%
35.62%

Answers

The percent mass of potassium in K3Fe(CN)6 is 35.62%. The molar mass (Mr) of K3Fe(CN)6 is the sum of atomic masses (Ar) of its elements. Ar(K) = 39.1 g/mol, Ar(Fe) = 55.84 g/mol; Ar(C) = 12.01 g/mol; Ar(N) = 14.01 g/mol. Mr(K3Fe(CN)6) = 3Ar(K) + Ar(Fe) + 6Ar(C) + 6Ar(N) = 3 * 39.1 + 55.85 + 6 * 12.01 + 6 * 14.01 = 117.3 + 55.85 + 72.06 + 84.06 = 329.27 g/mol. There are 3 atoms of K, so total mass of K in K3Fe(CN)6 is: 3Ar(K) = 3 * 39.1 = 117.3 g/mol. In percents, this is: 329.27 : 100% = 117.3 : x. x = 100% * 117.3 : 329.27 = 35.62%

Answer:

%35.62

Explanation:

Just took the test

The average speed of a nitrogen molecule in air at 25 °C is 515 m/s. Convert this speed to miles per hour.

Answers

Answer:

1151.08miles/h

Explanation:

The given speed is 515 m/s

To convert meters per second to miles per hour:

Convert meters to miles: 1 m = 0.000621371 miles

Convert seconds to hours: 1 hr = 3600 s

Plug into the formula: miles/hr = (m/s) * (0.000621371 miles/m) * (3600 s/hr)

Plugging in the numbers: miles/hr = (515 m/s) * (0.000621371 miles/m) * (3600 s/hr) miles/hr = 1151.08miles/h

Therefore, the average speed of a nitrogen molecule in air at 25 °C converted to miles per hour is 1151.08miles/h.

Final answer:

To convert the average speed of a nitrogen molecule in air from meters per second to miles per hour, first convert the speed from meters per second to kilometers per hour, and then convert from kilometers per hour to miles per hour.

Explanation:

To convert the average speed of a nitrogen molecule in air from meters per second to miles per hour, we can use the conversion factor 1 mile = 1609.34 meters and 1 hour = 3600 seconds.

First, let's convert the speed from meters per second to kilometers per hour. We divide the speed in meters per second by 1000 to get the speed in kilometers per second and then multiply by 3600 to get the speed in kilometers per hour. This gives us a speed of approximately 1850 km/h.

Next, we convert the speed from kilometers per hour to miles per hour by dividing the speed in kilometers per hour by 1.60934. This gives us a speed of approximately 1150 mph.

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