After decaying for 48 hours,1/16 of the original mass of a radioisotope sample remains unchanged. What is the half-life of this radioisotope?
Answers
If 1/16 of the sample remains it means that there were 4 half-life periods (16=2⁴)
4 half-life periods = 48 hours /4
half-life period = 12 hours
Hope it helped :)
The radioisotope is an unstable chemical element. The half-life of the radioisotope after decaying for 48 hours is 12 hours.
What is half-life?
Half-life is a period taken by the radioisotope to get decayed by half the original amount. The half-life is the time that is needed by the reactant to get decreased and form the product.
If the sample remained is 1/16 then there are 4 half-life periods present.
4 half life = 48 hours ÷ 4
= 12 hours
Therefore, 12 hours is the half-life period.
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Answer:
13.39 mol ≅ 13.4 mol.
Explanation:
- It is known that 1.0 mole of any gas occupies 22.4 L at STP conditions.
Using cross multiplication:
1.0 mole of Cl₂ occupies → 22.4 L.
??? mole of Cl₂ occupies → 300.0 L.
∴ The no. of moles of Cl₂ are in 300 liters = (1.0 mol)(300.0 L)/(22.4 L) = 13.39 mol ≅ 13.4 mol.
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Answer:
The balanced chemical equation is :
Explanation:
The chemical equation in which number of atoms in reactants is equal to products is called balanced equation.
Formula of , Beryllium Chloride :
Beryllium Nitrate :
Silver Chloride :
Silver Nitrate :
When beryllium chloride reacts with dissolved silver nitrate in water , following reaction occur :
The number of atoms in reactant as well as in products are balanced :
Be = 1
Ag = 2
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Final answer:
This is a chemical reaction involving beryllium chloride and silver nitrate in water, resulting in the formation of solid silver chloride and aqueous beryllium nitrate.
Explanation:
The question pertains to a chemical reaction in aqueous solution between beryllium chloride and silver nitrate. This reaction can be described by the equation BeCl2(aq) + 2AgNO3(aq) → 2AgCl(s) + Be(NO3)2(aq). In this equation, (aq) represents compounds dissolved in water (aqueous), and (s) represents solid. This reaction results in a precipitate of silver chloride (AgCl(s)), which is a powder, and an aqueous solution of beryllium nitrate (Be(NO3)2a).
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