Identify the property shown. 3p · (2 + k) = 6p + 3pk



A.
transitive


B.
associative


C.
commutative


D.
distributive

Answers

Answer 1
Answer: The answer is D. it is that because u are distributing the numbers within the parenthesis. HOPE THIS HELPS!!!!!!!!!

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What is a 1/4 of ?/100

Answers

(1)/(4)\cdot100=25
......
1/4 * 100 = 25

The answer is 25.

A recipe that makes 16 cookie calls for 1/4 cup sugar and 2/3 cup flour. Janelle wants to proportionally increase these amounts to get a new recipe using one cup of sugar. Using the new recipe, how much flour should she use? How many cookies can she make with the new recipe

Answers

just multiply by 4
4x2/3= 2 2/3
4x16= 64

What is the percent of 5/9

Answers

To write a fraction as a percent, first remember that a percent is a ratio of a number to 100. If we wanted to write (5)/(9) as a percent, we need to find a fraction equivalent to (5)/(9) with a 100 in the denominator of the fraction. We can do this by setting up a proportion.

(5)/(9) = (n)/(100)

Now, we can use cross products to find the missing value.

9n = 500

÷9     ÷9

n = 55.6

Therefore, 5/9 can be written as 55.6%.

There are 55.56% of the percent of 5/9.

Since, A number or ratio that can be expressed as a fraction of 100 or a relative value indicating hundredth part of any quantity is called percentage.

To Calculate the percent of a number , divide the number by whole number and multiply by 100.

We have to given that;

To find the percent of 5/9.

Let us assume that,

the percent of 5/9 is, x

Hence, We can formulate;

⇒ 5/9 = x%

⇒ 5/9 = x / 100

⇒ x = 500/9

⇒ x = 55.56%

Thus, There are 55.56% of the percent of 5/9.

Learn more about the percent visit:

brainly.com/question/24877689

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Solve irrational equation pls

Answers

\hbox{Domain:}\nx^2+x-2\geq0 \wedge x^2-4x+3\geq0 \wedge x^2-1\geq0\nx^2-x+2x-2\geq0 \wedge x^2-x-3x+3\geq0 \wedge x^2\geq1\nx(x-1)+2(x-1)\geq 0 \wedge x(x-1)-3(x-1)\geq0 \wedge (x\geq 1 \vee x\leq-1)\n(x+2)(x-1)\geq0 \wedge (x-3)(x-1)\geq0\wedge x\in(-\infty,-1\rangle\cup\langle1,\infty)\nx\in(-\infty,-2\rangle\cup\langle1,\infty) \wedge x\in(-\infty,1\rangle \cup\langle3,\infty) \wedge x\in(-\infty,-1\rangle\cup\langle1,\infty)\nx\in(-\infty,-2\rangle\cup\langle3,\infty)


√(x^2+x-2)+√(x^2-4x+3)=√(x^2-1)\nx^2-1=x^2+x-2+2√((x^2+x-2)(x^2-4x+3))+x^2-4x+3\n2√((x^2+x-2)(x^2-4x+3))=-x^2+3x-2\n√((x^2+x-2)(x^2-4x+3))=(-x^2+3x-2)/(2)\n(x^2+x-2)(x^2-4x+3)=\left((-x^2+3x-2)/(2)\right)^2\n(x+2)(x-1)(x-3)(x-1)=\left((-x^2+x+2x-2)/(2)\right)^2\n(x+2)(x-3)(x-1)^2=\left((-x(x-1)+2(x-1))/(2)\right)^2\n(x+2)(x-3)(x-1)^2=\left((-(x-2)(x-1))/(2)\right)^2\n(x+2)(x-3)(x-1)^2=((x-2)^2(x-1)^2)/(4)\n4(x+2)(x-3)(x-1)^2=(x-2)^2(x-1)^2\n
4(x+2)(x-3)(x-1)^2-(x-2)^2(x-1)^2=0\n(x-1)^2(4(x+2)(x-3)-(x-2)^2)=0\n(x-1)^2(4(x^2-3x+2x-6)-(x^2-4x+4))=0\n(x-1)^2(4x^2-4x-24-x^2+4x-4)=0\n(x-1)^2(3x^2-28)=0\nx-1=0 \vee 3x^2-28=0\nx=1 \vee 3x^2=28\nx=1 \vee x^2=(28)/(3)\nx=1 \vee x=\sqrt{(28)/(3)} \vee x=-\sqrt{(28)/(3)}\n

There's one more condition I forgot about
-(x-2)(x-1)\geq0\nx\in\langle1,2\rangle\n

Finally
x\in(-\infty,-2\rangle\cup\langle3,\infty) \wedge x\in\langle1,2\rangle \wedge x=\{1,\sqrt{(28)/(3)}, -\sqrt{(28)/(3)}\}\n\boxed{\boxed{x=1}}

Drag each label to the correct box. Not all labels will be used.William says that 15 years from now, his age will be 3 times his age 5 years ago. If x represents William's present age, complete the following
sentences
15 years
18 years
x - 15 = 3(x + 5)
x+15= 3(x - 5)
The equation representing William's claim is
William's present age is

Answers

Answer:

x+15=3(x-5) his present ae is 15 years

Step-by-step explanation:

x+15=3(x-5)

x+15=3x-15

15+15=3x-x

30=2x

x=30/2=15 years

Mr. Glidden is expanding the size of his garden. His new garden will be 3 times as long and 2 times as wide as his original garden. The perimeter of his original garden is 30 feet and the length is 11 feet. What will be the perimeter, in feet of his new garden?

Answers

Method One:


Step One: Figure out how long the width is, witch is 19 feet.

Step Two: Multiply 2*19 and 3*11 because it is 2 times as long and three times as wide

Step Three: Add 38+33

The new perimeter will be 71 feet.