Answer:
NaClO₄
Solution:
Let us calculate the oxidation state of Chlorine in each compound one by one;
1) NaClO
O.N of Na = +1
O.N of O = -2
So,
(+1) + (Cl) + (-2) = 0
1 + Cl - 2 = 0
Cl = -1 + 2
Cl = +1
2) NaClO₃
(+1) + (Cl) + (-2)3 = 0
(+1) + (Cl) - 6 = 0
1 + Cl - 6 = 0
Cl = -1 + 6
Cl = +5
3) NaClO₂
(+1) + (Cl) + (-2)2 = 0
(+1) + (Cl) + (-4) = 0
1 + Cl - 4 = 0
Cl = -1 + 4
Cl = +3
4) NaClO₄
(+1) + (Cl) + (-2)4 = 0
(+1) + (Cl) + (-8) = 0
1 + Cl - 8 = 0
Cl = -1 + 8
Cl = +7
Answer:
the internet can teach you alot about all 3 things
Explanation:
Answer:
if you go on YT and search kinetic, potential, and gravitational energy their will be a bill nye vid that is very informational on the topic at hand!!!
Explanation:
hope this helps!!
b. silver
c. lead
d. iron?
In order to join stained glass pieces together lead is used
The lead is preferred material as
a) due to its soft and flexible nature we can easily cut and mold it according to the application area
b) Compared to other options lead is less costly and is long lasting
Thus lead finds its application in came glass work
Answer:
Q = 836 J
Explanation:
Given data:
Mass of water = 10.0 g
Temperature increased =ΔT = 20°C
Specific heat capacity of water = 4.18 J/g.°C
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Q = 10.0 g × 4.18 J/g.°C × 20°C
Q = 836 J
Answer:
The quantum numbers n = 3 and l = 0 correspond to a specific type of orbital within the third principal energy level (n = 3) of an atom.
When l = 0, it corresponds to the s orbital. So, the orbital designated by the quantum numbers n = 3, l = 0 is the 3s orbital. The 3s orbital is spherically symmetrical and has a single orientation within its energy level.
Henri Becquerel was studying properties of x-rays