A sample of an unknown compound is vaporized at 190.°C. The gas produced has a volume of 2160.mL at a pressure of 1.00atm, and it weighs 2.87g. Assuming the gas behaves as an ideal gas under these conditions, calculate the molar mass of the compound. Be sure your answer has the correct number of significant digits.

Answers

Answer 1
Answer:

Answer:

Molar mass = 50.4 g/mol

Explanation:

Pressure . Volume = number of moles (n) . R . T°K

This is the Ideal Gases Law where R is the Ideal Gases Constant and T°, Absolute Temperature.

We convert the T°C to T°K → 190°C + 273 = 463 K

R = 0.082 L.atm /mol.K

We need to convert the volume from mL to L → 2160 mL . 1L / 1000 mL = 2.16 L; now we replace:

1 atm . 2.16L = n . 0.082 L.atm /mol.K . 463K

(1 atm . 2.16L) / (0.082 L.atm /mol.K . 463K) = n → 0.569 moles

These moles refers to 2.87 g so let's find out the molar mass:

Molar mass (g/mol) = 2.87 g / 0.0569 mol =  50.4 g/mol


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The density of a liquid form of a material is always less than the density of the solid form of that same material true or false

Answers

Answer:

False

Explanation:

This property depends on the intermolecular interactions of the analyzed compound.

In most cases, this property is fulfilled, but one of the most important exceptions is water since ice cubes float in liquid water which means that its density is lower than that of liquid water.

This is due to one of the types of bonds that binds hydrogen bonds to water molecules.

Hydrogen bridges are a molecular interaction that occurs between the hydrogen in one molecule of water and the oxygen in another molecule.

Recall the formula of the density

d=(m)/(v)

The volume is inversely proportional to the density this means that the lower the volume the higher the density and the higher the volume the lower the density.

This type of bonding means that when the H_2O freezes there is more space between the molecules, then they occupy a larger volume

Therefore, if we have the same mass in the liquid state and the solid-state, the molecules in the liquid state will be closer together occupying less volume (higher density) and the molecules that are in the solid-state occupy a greater volume (lower density)

Almost always true. H2O is the exception as water is more dense than ice.

According to VSEPR theory, what causes water molecules to have a bent shape? A. the unusual location of the free electrons. . B. repulsive forces between specific lone pairs of electrons. . C. attraction between the fixed orbitals of the unshared pairs of oxygen electrons. . D. ionic attraction and repulsion

Answers

According to VSEPR theory, what causes water molecules to have a bent shape?

Answer: Out of all the options presented above the one that best represents what causes water molecules to have a bent shape according to VSEPR theory is answer choice B) repulsive forces between specific lone pairs of electrons. the bond angle in a water molecule is bent.

I hope it helps, Regards.

The correct answer is \boxed{{\text{option }}\left( {\text{B}} \right)} that is repulsive forces between specific lone pairs of electrons.

Further Explanation:

The total number of valence electrons of {{\text{H}}_2}{\text{O}} is calculated as,

Total valence electrons (TVE) = [(1) (Valence electrons of O) + (2) (Valence electrons of H)]

\begin{aligned}{\text{Total valence electrons}}\left( {{\text{TVE}}}\right)&=\left[{\left({\text{1}}\right)\left({\text{6}}\right)+\left({\text{2}}\right)\left({\text{1}}\right)}\right]\n&=8\n\end{aligned}

In {{\text{H}}_2}{\text{O}}, the total number of valence electrons is 8. Here, oxygen forms single bond with the hydrogen atom and therefore, 2 pair of electrons are used in the formation of two single bonds with hydrogen atom. Remaining 2 pair of electrons are used to complete the octet of oxygen atom. Therefore, {{\mathbf{H}}_{\mathbf{2}}}{\mathbf{O}}contains two bond pairs and two lone pairs (refer to the image attached).

According to the VSEPR theory, central atom oxygen has two bond pair with two lone pair, therefore, {{\text{H}}_2}{\text{O}} has an {\text{A}}{{\text{B}}_2}{{\text{E}}_2} arrangement. Therefore, these four pairs of electrons spread out as tetrahedral arrangement to minimize lone pair-lone pair and bond pair-bond pair repulsion. Since lone pairs are not considered in the shape of the molecule and therefore, the final shape of water molecule is bent-shape.

Learn more:

1. Molecular shape around the central atom in the amino acid glycine: brainly.com/question/4341225

2. Balanced chemical equation: brainly.com/question/1405182

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Covalent bonding and molecular structure

Keywords: hybridization, water, geometry, sp3, steric number, 3, p orbital, s orbital, Lewis structure, hybridization of water, central atom, carbon, hydrogen, oxygen, shape, double bond, h2o.

Entropy measures _____.a. disorder
b. energy
c. heat transferred
d. force

Answers

a. disorder

Good luck!

What are the formal charges of both chlorines and iodine in icl2?

Answers

Answer:

Explanation:

 Formal charge of ICl₂⁻

Formal charge = group no - ( no of non bonding electrons +no of bonds)

In I there are 7 electrons in outermost orbit . If we add one more electrons due to - ve charge on the ion , it becomes eight . This centrally placed iodine forms two single bond with two chlorine atoms on either side.

Each of chlorine atoms also contains 7 valance electrons like iodine.

So formal charge of chlorine

= group no - ( no of non bonding electrons +no of bonds)

= 7 - ( 6 + 1 )

= 0

So formal charge of iodine

= group no - ( no of non bonding electrons +no of bonds)

= 7 - ( 5 + 2 )

=0

 Formal charge of ICl₂⁺

In this case , central iodine will have only 6 valence electrons due to absence one electron.

So formal charge of chlorine in  ICl₂⁺

= group no - ( no of non bonding electrons +no of bonds)

= 7 - ( 6 + 1 )

= 0

formal charge of iodine in  in   ICl₂⁺

7 - ( 4 + 2)

= 1

Which type of reaction occurs when nonmetal atoms become negative nonmetal ions?A. oxidation
B. reduction
C. substitution
D. condensation

Answers

Answer: Option (B) is the correct answer.

Explanation:

When an atom gains electrons then it becomes rich in electrons and therefore it acquires a negative charge.

Also, it is known that a reduction reaction is a reaction in which an element gain electron(s).

For example, Br_(2) + 2e^(-) \rightarrow 2Br^(-) is a reduction reaction.

Thus, we can conclude that when nonmetal atoms become negative nonmetal ions then type of reaction which occurs is reduction reaction.

The answer is B. reduction. The atom becoming negative ions means it gains electrons. The reaction which gain electrons is reduction reaction. So the answer is B.

What information is necessary to determine the atomic mass of the element chlorine?(1) the atomic mass of each artificially produced isotope of chlorine, only
(2) the relative abundance of each naturally occurring isotope of chlorine, only
(3) the atomic mass and the relative abundance of each naturally occurring isotope of chlorine
(4) the atomic mass and the relative abundance of each naturally occurring and artificially produced isotope of chlorine

Answers

Answer is: (3) the atomic mass and the relative abundance of each naturally occurring isotope of chlorine.

m(³⁵Cl) = 34.97 amu; the average atomic mass of chlorine-35.  

m(³⁷Cl) = 36.97 amu; the average atomic massof chlorine-37.

ω(³⁵Cl) = 75.76% ÷ 100% = 0.7576; fractional abudance of chlorine-35.

ω(³⁷Cl) = 24.24% ÷ 100% = 0.2424; fractional abudance of chlorine-37.

m(Cl) = m(³⁵Cl) · ω(³⁵Cl) + m(³⁷Cl) · ω(³⁷Cl).  

m(Cl) = 34.97 amu · 0.7576 + 36.97 amu · 0.2424.  

m(Cl) = 35.4548 amu; average atomic mass of chlorine.

Final answer:

The atomic mass of chlorine is determined by both the atomic mass and the relative abundance of each naturally occurring isotope of chlorine. It's based on an average of the masses of the isotopes according to their relative abundance.

Explanation:

To determine the atomic mass of the element chlorine, option (3), both the atomic mass and the relative abundance of each naturally occurring isotope of chlorine is required. The atomic mass of chlorine is not just the mass of one particular atom, or isotope; instead, it's an average of the masses for all the isotopes according to their relative abundance. For instance, Chlorine has two isotopes Chlorine-35 and Chlorine-37. If the relative abundance of Chlorine-35 is 75% and that of Chlorine-37 is 25%, the atomic mass is calculated by the formula [(0.75 x 35) + (0.25 x 37)].

Learn more about Atomic Mass here:

brainly.com/question/32442642

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