A solution contains 35 grams of KNO3 dissolved in 100 grams of water at 40°C. How much more KNO3 would have to be added to make it a saturated solution?(1) 29 g (3) 12 g
(2) 24 g (4) 4 g

Answers

Answer 1
Answer:

A saturated solution is a solution that can not dissolve any more solute in it. The amount of potassium nitrate that can be dissolved to make a saturated solution is 29 gm.

What is solubility?

The capability of the solute to get dissolved in the solvent to form a saturated solution is called solubility.

The solubility of potassium nitrate in 100 gm of water at 40 degrees celsius is 64 gm. Hence, 64 gm of potassium nitrate is required in 100 gm of water to form a saturated solution.

In the question, the amount of potassium nitrate in 100gm water is 35 gm so, the amount of the potassium nitrate required more will be,

64 - 35 = 29 \;\rm gm

Therefore, option (1) 29 gm of potassium nitrate should be added more.

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Answer 2
Answer:

The solubility of  at 40 C is around 64 g in 100 g water  ot 0.64 g KNO3 in 100 g water.  

Therefore 64 g KNO3  in 100 g water is required for satured solution.

 According to the problem  there are 35 grams of KNO3 dissolved in 100 grams  water  

So we need 64 g-35 g= 29 g more KNO3  

Hence the correct answer is 1  

Solubility:

When the maximum amount of solute is dissolve in the solvent is called solubility. On the basic of solubility the solution are following types:

Saturate solution:

A solution which contains the maximum amount of dissolved solute at the equilibrium is called saturated solution.  

Un-saturate solution:

A solution which contains lesser amount of solute as compare to saturated solution.  It will be able to dissolver more solute.  

Super -Saturate solution:

A solution which contains the more dissolved amount of solute as compare to saturated solution.


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Choose the aqueous solution that has the highest boiling point. These are all solutions of nonvolatile solutes and you should assume ideal van't Hoff factors where applicable. 0.100 m C6H12O6 0.100 m AlCl3 0.100 m NaCl 0.100 m MgCl2 They all have the same boiling point.

Answers

Final answer:

The boiling point of an aqueous solution is elevated due to the presence of a nonvolatile solute. The extent of the boiling point elevation depends on the total number of solute particles in the solution. The solution with the highest boiling point would be 0.100 m AlCl3 because it breaks down into the most ions in solution.

Explanation:

The subject of this question is boiling point elevation, a chemical concept that is most relevant to the field of chemistry. The boiling point of an aqueous solution is elevated due to the presence of a nonvolatile solute because the solute lowers the solution's vapor pressure, requiring a higher temperature for the solution to boil. The extent of the boiling point elevation depends on the total number of solute particles in the solution, rather than their individual properties such as mass or chemical identity.

Given the choices of 0.100 m C6H12O6, 0.100 m AlCl3, 0.100 m NaCl, and 0.100 m MgCl2, the solution with the highest boiling point would be 0.100 m AlCl3. This is because AlCl3, aluminum chloride, breaks down into four ions in solution (one Al3+ ion and three Cl- ions), whereas the other substances break down into fewer ions (C6H12O6 doesn't break down into ions at all, NaCl breaks down into two ions, and MgCl2 breaks down into three ions). The more ions a substance breaks down into, the higher the elevation of the solution's boiling point.

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Final answer:

Among the given solutions, the 0.100 m AlCl3 (aluminum chloride) solution should have the highest boiling point as it produces the most particles when it dissociates in the solution, according to the principle of 'boiling point elevation'.

Explanation:

The question asks to choose the aqueous solution with the highest boiling point among 0.100 m C6H12O6 (glucose), 0.100 m AlCl3 (aluminum chloride), 0.100 m NaCl (sodium chloride), and 0.100 m MgCl2 (magnesium chloride). The highest boiling point will be determined by the solution with the most particles, because as the number of particles increase, the boiling point will rise. This concept is part of 'boiling point elevation' in solutions.

Both NaCl and MgCl2 will dissociate into ions when dissolved in water, producing 2 and 3 particles respectively for each formula unit. Meanwhile, AlCl3 will produce 4 particles when it dissociates (Al3+ and three Cl- ions). Glucose is a covalent compound and will not dissociate when dissolved in water; hence it only counts as one particle.

Based on the number of solute particles, AlCl3 should have the highest boiling point as it produces the most particles when it dissociates in the solution.

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State in term of molecular polarity why ethanol is soluble in water

Answers

Explanation:

As we all know that like disolves in like solvent.

Here both water and Ethanol are polar. Hence Ethanol soluble in water.

Moreover, both forms intermolecular hydrogen bonds. It enhances the solubility of ethanol.

Both water and Ethanol are called as associate liquids. Hence solubility is more.

Alcohols have higher boiling point than other hydrocarbons due to their polarity and from the fact that they form very strong intermolecular hydrogen bonding. This is due to the large difference in their electronegativity that forms between the oxygen and the hydrogen atom. 

Use the periodic table to find the charge of the ion that each atom is most likely to form. The charge of a sulfur (S) ion is The charge of a potassium (K) ion is The charge of a boron (B) ion is The charge of an iodine (I) ion is The charge of a bromine (Br) ion is

Answers

Final answer:

The charges of ions that Sulfur (S), Potassium (K), Boron (B), Iodine (I), and Bromine (Br) are most likely to form are -2, +1, +3, -1, and -1, respectively. This is determined by their positions on the periodic table.

Explanation:

The charge of an ion that a certain atom is most likely to form is dependent on its position on the periodic table. Elements on the left side of the periodic table (like potassium) tend to lose electrons and form positive ions, while elements on the right side (like sulfur, iodine, bromine) tend to gain electrons and form negative ions.

The charge of a sulfur (S) ion is usually -2 because sulfur, being in Group 16, tends to gain two electrons to reach a stable electronic configuration. The charge of a potassium (K) ion is usually +1. This is because potassium, which is in Group 1, usually loses one electron to achieve a stable electron configuration. The charge of a boron (B) ion is usually +3 because boron, being in Group 13, tends to lose three electrons in order to reach stability. The charge of an iodine (I) ion is usually -1 because iodine, which is in Group 17, tends to gain one electron to reach stability. Lastly, the charge of a bromine (Br) ion is usually -1, because bromine, also in Group 17, tends to gain one electron to attain a stable electronic configuration.

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Answer:

Sulfur (S) is

-2

Potassium (K) is +1

Boron (B) is +3

Iodine (I) is -1

Bromine (Br) is -1

Explanation:

The combustion of a sample of butune, C4H10 (lighter fluid), produced 2.46 grams of water. 2 C4H10 + 13O2------> 8CO2 + 10H2O

How much oxygen is used up in grams?

Answers

Molar mass :

H₂O = 18.0 g/mol
O₂ = 32.0 g/mol

2 CH₁₀ + 13 O = 8 CO + 10 HO

13 x 32.0 g O₂ ------------- 10 x 18.0 g H₂O
            ? g O₂ ------------- 2.46 g H₂O


Mass O₂ = 2.46 x 13 x 32.0 / 10 x 18.0

Mass  O₂ =1023.36 / 180

=> 5.68 g of O₂

hope this helps!

the word circuit means ________ therefore a circuit is a ___________ around which electricity or water flows

Answers

Answer:

the word circuit means go around therefore a circuit is a closed path around which electricity or water flows

Explanation:

Help this was helpful

Given the balanced ionic equation representing a reaction:2A1(s) + 3Cu2+(aq) ==>2A13+(aq) + 3Cu(s)
Which half-reaction represents the reduction that occurs?(I ) Al ==> Al3+ + 3e-
(2) Al3+ + 3e- ==>Al
(3) Cu ==> Cu2+ + 2e-
(4) Cu2+ + 2e- ==>Cu

Answers

the answer should be (4)