CHEMISTRY HIGH SCHOOL

Which organic compound is unsaturated?(1) 2-methylbutane (3) 2-hexanol
(2) 2-chloropropane (4) 2-pentene

Answers

Answer 1
Answer: The answer is (4) 2-pentene. The pentene belongs to olefin and has double bonds between the carbon atoms. And the other three belongs to alkane which don't have double bonds. So the pentene is unsaturated.

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A sample of an element is malleable and can conduct electricity. This element could be(1) H (3) S
(2) He (4) Sn

Answers

Answer is: 4) Sn.

Tin (Sn) is only metal in this question and metals are malleable and can conduct electricity.

Metals have metallic bond.

1. Metallic bond is a type of chemical bond.  

2. Metallic bond is formed between electrons and positively charged metal ions.  

3. Metallic radius is defined as one-half of the distance between the two adjacent metal ions.  

4. Metallic bond increace electrical and thermal conductivity.  

5. Metals conduct heat, because when free moving electrons gain energy (heat) they vibrate more quickly and can move around.
The answer is (4) Sn. Malleability and conductivity are properties of metals, and Sn is the only metal of the four.

How many protons , electrons, and neutrons are contained in gallium-69?

Answers

In gallium-69, there are 31 protons, and and 31 electrons, if it is an atom of gallium-69. There are 38 neutrons as well.

Final answer:

Gallium-69, an isotope of Gallium, contains 31 protons, 31 electrons and 38 neutrons.

Explanation:

Gallium-69 is a specific isotope of the element Gallium.Gallium is the element with atomic number 31 on the periodic table. This atomic number means that a Gallium atom has 31 protons in its nucleus. Given that in a neutral atom the number of electrons equals the number of protons, we can also deduce that Gallium-69 contains 31 electrons.

The number following the name of the element, 69 in this case, is the isotope's mass number, which is the total number of protons and neutrons that an atom of that isotope contains in its nucleus. To find the number of neutrons in Gallium-69, you simply subtract the number of protons from the mass number. This yields 69 - 31 = 38. Thus, Gallium-69 has 38 neutrons.

Learn more about Gallium-69 here:

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The Haber process can be used to produce ammonia (NH3) from hydrogen gas (H2) and nitrogen gas (N2). The balanced equation for this process is shown below. 3H2 N2 Right arrow. 2NH3 The molar mass of NH3 is 17. 03 g/mol. The molar mass of H2 is 2. 0158 g/mol. In a particular reaction, 0. 575 g of NH3 forms. What is the mass, in grams, of H2 that must have reacted, to the correct number of significant figures? 0. 1 0. 102 0. 10209 0. 1021.

Answers

Answer:

B

Explanation:

We are given that ammonia can be produced from hydrogen gas and nitrogen gas according to the equation:

\displaystyle 3\text{H$_2$} + \text{N$_2$} \longrightarrow 2\text{NH$_3$}

We want to determine the mass of hydrogen gas that must have reacted if 0.575 g of NH₃ was produced.

To do so, we can convert from grams of NH₃ to moles of NH₃, moles of NH₃ to moles of H₂, and moles of H₂ to grams of H₂.

We are given that the molar masses of NH₃ and H₂ are 17.03 g/mol and 2.0158 g/mol, respectively.

From the equation, we can see that two moles of NH₃ is produced from every three moles of H₂.

With the initial value, perform dimensional analysis:

\displaystyle \begin{aligned} 0.575\text{ g NH$_3$}& \cdot \frac{1\text{ mol NH$_3$}}{17.03\text{ g NH$_3$}} \cdot\frac{3\text{ mol H$_2$}}{2\text{ mol NH$_3$}} \cdot \frac{2.0158\text{ g H$_2$}}{1\text{ mol H$_2$}} \n \n & = 0.102\text{ g H$_2$}\end{aligned}

*Assuming 100% efficiency.

Our final answer should have three significant figures. (The first term has three, the second term has four (the one is exact), the third term is exact, and the fourth term has five. Hence, the product should have only three.)

In conclusion, our answer is B.

Hydrogen bonding is strongest between molecules of

Answers

i'm not completely sure but i think it's H2O. hope this helps :)

A mixture of CH4 and H2O is passed over a nickel catalyst at 1000 K. The emerging gas is collected in a 5.00-L flask and is found to contain 8.62 g of CO, 2.60 g of H2, 43.0 g of CH4, and 48.4 g of H2O.

Answers

The given question is incomplete. But the complete question is this:

A mixture of CH_(4) and H_2O is passed over a nickel catalyst at 1000 K. The emerging gas is collected in a 5.00-L flask and is found to contain 8.62 g of CO, 2.60 g of H_2, 43.0 g of CH_(4), and 48.4 g of H_(2)O. Assuming that equilibrium has been reached, calculate K_(p) for the reaction.

Explanation:

As the given reaction is as follows.

       CH_4 + H_2O \rightarrow CO + 3H_2

And, we know that

        No. of moles = \frac{mass}{\text{molar mass}}

Therefore, calculate the moles as follows.

      Moles of CH_4 = (43)/(16.04)

                                  = 2.6808  mol

      Moles of H_2O = (48.4)/(18.01528)

                                  = 2.6866 mol

     Moles of CO = (8.62)/(28.01)

                           = 0.307747  mol

       Moles of H_(2) = (2.6)/(2.01588)

                           = 1.2897  mol

As, we know that

        Concentration = (moles)/(volume (L))

Given volume = 5 L

Hence, calculate the concentration of given species as follows.

    Conc. of CH_4 = (2.6875)/(5)

                                 = 0.5361

     Conc. of H_2O = (2.6889)/(5)

                                = 0.5373

      Conc. of CO = (0.307747)/(5)

                                  = 0.06155

and,  Conc. of H_2 = (1.2897)/(5)

                               = 0.2579

Now, expression for equilibrium constant for the given reaction is as follows.

        K_(c) = ([CO][H_2]^(3))/([CH_4][H_2O])

Now, putting the given values into the above formula as follows.

        K_(c) = ([0.06155][0.2579]^(3))/([0.5361][0.5373])

         K_(c) = 3.665 * 10^(-3)

Also, we know that

             K_p = K_c * (RT)^dn

Consider the equation

        CH_4(g) + H2O(g) \rightarrow CO(g) + 3H_2(g)

Calculate change in moles of gas as follows.

         change in gas moles (dn) = 1 + 3 - 1 - 1

                                              dn = 2

As,    K_p = K_c * (RT)^2

It is given that,  

T = 1000 K,         R = 0.0821

So,

         K_p = 3.665 * 10^(-3) * (0.0821 * 1000)^(2)

          K_p = 24.70

Thus, we can conclude that value of K_(p) for the reaction is 24.70.

Is zinc coMpund Plz help me​

Answers

Answer:

it is indeed a compound

Explanation:
Zinc is NOT a compound.

A compound contains two or more elements or molecules like H2O. Where H is 1 element and Oxygen is another and together they make a compound.

Zinc itself is a single molecule (or element) and can be used in a compound like ZnO (zinc oxide)
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