PHYSICS HIGH SCHOOL

Sound waves are produced by the horn of a truckthat is approaching a stationary observer.
Compared to the sound waves detected by the
driver of the truck, the sound waves detected by
the observer have a greater
(1) wavelength (3) period
(2) frequency (4) speed

Answers

Answer 1
Answer: Compared to the sound waves detected by the driver of the truck, the sound waves detected by the observer have a greater "(2) frequency" and will be more high pitched. 
Answer 2
Answer:

Answer: The correct option is (2).

Explanation:

Doppler effect is the phenomenon in which the frequency of the wave increase or decrease when there is relative motion between the source and the listener. There is an apparent change in the frequency.

When the source and the listener are approaching each other then there will be increase in the frequency.

When the source and the listener are moving away form each other then there will be decrease in the frequency.

In the given problem, Sound waves are produced by the horn of a truck

that is approaching a stationary observer. The sound waves detected by the observer have greater frequency.

Therefore, the correct option is (2).

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What do an electron and a neutron have in common? Each particle has a mass of 1 amu.Each particle exists inside an atom. Each particle has an electrical charge.Each particle is located in the nucleus.
A ball is dropped from a height of 16 feet. Each time it drops h feet, it rebounds 0.81h feet. Find the total distance traveled by the ball.
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Nicolaus Copernicus was considered: a heretic because his theory disagreed with the church a hero because his theory agreed with current beliefs the "Father of Astronomy" because he believed the earth was the center of the solar system

Answers

Answer:

A heretic because his beliefs disagreed with the church
Nicolaus Copernicus was considered the "Father of Astronomy" because he believed the earth was the center of the solar system. The rest of the choices do not answer the question above.

Ahmad is riding his bicycle. He finds that he can accelerate from rest at 0.44 m/s^2 for 5 s to reach a speed of 2.2 m/s. The total mass of Christian and his bicycle is 54 kg. Later, he straps some cargo onto the back of his bicycle. The mass of the cargo is 12 kg.• Calculate the force that Christian can exert on his bicycle before picking up the cargo and exerts the same force on his bicycle.

Answers

Answer:

1) The force Christian can exert on his bicycle before picking up the the cargo is 529.74 N

2) The force Christian can exert on his bicycle after picking up the the cargo is 647.46 N

Therefore, Christian has to exert more force on his bike after picking up the cargo

Explanation:

The given parameters are;

The mass of Christian and his bicycle = 54 kg

The mass of the cargo = 12 kg

1) The force Christian can exert on his bicycle before picking up the the cargo = Mass of Christian and his bicycle × Acceleration due to gravity

∴ The force Christian can exert on his bicycle before picking up the the cargo = 54 kg × 9.81 m/s² = 529.74 N

2) The force Christian can exert on his bicycle after picking up the the cargo = (54 + 12) kg × 9.81 m/s² = 647.46 N

Therefore, Christian has to exert more force on his bike after picking up the cargo.

2a. Abecomes
jeep starts from it the
starts from it the state of rest. If its
velocity 60m/s and its take 5 minute: what is the accelera
ution of the jeep
the distanced travelled by
the jeep:​

Answers

\bf \underline{ \underline{Given : }}

  • Initial velocity,u = 0 m/s

  • Final velocity,v = 60 m/s

  • Time taken,t = 5 min = 5 × 60 sec = 300 seconds

\bf \underline{ \underline{</p><p>To \: be \: calculated : }}

Calculate the acceleration ( a ) and distance (s ) covered by the jeep.

\bf \underline{ \underline{Solution : }}

We will first calculate the acceleration of the jeep.

CASE 1 :

By Using first equation of motion ,

\sf \: v = u + at

\sf \star \: Substituting \: the \: values...

\sf\rightarrow \: 60 = 0 + a * 300

\sf \rightarrow \: 60 = 300a

\sf \rightarrow \: 300a = 60

\sf \rightarrow \: a = \cancel (300)/(6)

\sf \rightarrow \: a = 50 \: m {s}^( - 2)

Thus,the acceleration of the jeep is 50 m/s².

Now, Let us calculate the distance travelled by the jeep.

CASE 2 :

By Using third equation of motion ,

\sf {v}^(2) = {u}^(2) + 2as

\sf \star \: Substituting \: the \: values...

\sf \rightarrow \: {60}^(2) = {0}^(2) + 2 * 50 * s

\sf \rightarrow \: 3600 = 100s

\sf \rightarrow \: 100s = 3600

\sf \rightarrow \: s = \cancel(3600)/(100)

\sf \rightarrow \: s = 36 \: m

Thus,the distance covered by the jeep is 36 m .

If 1.3 grams of air has a volume of 1000cm ^3, what is the density of air? A) 1300g/cm^3
B) 1001.3 g/cm^3
C) 769.23 g/cm^3
D) 0.0013 g/cm^3

Answers

Answer:

Density, d=0.0013\ g/cm^3

Explanation:

Given that,

Mass of the air, m = 1.3 grams

Volume of the air, V=1000\ cm^3

The density of the air is given by total mass divided by total volume. Mathematically, it is given by :

d=(m)/(V)

d=(1.3\ g)/(1000\ cm^3)

d=0.0013\ g/cm^3

Hence, this is the required solution.

D)
Density is equal to mass/volume, so in your case:
density=1.3/1000=0.0013 g/cm^3

Bumper of a stationary bumper car. The momentum of the stationary car increases. Which happens to the momentum of the moving bumper car? It decreases. It stays the same. It is converted to inertia.

Answers

Bumper of a stationary bumper car. The momentum of the stationary car increases. Which happens to the momentum of the moving bumper car? It decreases. It stays the same. It is converted to inertia.

Bumper of a stationary bumper car. The momentum of the stationary car increases. The momentum of the moving bumper car It is converted to inertia.

A myth that explains the spots on the moon is called

Answers

they arent myths, the spots are called "lunar mare", singular form is mare, but normally you'll hear "maria". 

hope this helps!
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