At standard pressure, the total amount of heat required to completely vaporize a 100. gram sample of water at its boiling point is(1) 2.26 X 10 J (3) 2.26 X 103 J(2) 2.26 X 102 J (4) 2.26 X 105 J

Answers

Answer 1
Answer:

During phase transformation Temperature remains same, as the extra heat goes into breaking the force of attraction between the particles. the correct option is option (4) that is 2.26×10⁵ J.

What is heat of vaporization?

Heat of vaporization is the amount of energy or heat that is required to break the force of attraction between the particles to convert liquid into vapors. Vaporization is an endothermic reaction. So the amount of energy that is required over here is positive. Heat of condensation is negative that is heat is released during reaction.

We know that the heat of vaporization of water is 2260 J/g. So, the total amount of heat required to completely vaporize a 100gram sample of water at its boiling point is 2260×00=2.26×10⁵ J.

Thus the correct option is option (4)

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Answer 2
Answer: We know that the heat of vaporization of water is 2260 J/g. So 100 gram sample of water being completely vaporized needs 2260*100=2.26*10^5 J. So the answer is (4).

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A serving of fish contains 50 g protein and 4 g of fat. If protein has a caloric value of 4 kcal/g and fat has 9 kcal/g, how many kcal are in the serving? Round off the energy value for each food group to the tens place.

Answers

Answer: 240

Explanation:

Final answer:

A serving of fish contains 236 kcal.

Explanation:

To find the number of kilocalories (kcal) in a serving of fish, we need to calculate the energy from protein and fat separately and then add them together. The energy from protein is calculated by multiplying the amount of protein by its caloric value of 4 kcal/g. So, 50 g of protein provides (50 g) x (4 kcal/g) = 200 kcal. The energy from fat is calculated in the same way, so 4 g of fat provides (4 g) x (9 kcal/g) = 36 kcal. Finally, we add the energy from protein and fat together, resulting in a total of 200 kcal + 36 kcal = 236 kcal in the serving of fish.

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What type of reaction is
CH 4 (g)+2O 2 (g) CO 2 (g)+2H 2 O(g)

Answers

Answer: combustion

Explanation:

Combustion reactions can be identified by looking at the reactants and the products.

Usually, the reactants will be a hydrocarbon and oxygen. And the products will be CO2 and H2O

The percentage by mass of Br in the compoundAlBr3 is closest to
(1) 10.% (3) 75%
(2) 25% (4) 90.%

Answers

Answer: The correct answer is option(4).

Explanation:

Molar mass of the aluminium bromide, AlBr_3=266.69 g/mol

Atomic mass of bromine = 79.90 g/mol

Percentage of Mass of bromine in AlBr_3:

\% Br\text{ by mass}=\frac{\text{Atomic mass of Br}* \text{Number of Br atoms}* 100}{\text{Molar mass of }AlBr_3}

\% Br\text{ by mass}=(79.90 g/mol* 3* 100)/(266.69 g/mol)=89.97\%\approx 90\%

Hence, the correct answer is option(4).

What you have to do it find the percentage / solve it. Divide the mass by the entire mass. 
239.7 ÷ 266.68 = 0.898 × 100 = 90% Br.

For the reaction ?H2 +?O2 → ?H2O, what is the maximum amount of H2O (18.0153 g/mol) which could be formed from 9.43 g of H2 (2.01588 g/mol) and 12.98 g of O2 (31.9988 g/mol)? Answer in units of g.

Answers

2H2 + O2 →2H2O
This is a limiting reactant problem in which you need to figure out which reactant is the limiting reactant. You can usually look at the information given and see that hydrogen has the smaller amount of mass used, but it is always good to check that assumption through stoichiometry:
(9.43g H2/2.02g/mol)(2mol H2O/2mol H2)(18.02gH2O/1mol H2O)= 84.1g H2O produced from 9.43g of H2

(12.98g O2/32.00g/mol O2)(2mol H2O/1mol O2)(18.02gH2O/1mol H2O)= 14.6g H2O

So my assumption that hydrogen makes the smaller amount of water is wrong since oxygen (it is the limiting reactant) created the smaller amount of water with 14.6g, so 14.6g is the maximum amount of water that can be formed

How many neutrons are in Cesium-130 (Cs)?

Answers

There are 75 neutrons in Cesium-130 (Cs).

Hope this helps!

How many protons , electrons, and neutrons are contained in gallium-69?

Answers

In gallium-69, there are 31 protons, and and 31 electrons, if it is an atom of gallium-69. There are 38 neutrons as well.

Final answer:

Gallium-69, an isotope of Gallium, contains 31 protons, 31 electrons and 38 neutrons.

Explanation:

Gallium-69 is a specific isotope of the element Gallium.Gallium is the element with atomic number 31 on the periodic table. This atomic number means that a Gallium atom has 31 protons in its nucleus. Given that in a neutral atom the number of electrons equals the number of protons, we can also deduce that Gallium-69 contains 31 electrons.

The number following the name of the element, 69 in this case, is the isotope's mass number, which is the total number of protons and neutrons that an atom of that isotope contains in its nucleus. To find the number of neutrons in Gallium-69, you simply subtract the number of protons from the mass number. This yields 69 - 31 = 38. Thus, Gallium-69 has 38 neutrons.

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