The sum of a number and 3 times the same number is 100. What is the number?
Equation:
Solution:

Answers

Answer 1

Answer: X + (3 × X) = 100

25 + (3 × 25) = 100

Answer 2

Answer: Let the number be x.

According to your question,

x + 3x = 100 ( Equation)

thus, 4x = 100

Thus, x = 100/4 = 25

Thus, the number is 25 (Solution)

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Find the difference using fraction bars or a paper and pencil. Write your answer in simplest form.11/12 - 3/4

Answers

First, find the lowest common denominator. That is 12. You only have to change 3/4 into 12ths.

3/4 = 9/12

11/12 – 9/12 = 2/12 = 1/6

We must find a common denominator, first

11/12 - 9/12

2/12

Simplified, it becomes 1/6

What is 10 more than 12793

Answers

All you do is add ten, 12,803 is ten more than 12,793.

you just have to add 10 more to that number 12793+10=12800

Help me make this the brainests

Solve for v -3v+11=-8v+51 Simplify your answer as much as possible.

Answers

Answer:

v = 8

Step-by-step explanation:

Solve for v -3v+11=-8v+51 Simplify your answer as much as possible.

-3v + 11 = -8v + 51

-3v + 8v = 51 - 11

5v = 40

v = 40 : 5

v = 8

--------------------------

check

-3(8) + 11 = -8(8) + 51

-24 + 11 = -64 + 51

-13 = -13

If alpha and beta are the zeroes of the polynomial 6x2+x-2 find the value og alpha/beta + beta/alpha

Answers

$6x^2+x-2=6x^2+4x-3x-2=2x(3x+2)-1(3x+2)\n\n=(3x+2)(2x-1)\n\n3x+2=0\to x=-(2)/(3)\n\n2x-1=0\to x=(1)/(2)\n\n\alpha=-(2)/(3);\ \beta=(1)/(2)\n\n(\alpha)/(\beta)+(\beta)/(\alpha)=(-(2)/(3))/((1)/(2))+((1)/(2))/(-(2)/(3))=-(2)/(3)\cdot(2)/(1)-(1)/(2)\cdot(3)/(2)=-(4)/(3)-(3)/(4)\n\n=-(16)/(12)-(9)/(12)=-(25)/(12)=-2(1)/(12)$

$use\ Vieta's\ formula:\n\n(\alpha)/(\beta)+(\beta)/(\alpha)=(\alpha^2+\beta^2)/(\alpha\beta)=(\alpha^2+2\alpha\beta+\beta^2-2\alpha\beta)/(\alpha\beta)=((\alpha+\beta)^2-2\alpha\beta)/(\alpha\beta)=((\alpha+\beta)^2)/(\alpha\beta)-2\n\n\alpha+\beta=(-b)/(a);\ \alpha\beta=(c)/(a)\n\n((\alpha+\beta)^2)/(\alpha\beta)-2=(\left((-b)/(a)\right)^2)/((c)/(a))-2=(b^2)/(a^2)\cdot(a)/(c)-2=(b^2)/(ac)-2$

$6x^2+x-2\n\na=6;\ b=1;\ c=-2\n\n(\alpha)/(\beta)+(\beta)/(\alpha)=(1^2)/(6\cdot(-2))-2=(1)/(-12)-2=-2(1)/(12)$

What is the standard form for 25x²+4y²+50x-24y-39=0

Answers

25x² + 4y² + 50x - 24y - 39 = 0
25x² + 50x + 4y² - 24y - 39 = 0
25x² + 50x - 39 = 0   4y² - 24y - 39 = 0
x = -b + √b² - 4ac y= -b + √b² - 4ac
      2a 2a
x = -50 + √(-50)² - 4(25)(-39)     y = -(-24) + √-(-24)² - 4(4)(-39)
   2(25) 2(4)
x = -50 + √2500 + 3900 y = 24 + √-576 + 624
   50 8
x = -50 + √6400 y = 24 + √48
      50    8
x = -50 + 80 y = 24 + √16 × 3
   50 8
x = -50 + 80 y = 24 + √16 √3
   50   8
x= -50 + 80    y = 24 + 4 √3
   50 8
x = -50 + 80                                        y = 24 + 4 √3
   50    8
x = -50 + 80   x = -50 - 80 y = 24 + 4 √3   y = 24 - 4 √3
      50 50 8     8
x = 30     x = -130     y = 28 √3     y = 20 √3
      50      50         8      8
x = 3     x = -13 y = 28 √3        y = 20 √3
      5     5    8     8
(x, y) = (3, 26 √3) (x, y) = (-13, 20 √3 )
        5    8 5 8

$25x^2+4y^2+50x-24y-39=0\n25x^2+50x+25+4y^2-24y+36-100=0\n(5x+5)^2+(2y-6)^2=100$