What usually happens to the host’s DNA during the lytic cycle?
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Related Questions
All living things are made up of two or more cells true or false
A particle with charge − 3.74 × 10 − 6 C is released at rest in a region of constant, uniform electric field. Assume that gravitational effects are negligible. At a time 8.36 s after it is released, the particle has a kinetic energy of 3.17 × 10 − 8 J. At what time t after the particle is released has it traveled through a potential difference of 0.401 V?
The approximate size of a galaxy can be measured by using the doppler effect. true or false.
a soap film is viewed in white light. if the film is much thinner than the wavelength of blue light, what is the appearance of the film?
B.no change occurs in the number of wavelengths that pass a given point per second
C.a greater number of wavelengths pass a given point per second
D.the number of wavelengths that pass a given point per second doubles
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1. Before dropping, all potential energy
2.dropping, potential energy transformed to kinetic energy
3. before hitting the ground, all Kinetic energy.
Recall the formula for both energy, which are U=mgh, and K=1/2mv^2
Since the energy is conserved in this case ( b/c otherwise it will say in the problem), the amount of energy at the beginning should equal to the energy at the end. Therefore we have, mgh=1/2mv^2
plug the number in and solve for velocity.
2x400x10=1/2 x 2 x v^2
v^2=8000
v=
v=40
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Answer;
B. Effective length of the tube.
Explanation;
- Most wind instruments are of either the open-open tube or the open closed tube type. Open ends of the tubes makes contact with the outside, atmospheric air.
- At an open end, when the air is disturbed in the wind instruments, the air vibrates with a variety of frequencies, however the frequencies that correspond to the natural frequencies will persist.
- Effective Length of the tube is responsible for determining the frequency of vibration of the air column in the pool with in a wind instrument.
The effective length of the tube is responsible for determining the frequency of vibration of the air column in the tube within a wind instrument.
b. planets
c. solar nebulae
d. planetesimals
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What did the protoplanets become?
a. nebulae
b. planets
c. solar nebulae
d. planetesimals
The protoplanets become nebulae. The answer is letter A. The rest of the choices do not answer the question above.
The answer is B. Planets
a. yes
b. no
Because the path difference is equal to the wavelength of the sound, the sound originating at the two speakers will interfere constructively at your location and you will perceive a louder sound.
Part B. What is the shortest distance d you need to walk forward to be at a point where you cannot hear the speakers? The forward direction is defined as being perpendicular to a line joining the two speakers and you start walking from the line that joins the two speakers.
Express your answers in meters to three significant figures.
d = m
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Final answer:
The sound will be louder when both loudspeakers are used compared to just one due to constructive interference. The shortest distance you need to walk forward to not hear the sound anymore is 0.250 m, calculated using the condition for destructive interference.
Explanation:
Yes, the sound you hear will be louder than if only one speaker were in use. Given that both the loudspeakers are emitting waves in phase and the path difference is equal to the wavelength, the waves will interfere constructively at your location, which will result in a louder sound. This is because when waves meet while they're in phase, they add together to produce a greater amplitude.
The shortest distance d you would need to walk forward to a point where you can't hear the speakers can be calculated using the path difference. From the condition for destructive interference, we know that the path difference should be an odd multiple of half the wavelength (λ/2). Hence the distance would be [(1/2)*λ] which equals [(1/2)*(speed of sound/frequency)]. So, d = [(1/2)*(344/688)] = 0.250 m after joining the values.
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Final answer:
Yes, the sound will be louder due to constructive interference. The shortest distance the student needs to walk forward to not hear the speakers is 0.25 m.
Explanation:
In this scenario, the student is standing equidistant from two loudspeakers that are emitting sound waves in phase at a frequency of 688 Hz. The speed of sound in air is 344 m/s. Part A of the question asks whether the sound that the student hears will be louder than if only one speaker was in use. The answer is yes. This is because the path difference between the two speakers is equal to the wavelength of the sound, resulting in constructive interference at the student's location.
Part B of the question asks for the shortest distance the student needs to walk forward to be at a point where they cannot hear the speakers. To determine this distance, we need to find the point where the path difference between the two speakers is equal to half a wavelength, resulting in destructive interference. The shortest distance the student needs to walk forward is equal to half the wavelength of the sound. Using the formula wavelength = speed of sound / frequency, we can find the wavelength and calculate the distance.
d = (344 m/s / 688 Hz) / 2 = 0.25 m
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c. rationing
b. a price floor
d. equilibrium
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♡♡Hope I helped!!! :)♡♡
Answer:
c. rationing
Explanation:
allow each person to have only a fixed amount of (a particular commodity).