What force is required to accelerate a body with a mass of 15 kilograms at a rate of 8 m/s²?

Answers

Answer 1

Answer: The equation for force is force is equal to mass times acceleration or F = ma where Force or F is measured in Newtons or N (which is also kilogram-meter per second squared), Mass or m is measured in kilograms or kg, and acceleration is measured in meters per second or m/s2. This leads to an answer in kilogram-meter per second squared or kg- m/s2, So if we multiply a body with a mass of 15 kilograms to a rate of 8 meters per second, we get 120 kilogram-meter per second squared.

Answer 2

Answer: it is simple 120 N is the answer

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A long solenoid has 1400 turns per meter of length, and it carries a current of 4.9 A. A small circular coil of wire is placed inside the solenoid with the normal to the coil oriented at an angle of 90.0˚ with respect to the axis of the solenoid. The coil consists of 42 turns, has an area of 1.2 × 10-3 m2, and carries a current of 0.45 A. Find the torque exerted on the coil.

Answers

Answer:

The torque on the coil is $1.955* 10^(- 4)\ N-m$

Solution:

No. of turns per meter length, n = 1400 turns\m

Current, I = 4.9 A

Angle, $\theta = 90.0^(\circ)$

No. of turns of coil, N = 42 turns

Area, A = $1.2* 10^(- 3)m^(2)$

Current in the coil, I' = 0.45 A

Now,

To calculate the exerted torque on the coil:

The magnetic field, B produced inside the coil is given by:

$B = n\mu_(o)I$

$B = 1400* 4\pi times 10^(- 7)* 4.9 = 8.62* 10^(- 3)\ T$

Now, the torque exerted is given by:

$\tau = I'NAB$

$\tau = 0.45* 42* 1.2* 10^(- 3)* 8.62* 10^(- 3) = 1.955* 10^(- 4)\ N-m$

Answer:

$T\approx 1.95* 10^(-4) N.m$

Explanation:

Given:

A long solenoid having

no. of turns per meter, n =1400

current, I = 4.9 A

A small coil of wire placed inside the solenoid

angle of orientation with respect to the axis of the solenoid, $\theta=90\degree$ °

no. of turns in the coil, N = 42

area of the coil, $a= 1.2* 10^(-3) m^2$

current in the coil, $i =0.45 A$

We have for torque:

$T=n.i.a.B. sin\theta$ .......................(1)

∵ $B=\mu_(0) .n.I$ ................................(2)

where:

B= magnetic field

$\mu_0=$ The permeability of free space = $4\pi*10^(-7) T.m.A^(-1)$

Substitute B from eq. (2) into eq. (1) we have:

$T=n.i.a.(\mu_0.N.I ).sin\theta$

putting the respective values in above eq.

$T=42* 0.45* 1.2* 10^(-3)* 4\pi*10^(-7) * 1400* 4.9* sin 90^(\circ)$

$T\approx 1.95* 10^(-4) N.m$

Compute the resistance in ohms of a copper block 5.0 cm long and 0.10 cm2 in cross-sectional area. (ρ = 1.77 × 10-6 ohm-cm)

Answers

R=ρ l/a
l=5 cm
a=0.10 cm²
ρ=1.77×10∧-6 Ωcm
R=(1.77×10∧-6) ×5/0.10
=8.85 ×10∧-5 Ω

resistance is directly proportional to length and inversly proportional to area of cross section is given by above equation

What type of electron is available to form bonds?

Answers

Answer:

Valence electrons

Explanation:

The valence electrons are found in the outermost shell of an atom. They are the most loosely held electrons found within an atom. These valence electrons are involved and are used to form bonds when atoms combines together.

The energy required to remove these loosely held electrons is relatively low compared to electrons located in the inner orbitals. This is why when atoms combines, they use the outermost electrons to form bonds and mimic stable atoms like those of the noble gases.

According to universal gravitation, both mass and air resistance affect the gravitational attraction between objects

Answers

Air resistance doesn't appear in the formula for gravitational force, because it doesn't affect it. Mass does because it does.

False, it would be only mass who does it.

IN a physics lab, a student discovers that the magnitude of the magnetic field at a certain distance from a long wire is 4.0μT. If the wire carries a current of 5.0 A, what is the distance of the magnetic field from the wire?

Answers

Answer:

0.25 m

Explanation:

The intensity of the magnetic field around a current-carrying wire is given by:

$B=(\mu_0 I)/(2 \pi r)$

where

$\mu_0 = 4\pi \cdot 10^(-7)Tm/A$ is the permeabilty of free space

I is the current

r is the distance from the wire

In this problem, we know:

$B=4 \mu T=4 \cdot 10^(-6) T$ is the magnetic field

$I=5.0 A$ is the current in the wire

Re-arranging the equation, we can find the distance of the field from the wire:

$r=(\mu_0 I)/(2 \pi B)=((4\pi \cdot 10^(-7))(5.0 A))/(2\pi(4\cdot 10^(-6) T))=0.25 m$

If a hypothesis states that children who consume a large quantity of sugar in the morning will perform more poorly in school than children who do not, then what will be the independent variable? A) children eating a healthy breakfast in the morning
B) children performing poorly in school
C) children performing well in school
D) children consuming a large quantity of sugar in the morning

Answers

the answer is letter a

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