What is 4 to the power of 0 equal to?

Answers

Answer 1
Answer: Any number to the power of zero is one.  Think of it like this - a power is basically multiplying a certain number of the same integer together.  So, if we multiply 0 fours together, we just get 1.  Alternatively, consider it like this - 4 to the power of one divided by four to the power of one is equal to four to the power of zero, so 4/4=1 is 4 to the power of zero.  Therefore, 4^0 is 1.
Answer 2
Answer: any number to the zero power is equal to 1

an exponent is how many times you multiply something by itself
remember that x^2=x^2 times 1
when you have x^0 then that means x^0 times 1 and then since there are no x's, the resulting value is just 1

the answer is 1

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Find point-slope.(3/2, -1/2)
(-2/3, 1/3)

x1: 3/2
x2: -2/3
y1: -1/2
y2: 1/3

to find slope:
m= y2-y1/x2-x1

point-slope:
y-y1=m(x-x1)

Answers

this iis easie guise, why don't you do it? so
point slope=y-y1=m(x-x1)

so just subsitute
first find m
m=(y2-y1)/(x2-x1)=(1/3-(-1/2))/(-2/3-3/2)=(1/3+1/2)/(-2/3-3/2)=(5/6)/(-13/6)=-5/13
m=-5/13
subsitute
y-y1=-5/13(x-x1)
subsitute
y-(-1/2)=-5/13(x-3/2)
y+1/2=-5/13x+15/26
subtract 1/2 from both sides
y=-5/13x+15/26-13/26 (1/2=13/26)
y=-5/13x+2/26
y=-5/13x+1/13

Answer:

Step-by-step explanation:

Sample Answer:When a linear function is expressed in different forms, its slope and y-intercept remain the same. The slope from the equation is -1, and the y-intercept from the equation is 3. The slope from the table is -1, and the y-intercept from the table is −3. These are not the same functions.

hope this helps.

When x = -3 on the graph of y = 2|x| + 3 what will be the y-coordinate?A. -3
B. 3
C. -9
D. 9

Answers

Substitute -3 into the equation

y = 2|x| + 3
y = 2 (3) + 3
y = 6 + 3
y = 9

Answer D

HELPPSKSKSJDJJSJSnsnsks

Answers

Answer:

The first and 3rd are functions, but the second and fourth are not functions.

Step-by-step explanation:

To see if something is a function, use the vertical line test. If there are multiple y coordinates for a singular point for x, it is not a function.

What is the multiplicative inverse of 6 + 2i?

Answers

The product of a number and it multiplicative inverse is 1. Let the multiplicative inverse of 6 + 2i be x. Then
x(6 + 2i) = 1
x = 1/(6 + 2i) = (6 - 2i)/(6 + 2i)(6 - 2i) = (6 - 2i)/(36 - 12i + 12i + 4) = (6 - 2i)/40
We have to multiply (6 + 2i) with its conjugate:
(6 + 2i) (6 - 2i) = 36-12i+12i-4i^2
As i^2= -1 . So , 
                        = 36+4
                        = 40
So 40 +is the correct answer.

The larger leg of a right triangle is 3cm longer than its smaller leg. The hypotenuse is 6cm longer than the smaller leg. how many centimeters long is the smaller leg  please explain how you got it 

Answers

b=a+3\n c=a+6\n a^2+b^2=c^2\n\n a^2+(a+3)^2=(a+6)^2\n a^2+a^2+6a+9=a^2+12a+36\n a^2-6a-27=0\n a^2-9a+3a-27=0\n a(a-9)+3(a-9)=0\n (a+3)(a-9)=0\n a=-3 \vee a=9\n

The length can't be negative, so the answer is 9 cm.
Let the smaller leg be x.

Thus, larger leg = 3 +x
Thus, hypotenuse = 6 + x

Applying pythagoras theorum ;

(6+x)^2 = x^2 + (3+x)^2 \n \n or, 6^2 + 12x + x^2 = 3^2 + 6x + x^2 \n \n i.e., 36 + 12x = 9 + 6x \n \n =>6x = 45 \n \n => x = 9

Thus, the length of smaller peg is 9 cm.

(c) Express the diagonal of a rectangle, D, in terms of its width, w, if the area of the rectangle is 13 square feet. D(w) =

Answers

we are asked to express the diagonal of a rectangle in terms of the width in which the area of the polygon is equal to 13 square feet. The area of teh rectangle is equal to length times width. That is 13 = lw; diagonal using pythagorean theorem is sqrt ( l2 + w2). Thus d =  sqrt ( (13/w)2 + w2) = sqrt ( (169/w2 + w2) = sqrt ( (169 + w4)/w2) = 1/w  sqrt (169 + w4)

Answer:

Hence, the diagonal of rectangle in terms of width(w) is:

D(w)=(√(169+w^4))/(w)

Step-by-step explanation:

Let the length of the rectangle=l

and width of the rectangle is:w.

We know that the diagonal D of the rectangle is given by with the help of the Pythagorean theorem as:

D=√(l^2+w^2)-------(1)

Also the area of rectangle(A) is given as:

A=l* w

Area of rectangle=13=l×w.

l=(13)/(w)

Hence putting the value of l in equation (1) we get:

D=\sqrt{((13)/(w))^2+w^2}=\sqrt{(13^2)/(w^2)+w^2}\n\nD=\sqrt{(169)/(w^2)+w^2}=\sqrt{(169+w^4)/(w^2)}=(√(169+w^4))/(w)

Hence, the diagonal of rectangle in terms of width(w) is:

D(w)=(√(169+w^4))/(w)