A runner achieves a velocity of 11.1 m/s 9 seconds after he begins. What is his acceleration? What distance did he cover?
Answers
Therefore:
As the runner was travelling for 9 seconds, he covered a distance of 99.9 metres. 9 seconds x 9 seconds = 81 seconds squared, and the runner covers roughly 1.23 metres in distance every second squared.
Explanation:
Acceleration=
Time
FinalVelocity−InitialVelocity
Therefore:
\begin{gathered}Acceleration=\frac { 11.1\quad m/s\quad -\quad 0\quad m/s }{ 9\quad seconds } \\ \\ =\frac { 11.1\quad m/s }{ 9\quad seconds } \\ \\ =1.23\quad m/{ s }^{ 2 }\quad (2\quad decimal\quad places)\end{gathered}
Acceleration=
9seconds
11.1m/s−0m/s
=
9seconds
11.1m/s
=1.23m/s
2
(2decimalplaces)
As the runner was travelling for 9 seconds, he covered a distance of 99.9 metres. 9 seconds x 9 seconds = 81 seconds squared, and the runner covers roughly 1.23 metres in distance every second squared.
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Answers
Answer:
14,400 meters
Explanation:
yes
Answers
Answer:
Explanation:
If P₁(p) be the partial pressure of gas in first bulb then
P₁(p) (1 +1.5) = P₁V₁ = 1 X 0.75
P₁(p) = (1 / 2.5) x .75 = 0.3 atm
Similarly partial pressure of gas in second bulb
= ( 1.5 / 2.5) x 1.2 = .72 atm
Total pressure= .3 + .72 = 1.02 atms.
If n₁ and n₂ be their moles in the respective bulbs
P₁V₁ = n₁ R t
P₂ V₂ = n₂ R t
mole fraction of argon =
=
= 15 / 51
Mole fraction of helium = 1 - 15 / 51 = 36 / 51
Answer:
The total pressure of the mixture is 1.02 atm.
Partial pressure of the argon :
Partial pressure of the helium :
Explanation:
Volume of argon in the bulb = = 1.00 L
Pressure of argon in the bulb = = 0.75 atm
Temperature of the both the gases = T
Moles of argon gases =
..[1]
Volume of helium in the bulb = = 1.50 L
Pressure of helium in the bulb = = 1.20 atm
Moles of helium gases =
..[2]
[1] ÷ [2]
After opening the stopcock, the gases are mixed.
The mole fraction of argon =
The mole fraction of helium=
Volume of the mixture ,V= 1.00 L + 1.50 L =2.50 L
Total pressure in the mixture = P
Temperature is same = T
Total moles of gases in the mixtures = n
The total pressure of the mixture is 1.02 atm.
Partial pressure of the argon after mixing :
Partial pressure of the helium after mixing :
Answers
Answer:
How are we expected to make an island
Answers
average volume= volume per atom.
density*mass per atom = volume per atom
1cm^3 / 7.87 gram * 9.27 *10^-26 kg /atom* 1000 gram / kg=
=1.178 * 10^-22 cm^3 per atom
Convert that to mass
1 cm^3 * (1 m / 100 cm)^3
average volume= 1.178 *10^-29 m^3 per atom
distance:
Volume of a cube is L^3
so L = (1.178*10^-29)^(1/3)
Half way through the cube is distance 1/2 L.
Second cube is 1/2 L
So distance between the center of 2 cubes = L
=2.28 *10^-10 m