Determine the conversion factor between (a) km/h and mi/h, (b) m/s and ft/s, and (c) km/h and m/s.

Answers

Answer 1

Answer: (a) km/h and mi/h,
1 km/hr (km hr-1) = 0.278 m/s (m s-1) = 0.621mi/hr (mi hr-1) = 0.912 ft/s (ft s-1)
(b) m/s and ft/s,
Speed of sound in air at 0 oC (32 oF)= 331 m/s (m s-1) = 1090 ft/s (ft s-1) =41 mi/hr (mi hr-1)
(c) km/h and m/s. 1km/hr (km hr-1) = 0.278 m/s (m s-1)

Answer 2

Answer:

(a) 1 mi/h = 1.60934 km/h

(b) 1 ft/s = 0.3048 m/s

(c) 1 m/s = 3.6 km/h

Further explanation

Acceleration is rate of change of velocity.

$\large {\boxed {a = (v - u)/(t) } }$

$\large {\boxed {d = (v + u)/(2)~t } }$

a = acceleration ( m/s² )

v = final velocity ( m/s )

u = initial velocity ( m/s )

t = time taken ( s )

d = distance ( m )

Let us now tackle the problem !

$1 ~ foot = 30.48 ~ cm$

$1 ~ inch = 2.54 ~ cm$

$1 ~ foot = 12 ~ inches$

$1 ~ mile = 1609.34 ~ metres$

Question (a):

$1 ~ mi/h = (1 ~ miles)/(1 ~ hour)$

$1 ~ mi/h = (1.60934 ~ km)/(1 ~ hour)$

$\large {\boxed {1 ~ mi/h = 1.60934 ~ km/h} }$

Question (b):

$1 ~ ft/s = (1 ~ foot)/(1 ~ s)$

$1 ~ ft/s = (0.3048 ~ m)/(1 ~ s)$

$\large {\boxed {1 ~ ft/s = 0.3048 ~ m/s} }$

Question (c):

$1 ~ m/s = (1 ~ m)/(1 ~ s)$

$1 ~ m/s = (1/1000 ~ km)/(1/3600 ~ h)$

$1 ~ m/s = (3600)/(1000) ~ km/h$

$\large {\boxed {1 ~ m/s = 3.6 ~ km/h} }$

Learn more

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Kinetic Energy : brainly.com/question/692781
Acceleration : brainly.com/question/2283922
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Answer details

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate

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Answers

Which of the following materials is able to absorb large amounts of energy without changing temperature very much?

Answer: Out of all the options presented above the one that represents the material that is able to absorb large amounts of energy without changing temperature very much is answer choice C) Water.

I hope it helps, Regards.

Answer : The correct option is water.

Explanation :

Water has an ability to absorb large amount of energy without changing temperature very much.

This shows the specific heat of water is high. It is approximately equal to $4.186\ J/g\ ^0C$ .

The specific heat of air is $1.005\ J/g\ ^0C$ .

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Ksp for agbr is 5x10-13. what is the maximum concentration of silver ion that you can have in a 0.1 m solution of nabr?

Answers

Answer : The maximum concentration of silver ion is $5* 10^(-12)m$

Solution : Given,

$K_(sp)$ for AgBr = $5* 10^(-13)$

Concentration of NaBr solution = 0.1 m

The equilibrium reaction for NaBr solution is,

$NaBr(aq)\rightleftharpoons Na^++Br^-$

The concentration of NaBr solution is 0.1 m that means,

$[Na^+]=[Br^-]=0.1m$

The equilibrium reaction for AgBr is,

$AgBr\rightleftharpoons Ag^++Br^-$

At equilibrium s s

The expression for solubility product constant for AgBr is,

$K_(sp)=[Ag^+][Br^-]$

The concentration of $Ag^+$ = s

The concentration of $Br^-$ = 0.1 + s

Now put all the given values in $K_(sp)$ expression, we get

$5* 10^(-13)=(s)(0.1+s)$

By rearranging the terms, we get the value of 's'

$s=5* 10^(-12)m$

Therefore, the maximum concentration of silver ion is $5* 10^(-12)m$ .

[Br⁻¹] = [NaBr] = 0.1

Ksp = [Ag⁺] x [Br⁻]
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State 2 applications of convection in daily life

Answers

Final answer:

Convection is a process that helps distribute heat, notably in daily applications such as heating systems and cooking. It involves the movement of heat through fluids, where hotter parts become less dense and rise, creating a current.

Explanation:

Convection is a significant process in our daily lives that enables the transfer of heat in fluids (liquids and gases) from one place to another.

One common application of convection is seen in Heating Systems. For instance, in a radiator, hot water or steam travels through the system, heats the surrounding air, and this hot air rises, creating a convection current that distributes the warmth throughout a room.

Another prime example of convection at work is Cooking. When you boil water or cook in a pot, the heat from the stove heats up the pot which then heats the water at the bottom. This hot water rises, pushing the cooler water to the bottom where it too gets heated, thus creating a convection current.

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If the volume of a gas is 2.0 L and itspressure is 5 atm what will the new
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Answers

Answer:

The answer is 1.05 atm

Explanation:

The new volume can be found by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

Since we are finding the new volume

$V_2 = (P_1V_1)/(P_2) \n$

From the question we have

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We have the final answer as

1.05 atm

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